CBSE Sample Papers for Class 10 Computer Applications Set 1 with Solutions

Students can access the CBSE Sample Papers for Class 10 Computer Applications with Solutions and marking scheme Set 1 will help students in understanding the difficulty level of the exam.

CBSE Sample Papers for Class 10 Computer Applications Set 1 with Solutions

Time: 3 Hours
Maximum Marks: 50

General Instructions

  1. This question paper contains two parts A and B. Each part is compulsory.
  2. Part A carries 20 marks while Part B carries 30 marks.
  3. Part A consists very short answer and case based MCQ Questions and Part B is Descriptive Paper.
  4. Both Part A and Part B have choices.

Part-A

  1. It consists two sections-1 and II.
  2. Section I has 13 questions of Very Short Answer Type. An examinee is to attempt any 10 out of 13 questions.
  3. Section II has two Case Studies. Each Case Study has 7 case-based sub-parts. An examinee is to attempt any
    5 out of 7 sub-parts.

Part-B

  1. Question numbers 16 to 20 are Short Answer Type (SA-I) Questions of 2 marks each, Question numbers
    21 to 25 are Short Answer Type (SA-II) questions of 3 marks each and Question numbers 26 is Long Answer \ Type Question of 5 marks.
  2. Internal choice is provided in 1 question of 2 marks, 1 question of 3 marks and 1 question of 5 marks.

Part-A
Section 1

This section consists of 13 questions of very short answer type. Question numbers 4 to 8 are of “fill in the blank’ type. Fill the blank with the most appropriate answer. Attempt any 10 questions from Question numbers 1 to 13.

Question 1.
Expand the term SMTP.
Answer:
Simple Mail Transfer Protocol

Question 2.
What do you understand by blog?
Answer:
A blog is a website or web page, in which an individual records opinion links to other sites on regular basis.

You are advised to attempt this sample paper without referring the answers given here. However, cross check your answers once you complete the paper.
Question 3.
Nisha wrote the following HTML statement:
<IMG src=”school.jpg”>
She did not use closing tag of IMG and told her friend that IMG is empty element. What is an empty element?
Answer:
Empty elements are standalone tags, i.e. empty tags do not have to be wrapped around text or graphics and do not require a closing tag.

Question 4.
______ and ______ tags break the line flow.
Answer:
<BR>, <HR>

Question 5.
______ is used to change the color of a visited link.
Answer:
vlink

Question 6.
______ are used to connect web pages. They are created with <A> tag.
Answer:
Hyperlinks

Question 7.
<TH> tag is used to specify the column ______ in a table.
Answer:
heading

Question 8.
______ attribute of <AUDIO> tag specifies the audio file standard type.
Answer:
type

Question 9.
Neha wants to transfer multimedia documents through Internet. Her friend told her that some type of protocol is used to transfer documents through Internet. But she is confused about its name. Which protocol help her to transfer the documents through Internet?
Answer:
The name of this protocol is HTTP (HyperText Transfer Protocol).

Question 10.
How does gender contribute to the digital divide?
Answer:
Gender is stated that in some countries and organisations, females have less access to the Internet than males.

Question 11.
Which services are provided by CPA WebTrust in E-commerce?
Answer:
In E-commerce, CPA WebTrust provides services titled WebTrust and SysTrust.

Question 12.
Which attribute of <BODY> tag specifies the color of visited links in a document?
Answer:
vlink attribute

Question 13.
Write the syntax of <INPUT> tag.
Answer:
<INPUT type = “fieldtype” name = “fieldname” value = ”fieldtext”>

Section II

Both the case study based questions are compulsory. Attempt any 5 questions (out of 7 questions) from each case study. Each question carries 1 mark.

Question 14.
URL
Web is a collection of documents (web pages) stored on computers around the world. Each web page has an address describing where it can be found. This address is known as web address or URL. A web address identifies the location of a specific web page on the Internet, such as
http://www.leamyoga.com
Every computer connected to the Internet has its unique web address, without which it cannot be reached by other computers.
(i) Which of the following is used by the browser to connect to the location of the Internet resources?
(a) Linkers
(b) Protocol
(c) Cable
(d) URL
Answer:
(d) URL

(ii) An absolute contains the complete address of a file on the Internet.
(a) JavaScript
(b) URL
(c) SQL
(d) String
Answer:
(b) URL

(iii) The full form of URL is
(a) Uniform Resource Locator
(b) Universal Resource Locator
(c) Universally Resource Locator
(d) Uniform Reference Locator
Answer:
(a) Uniform Resource Locator

(iv) Which of the following must be contained in a URL?
(a) A protocol identifier
(b) The letters, www
(c) The unique registered domain name
(d) A protocol identifier, www and the unique registered domain name
Answer:
A protocol identifier, www and the unique registered domain name

(v) What is URL?
(a) A computer software program
(b) A type of programming object
(c) The address of a document or page on the www
(d) A piece of hardware
Answer:
(c) The address of a document or page on the www

(vi) The types of URL is
(a) absolute
(b) relative
(c) Both (a) and (b)
(d) mixed
Answer:
(c) Both (a) and (b)

(vii) It points to a file/directory in relation to the present file/directory.
(a) Absolute URL
(b) Relative URL
(c) Either (a) or (b)
(d) None of these
Answer:
Relative URL

Question 15.
Embed Audio Element
The HTML <AUDIO> element is used to embed sound content in documents. It may contain one or more audio sources, represented using the src attribute. The <AUDIO > element defines an in-browser audio player. The audio player can provide a single piece of audio content. To specify the source file of the audio content, use one or more <SOURCE> elements inside the <AUDIO> element. All <SOURCE> files should contain the same audio content, but in different file formats. The browser will select the first file format that it is able to play. If you are not going to provide multiple source file formats, you may indicate the source file in the src attribute, instead of in a separate <SOURCE> element.
(i) <AUDIO> tag is used in (1)
(a) < HTML > tag
(b) <BODY> tag
(c) < HEAD > tag
(d) <TITLE> tag
Answer:
<BODY> tag

(ii) Which of the following attributes of <AUDIO> tag?
(a) autoplay
(b) src
(c) type
(d) All of these
Answer:
(d) All of these

(iii) What is the attribute of <SOURCE> tag?
(a) src
(b) type
(c) Both (a) and (b)
(d) height
Answer:
Both (a) and (b)

(iv) This attribute specifies the location of the audio file.
(a) loop
(b) src
(c) type
(d) controls
Answer:
(b) src

(v) Most commonly used audio format(s) is/are (1)
(a) ogg
(b) mp3
(c) wav
(d) All of these
Answer:
All of these

(vi) What is the full form of src? (1)
(a) Source
(b) Service
(c) Support Cast
(d) Specify Resource
Answer:
(a) Source

(vii) Which attribute of < AUDIO > tag allows audio automatically see back to the start after reaching at the end?
(a) src
(b) autobuffer
(c) loop
(d) autoplay
Answer:
(c) loop

Part-B

All questions are compulsory. In case of internal choices, attempt any one.

Question 16.
Below are given names of some websites : (2)
(i) www.google.co.in
(ii) www.microsoft.com
Identify the components of all the web addresses given above.
Answer:
(i) www.google.co.in
Host name – www
Domain name – google.co.in
Domain type – co.in

(ii) www.miqrosoft.com
Host name – www
Domain name – microsoft.com
Domain type – com

Question 17.
Explain the two elements which with search engine works. (2)
Answer:
Search engine works with two elements, which are as follows:
(i) Web Crawler It is a software that browses the Internet in a systematic manner. It retrieves the information, which follows every link on the site that are stored by Web search engines. It is also known as spider, ant, automatic indexer or Web scutter.

(ii) Indexing Software It is a software that receives the list of Web documents and addresses collected by Web crawler. Some search engines provide proximity search which allows users to define the distance keywords.

Question 18.
Explain the open source software movement. (2)
Answer:
The open source software movement is a movement that supports the use of open source licenses for some softwares. It was started to spread the concept of open source software. Thus, open source software is a software whose source code is available for modification or enhancement by anyone. Programmers develop the open source movement contribute to the open source community by writing and exchanging programming code for software development.

Question 19.
Give any six reasons behind plagiarism. (2)
Answer:
The reason behind plagiarism are

  1. Fear of failure (ii) Not having enough knowledge
  2. Being lazy (iv) Lack of enforcement (v) Competition (vi) Lack of management skills

Question 20.
6CO2 +6H2O → C6H12O2 +6O2         (2)
To display above given chemical expression on a web page, following HTML code was written:
6CO<SUP>2</SUP> + 6H<SUP>2</SUP>0 —> C<SUP> 6</SUP> H<SUP>
12 </SUP > O < SUP > 6 </SUP >+ 60 < SUP > 2 </SUP >
But it is not displaying the expression in desired format. Identify the fault(s) and suggest the required correction(s).
Or
Write a simple HTML code to show an example of internal linking.(2)
Answer:
<SUP>tag will not be use in the given expression because it is a superscript tag. In this
expression, subscript tag, i.e. <SUB> tag will be use. ‘
Or
<HTML>
<HEAD><TITLE>Internal Li nki ng</TITLE>
</HEAD>
<BODY>
<H1> It is <A name =”top”>top</A> of the page </H1>
<BR><BR><BR><BR><BR><BR><BR><BR><BR>
<BR>
<BR><BR><BR><BR><BR><BR><BR><BR><BR>
<BR>
<BR><BR><BR>
<H1><A href =”#top”>Top</A></H1>
</BODY>
</HTML>

Question 21.
Write the HTML code to create the exact table which is given below : (3)

Roll_NoNameClassSubject
1NehaVthMaths
2Amit10thEnglish
3SnehaIIIrdG.K.

Answer:
<HTML>
<BODY>
<TABLE border = “2”>
<TR align = “center” valign = “middle”>
<TH> Roll_N0 </TH>
<TH> Name </TH>
<TH> Class </TH>
<TH> Subject </TH>
</TR>
<TR align = “center” valign = “middle”>
<TD> 1 </TD>
<TD> Neha </TD>
<TD> Vth </TD>
<TD> Maths </TD>
</TR>
<TR align = “center” valign = “middle”>
<TD> 2 </TD>
<TD> Amit </TD>
<TD> 10th </TD>
<TD> English </TD>
</TR>
<TR align = “center” valign = “middle”>
<TD> 3 </TD>
<TD> Sneha </TD>
<TD> IIIrd </TD>
<TD> G.K. </TD>
</TR>
</TABLE>
< / BODY >
</HTML>

Question 22.
Define the cascading style sheet.
Answer:
Cascading Style Sheet (CSS) is a style sheet language used for describing the presentation of a document written in a markup language. CSS is designed primarily to enable the separation of document content from document presentation, including aspects such as the layout, colors and fonts.

This separation can improve content accessibility, provide more flexibility and control in the specification of presentation characteristics, enable multiple HTML pages to share formatting by specifying the relevant CSS in a separate .css file, and reduce complexity and repetition in the structural content such as semantically insignificance tables that were widely used to format pages before consistent CSS rendering was available in all major browsers.

CSS makes it possible to separate presentation instructions from the HTML content in a separate file or style section of the HTML file. For each matching HTML element, it provides a list of formatting instructions.

Question 23.
Write about the Freedom of Information Act (FOIA). (3)
Answer:
FOIA (Freedom of Information Act) is a federal law that generally provides that any person has a right to obtain access to federal agency records. It is intended to increase transparency. It does not provide access to all government documents.The FOI Act provides that every person has the following legal rights:

  1. The right to access official records held by government departments as defined by the act.
  2. The right to be given reasons for decisions taken by government that affect them.

Question 24.
Give advantages and disadvantages of secure electronic transaction. (3)
Answer:
Advantages of SET (Secure Electronic Transaction) are as follows:

  1. SET prevents merchants from seeing the customer payment information.
  2. To ensure merchant privacy, SET prevents the payment gateway from seeing the order information.

Disadvantages of SET are as follows:

  1. The customer must install additional software, which can handle SET transactions.
  2. Implementing SET is more costly than SSL for merchants as well.
  3. Users must have credit card.

Question 25.
What is web server? Explain any one web server. (3)
Or
What do you mean by hypertext markup language.
Answer:
Web server is a computer program that serves requested HTML pages or files from the Web client. Every Web server that is connected to the Internet is associated with a unique address, i.e. IP address. Web server software generally requires a fairly robust operating system like Unix, Windows NT. Every Website need to be stored on a computer called the Web server from which it can be accessed.
Currently, there are five major Web servers commonly used for hosting Websites as follows:
(i) Apache HTTP Server
(ii) Internet Information Server
(iii) Lighttpd
(iv) Sun Java System Web Server
(v) Jigsaw Server

Apache HTTP Server was developed by Apache Software Foundation. It is the most popular Web hosting server in the world. This software can be installed virtually on all operating systems including Windows, Linux, Mac OS X, UNIX etc. At present, 60% of server machines run on the Apache Web server.
Or
HyperText Markup Language (HTML) is a markup language used for designing Web pages. A markup language is a set of markup (angular bracket, < >) tags, which tell the Web browser, how to display a Web page’s words and images for the user. Each individual markup code is referred to as an element or a tag. The text placed between a pair of angular brackets (< >) defines an HTML element.

HTML elements have two basic properties, i.e. attributes and content. Attributes are used to apply the desired style on the text and content refers to the text that you want to display on the browser. When a Web page is opened in a Web browser, then the formatted content is displayed.

Question 26.
Write the code to generate the following web page: (5)
CBSE Sample Papers for Class 10 Computer Applications set 1 with Solutions 26
Note The following points while generating the web page:
(i) Title of the page is “Indian Food”.
(ii) Link color is blue, vlink color is brown and alink color is pink.
(iii) Font face of heading is “arial”.
(iv) The color of the heading of the page is green.
(v) Image used as foodl.jpg.
(vi) Table border is 4px and border color is maroon.
(vii) Use link as:
For Available Food as Fl.html
For Dishes Price as F2.html
For Get Recipes as F3.html
(viii) E-mail id for bottom message “To get order click here” as [email protected].
Or
Answer the following:
(i) Write the HTML code to create a link for school.jpg located at C:\.
(ii) Name the attribute used for setting cell width.
(iii) Name the attribute used for changing the cell span.
(iv) What is the use of dir attribute of <HTML> tag?
(v) Name any two attributes you can use with <TABLE> tag but not with <TR> tag.
Answer:
<HTML>
<HEAD><TITLE> Indian Food </TITLE></HEAD>
<BODY link=”blue” vlink=”brown” alink=”pink” bgcolor=”orange”>
<FONT face=”arial” color=”green”>
<H1 align=”center”><U> Indian Food </U></H1>
</FONT>
The traditional food of India has been widely appreciated for its fabulous use of herbs and spices. Indian cuisine is known for its large assortment of dishes. The cooking style varies from region to region and is largely divided into South Indian & North Indian cuisine. India is quite famous for its diverse multi cuisine available in a large number of restaurants and hotel resorts, which is reminiscent of unity in diversity. <BR>
<P align=”right”><A href=”Fl.html ”> Available Food </A><BR>
<A href=”F2.html “> Dishes Price </A><BR>
<A href=”F3.html “> Get Receipes </A></P>
<IMG src=”foodl.jpg” align=”right” width =”180” height=”150”>
<TABLE border=”4” borderedor=”maroon” cel 1padding=”6″ align=”center”>
<CAPTION> Select Dishes </CAPTION>
<TR>
<TH> STATE </TH>
<TD> Gujrat </TD>
<TD> Punjab </TD>
<TD> Tamil Nadu </TD>
</TR>
<TR>
<TH> DISHES </TH>
<TD> Khandvi <BR> Dhokla <BR> Dal Vada </TD>
<TD> Falooda <BR> Nan <BR> Lassi </TD>
<TD> Masala Dosa <BR> Sambhar Idli <BR> Upma </TD>
</TR>
</TABLE>
<BR>
<A href=”[email protected]”> To get order click here </A>
</BODY>
</HTML>
Or
(i) <A href = “C: \school . jpg”> IMAGE</A>
(ii) width
(iii) rowspan and colspan
(iv) dir attribute tells the browser, the direction in which the displayed text is to be read.
(v) summary, rules

Selina Concise Mathematics Class 10 ICSE Solutions 2020-21

Selina Concise Mathematics Class 10 ICSE Solutions 2020-21 Edition

Learninsta.com provides step by step solutions for Selina Concise ICSE Solutions for Class 10 Mathematics. You can download the Selina Concise Mathematics ICSE Solutions for Class 10 with Free PDF download option. Selina Publishers Books of Concise Mathematics for Class 10 ICSE Solutions all questions are solved and explained by expert mathematic teachers as per ICSE board guidelines. By studying these Selina ICSE Solutions for Class 10 Maths you can easily get good marks in ICSE Class 10 Board Examinations.

Selina Concise Mathematics Class 10 ICSE Solutions Chapter 3 Shares and Dividend Ex 3A

Selina Concise Mathematics Class 10 ICSE Solutions Chapter 3 Shares and Dividend Ex 3A

These Solutions are part of Selina Concise Mathematics Class 10 ICSE Solutions. Here we have given Selina Concise Mathematics Class 10 ICSE Solutions Chapter 3 Shares and Dividend Ex 3A.

Other Exercises

Question 1.
How much money will be required to buy 400, ₹ 12.50 shares at a premium of ₹ 1?
Solution:
Number of shares purchased = 400
Rate of each share = ₹ 12.50
M.V. = ₹ 1 premium = ₹ 12.50 + ₹ 1 = ₹ 13.50
Amount of in vestment = ₹ 400 x ₹ 13.50 = ₹ 5400

Question 2.
How much money will be required to buy 250, ₹ 15 shares at a discount of ₹ 1.50?
Solution:
Number of shares = 250
M.V. = at ₹ 15 at a discount of ₹ 1.50 = ₹ 15 – ₹ 1.50 = ₹ 13.50
Amount of investment = ₹ 13.50 x 250 = ₹ 3375

Question 3.
A person buys 120 shares at a nominal value of ₹ 40 each, which he sells at ₹ 42.50 each. Find his profit and profit percent.
Solution:
No. of shares = 120
Nominal value of each share = ₹ 40.00
Profit at each share = ₹ 42.50 – ₹ 40.00 = ₹ 2.50
Total profit = 2.50 x 120 = ₹ 300
Cost price of 120 shares = ₹ 40 x 120 = ₹ 4,800
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 3 Shares and Dividend Ex 3A 3.1

Question 4.
Find the cost of 85 shares of Rs. 60 each when quoted at ₹ 63.25
Solution:
No. of shares = 85
Market value of cach share = ₹ 63.25
Total cost = ₹ 63.25 x 85 = ₹ 5,376.25

Question 5.
A man invests ₹ 800 in buying 75 shares and when they are selling at a premium of ₹ 1.15, he sells all the shares. Find his profit and profit percent.
Solution:
Investment = ₹ 800
In first case face value of each share = ₹ 5
and market value of each share = ₹ 5.00 + ₹ 1.15 = ₹ 6.15
Gain on each share of ₹ 5 = ₹ 1.15
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 3 Shares and Dividend Ex 3A 5.1

Question 6.
Find the annual income derived from 125, ₹ 120 shares paying 5% dividend.
Solution:
Amount of investment = ?
Number of shares purchased = 125 at ₹ 120, 5% dividend
Amount of investment = ₹ 125 x 120 = ₹ 15000
His annual income = 15000 x \(\frac { 5 }{ 100 }\) = ₹ 750

Question 7.
A man invests ₹ 3,072 in a company paying 5% per annum when its ₹ 10 share can be bought for ₹ 16 each. Find:
(i) his annual income;
(ii) his percentage income on his investment.
Solution:
Total investment = ₹ 3,072
Market value of each shares = ₹ 16
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 3 Shares and Dividend Ex 3A 7.1

Question 8.
A man invests ₹ 7,770 in a company paying 5 percent dividend when a share of nominal value of ₹ 100 sells at a premium of ₹ 5. Find :
(i) the number of shares bought;
(ii) annual income ;
(iii) percentage income ;
Solution:
Investment = ₹ 7770
Nominal value of each share = 100
Market value = 100 + 5 = 105
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 3 Shares and Dividend Ex 3A 8.1

Question 9.
A man buys ₹ 50 shares of a company paying 12 percent dividend, at a premium of ₹ 10. Find :
(i) the market value of 320 shares ;
(ii) his annual income ;
(iii) his profit percent.
Solution:
(i) Market value of each share = ₹ 50 + ₹ 10 = ₹ 60
Market value of 320 shares = ₹ 60 x 320 = ₹ 19,200
(ii) Rate of dividend = 12%
Face value of 320 shares = Rs. 50 x 320 = Rs. 16,000
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 3 Shares and Dividend Ex 3A 9.1

Question 10.
A man buys of Rs. 75 shares at a discount of Rs. 15 of a company paying 20% dividend. Find :
(i) the market value of 120 shares ;
(ii) his annual income ;
(iii) his profit percent.
Solution:
(i) Market value of one share = Rs. 75 – 15 = Rs. 60
Market value of 120 shares = Rs. 60 x 120 = Rs. 7,200
(ii) Rate of dividend = 20%
Face value of 120 shares = Rs. 75 x 120 = Rs. 9,000
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 3 Shares and Dividend Ex 3A 10.1

Question 11.
A man has 300, ₹ 50 shares of a company paying 20% dividend. Find his net income after paying 3% income tax.
Solution:
No. of shares = 300
Face value of 50 shares = Rs. 50 x 300 = Rs. 15,000
Rate of dividend = 20%
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 3 Shares and Dividend Ex 3A 11.1

Question 12.
A company pays dividend of 15 % on its ten-rupee shares from which it deducts income tax at the rate of 22%. Find the annual income of a man who owns one thousand shares of this company.
Solution:
No. of shares = 1,000
Face Value of each share = Rs. 10
Rate of dividend = 15%
Rate of income tax = 22%
Face value of 1,000 shares = 1,000 x 10 = Rs. 10,000
Total dividend = Rs. 10,000 x \(\frac { 15 }{ 100 }\) = Rs. 1,500
Income tax deducted = Rs. 1500 x \(\frac { 22 }{ 100 }\) = Rs. 330
Net income = Rs.1500 – Rs. 330 = Rs. 1170

Question 13.
A man invests Rs. 8,800 in buying shares of a company of face value of rupees hundred each at a premium of 10%. If he earns Rs. 1,200 at the end of the year as dividend find:
(i) the number of shares he has in the company;
(ii) the dividend percent per share. [2001]
Solution:
Investment = Rs. 8,800
Face value of each share = Rs. 100
Market value of each share = Rs. 100 + 10 = Rs. 110
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 3 Shares and Dividend Ex 3A 13.1

Question 14.
A man invests Rs. 1,680 in buying shares of nominal value Rs. 24 and selling at 12% premium. The dividend on the shares is 15% per annum. Calculate :
(i) The number of shares he buys ;
(ii) The dividend he receives annually. [1999]
Solution:
Investment = Rs. 1680
Nominal value of each share = Rs. 24
Market value of each share = Rs. 24 + 12% of 24
= Rs. 24 + 2.88 = Rs. 26.88
Rate of dividend = 15%
(i) No. of shares = \(\frac { 1680 }{ 26.88 }\) = 62.5
(ii) Face value of 62.5 shares = 62.5 x 24 = Rs. 1500
Amount of dividend = 1500 x \(\frac { 15 }{ 100 }\) = Rs. 225

Question 15.
By investing Rs. 7,500 in a company paying 10 percent dividend, an annual income of Rs. 500 is received. What price is paid for each of Rs. 100 share? [1990]
Solution:
Investment = Rs. 7,500
Rate of dividend = 10%
Total income = Rs. 500
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 3 Shares and Dividend Ex 3A 15.1

Hope given Selina Concise Mathematics Class 10 ICSE Solutions Chapter 3 Shares and Dividend Ex 3A are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2B

Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking (Recurring Deposit Accounts) Ex 2B

These Solutions are part of Selina Concise Mathematics Class 10 ICSE Solutions. Here we have given Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2B.

Other Exercises

Question 1.
Pramod deposits ₹ 600 per month in a Recurring Deposit Account for 4 years. If the rate of interest is 8% per year; calculate the maturity value of his account.
Solution:
Deposit per month (P) = ₹ 600
Rate of interest (r) = 8%
Period (n) = 4 years = 48 months.
According to formula,
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2B 1.1
Maturity value = ₹ 600 x 48 + ₹ 4,704 = ₹ 28,800 + ₹ 4,704 = ₹ 33504

Question 2.
Ritu has a Recurring Deposit Account in a bank and deposits ₹ 80 per month for 18 months. Find the rate of interest paid by the bank if the maturity value of this account is ₹ 1,554.
Solution:
Let rate of interest = r%,
n = 18,
P = ₹ 80
and A is maturity value.
Using formula
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2B 2.1

Question 3.
The maturity value of a R.D. Account is ₹ 16,176. If the monthly installment is ₹ 400 and the rate of interest is 8%; find the time (period) of this R.D. Account.
Solution:
Here maturity value (A) = ₹ 16,176
Rate = 8%,
P = ₹ 400
Let period = n (No. of months)
Using formula :
I = A – P x n = 16,176 – 400 x n = 16,716 – 400n.
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2B 3.1
⇒ 48,528 – 1,200n = 4n² + 4n
⇒ 4n² + 4n + 1200n – 48,528 = 0
⇒ 4n² + 1,204n – 48,528 = 0
⇒ n² + 301n — 12,132 = 0 (dividing by 4)
⇒ n² – 36n + 337n – 12,132 = 0
⇒ n (n – 36) + 337 (n – 36) = 0
⇒ (n – 36) (n + 337) = 0
Either n = 36 months or n = -337, which is not possible.
Time = 36 months = 3 years

Question 4.
Mr. Bajaj needs ₹ 30,000 after 2 years. What least money (in multiple of ₹ 5) must he deposit every month in a recurring deposit account to get required money at the end of 2 years, the rate of interest being 8% p.a. ?
Solution:
Amount of maturity = ₹ 30000
Period (n) = 2 years = 24 months
Rate = 8% p.a.
Let x be the monthly deposit
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2B 4.1
Amount of monthly deposit in the multiple of ₹ 5 = ₹ 1155

Question 5.
Rishabh has a recurring deposit account in a post office for 3 years at 8% p.a. simple interest. If he gets ₹ 9,990 as interest at the time of maturity, find :
(i) the monthly installment.
(ii) the amount of maturity.
Solution:
Total interest = ₹ 9990
Period (n) = 3 years = 36 months
Rate of interest (r) = 8%
(i) Let monthly installment = x
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2B 5.1
Monthly installment = ₹ 2250
(ii) Amount of maturity = Principal + Interest
= 36 x 2250 + 9990
= ₹ 81000 + 9990 = ₹ 90990

Question 6.
Gopal has a cumulative deposit account and deposits ₹ 900 per month for a period of 4 years. If he gets ₹ 52,020 at the time of maturity, find the rate of interest.
Solution:
Maturity value = ₹ 52,020
Monthly installment (P) = ₹ 900
Total principal = ₹ 900 x 48 = ₹ 43200
Amount of interest = ₹ 52020 – ₹ 43200 = ₹ 8820
Let rate of interest = r%
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2B 6.1

Question 7.
Deepa has a 4 year recurring deposit account in a bank and deposits ₹ 1,800 per month. If she gets ₹ 1,800 per month. If she gets ₹ 1,08,450 at the time of maturity, find the rate of interest.
Solution:
Deposit per month = ₹ 1800
Period = 4 years = 48 months
Maturity value = ₹ 108450
Total principal = ₹ 1800 x 48 = ₹ 86400
Amount of interest = ₹ 108450 – 86400 = ₹ 22050
Let r be the rate of interest
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2B 7.1

Question 8.
Mr. Britto deposits a certain sum of money each month in a Recurring Deposit Account of a bank. If the rate of interest is of 8% per annum and Mr. Britto gets ₹ 8,088 from the bank after 3 years, find the value of his monthly installment. (2013)
Solution:
Let monthly installment = ₹ x
Period (n) = 3 x 12 months = 36 months
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2B 8.1

Question 9.
Sharukh opened a Recurring Deposit Account in a bank and deposited ₹ 800 per month for 1\(\frac { 1 }{ 2 }\) years. If he received ₹ 15,084 at the time of maturity, find the rate of interest per annum. (2014)
Solution:
Money deposited per month (P) = ₹ 800
r = ?
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2B 9.1

Question 10.
Katrina opened a recurring deposit account with a Nationalised Bank for a period of 2 years. If the bank pays interest at the rate of 6% per annum and the monthly installment is ₹ 1,000, find the :
(i) interest earned in 2 years
(ii) maturity value. (2015)
Solution:
Period (n) = 2 years = 2 x 12 = 24 months
Rate of interest (r) = 6%
Monthly installment (P) = ₹ 1000
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2B 10.1

Question 11.
Mohan has a recurring deposit account in a bank for 2 years at 6% p.a. simple interest. If he gets ₹ 1200 as interest at the time of maturity, find :
(i) the monthly installment
(ii) the amount of maturity
Solution:
(i) Interest = ₹ 1200,
n = 2 x 12 = 24 months,
r = 6%
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2B 11.1
⇒ P = ₹ 800
So the monthly installment is ₹ 800
(ii) Total sum deposited = P x n = ₹ 800 x 24 = ₹ 19200
The amount that Mohan will get at the time of maturity = Total sum deposited + Interest Received
= ₹ 19200 + ₹ 1200 = ₹ 20400
Hence, the amount of maturity is ₹ 20400

Hope given Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2B are helpful to complete your math homework.

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Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A

Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking (Recurring Deposit Accounts) Ex 2A

These Solutions are part of Selina Concise Mathematics Class 10 ICSE Solutions. Here we have given Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A.

Other Exercises

Question 1.
Manish opens a Recurring Deposit Account with the Bank of Rajasthan and deposits ₹ 600 per month for 20 months. Calculate the maturity value of this account, if the bank pays interest at the rate of 10% per annum.
Solution:
Recurring Deposit per month = ₹ 600
Period (n) = 20 months
Rate of interest (r) = 10% p.a.
Total principal for 1 month
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A 1.1
Maturity value = ₹ 600 x 20 + ₹ 1,050 = ₹ 12,000 + ₹ 1,050 = ₹ 13,050

Question 2.
Mrs. Mathew opened a Recurring Deposit Account in a certain bank and deposited ₹ 640 per month for 4\(\frac { 1 }{ 2 }\) years. Find the maturity value of this account, if the bank pays interest at the rate of 12% per year.
Solution:
Recurring deposit per month = ₹ 640
Period (n) = 4\(\frac { 1 }{ 2 }\) years = 54 months
Rate of interest (r) = 12%
Total principal for 1 month
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A 2.1
Maturity value = ₹ 640 x 54 + ₹ 9,504 = ₹ 34,560 + ₹ 9,504 = ₹ 44,064

Question 3.
Each of A and B opened a recurring deposit accounts in a bank. If A deposited ₹ 1,200 per month for 3 years and B deposited ₹ 1,500 per month for 2\(\frac { 1 }{ 2 }\) years; find, on maturity, who will it get more amount and by how much ? The rate of interest paid by the bank is 10% per annum.
Solution:
A’s deposit per month (P) = ₹ 1200
Period = 3 years = 36 months
Total principal for one month
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A 3.1
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A 3.2
and maturity value = ₹ 1500 x 30 + Interest
= ₹ 45000 + 5812.50
= ₹ 50812.50
It is clear that B’s maturity value is greater Difference = ₹ 50812.50 – ₹ 49860 = ₹ 952.50

Question 4.
Ashish deposits a certain sum of money every month in a Recurring Deposit Account for a period of 12 months. If the bank pays interest at the rate of 11% p.a. and Ashish gets ₹ 12,715 as the maturity value of this account, what sum of money did he pay every month ?
Solution:
Let Recurring deposit per month = ₹ x
Period (n) = 12 months
Rate of interest (r) = 11%
Maturity value = ₹ 12,715 ………. (i)
Total principal for one month
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A 4.1
Recurring deposit per month ₹ 1000 p.m.

Question 5.
A man has a Recurring Deposit Account in a bank for 3\(\frac { 1 }{ 2 }\) years. If the rate of interest is 12% per annum and the man gets ₹ 10206 on maturity, find the value of monthly installments.
Solution:
Let Recurring deposit per month = ₹ x
Period (n) = 3\(\frac { 1 }{ 2 }\) years = 42 months
Rate of interest (r) = 12% p.a.
Amount of maturity = ₹ 10206 ……… (i)
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A 5.1
Amount of each installment = ₹ 200

Question 6.
(i) Puneet has a Recurring Deposit Account in the Bank of Baroda and deposits ₹ 140 per month for 4 years If he gets ₹ 8,092 on maturity, find the rate of interest given by the bank.
(ii) David opened a Recurring Deposit Account in a bank and deposited ₹ 300 per month for two years. If he received ₹ 7725 at the time of maturity, find the rate of interest per annum. (2008)
Solution:
(i) Recurring deposit per month = ₹ 140
Period (n) = 4 years = 48 months
Let Rate of interest (r) = r % p.a.
Amount of maturity = ₹ 8,092
Total principal for one month
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A 6.1
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A 6.2

Question 7.
Amit deposited ₹ 150 per month in a bank for 8 months under the Recurring Deposits Scheme. What will be the maturity value of his deposits, if the rate of interest is 8% per annum and interest is calculated at the end of every month ? [I.C.S.E. 2001]
Solution:
Amount of Recurring deposit = ₹ 150
Period (n) = 8 months
Rate of interest (r) = 8% p.a.
Total principal for one month
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A 7.1
Amount of maturity value = ₹ 150 x 8 + ₹ 36 = ₹ 1,200 + ₹ 36 = ₹ 1,236

Question 8.
Mrs. Geeta deposited ₹ 350 per month in a bank for 1 year and 3 months under the Recurring Deposit Scheme. If the maturity value of her deposits is ₹ 5,565; find the rate of interest per annum.
Solution:
Amount of recurring deposit per month = ₹ 350
Period (n) = 1 year 3 months = 15 months
Let rate of interest = r % p.a.
Amount of maturity = ₹ 5565
Amount of interest = ₹ 5,565 – ₹ 350 x 15 = ₹ 5,565 – 5,250 = ₹ 315 ….(i)
Now, total principal for one month
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A 8.1

Question 9.
A recurring deposit account of ₹ 1,200 per month has a maturity value of ₹ 12,440. If the rate of interest is 8% and the interest is calculated at the end of every month; find the time (in months) of this Recurring Deposit Account.
Solution:
Amount of recurring deposit per month = ₹ 1,200
Rate of interest (r) = 8% p.a.
Let period = n months
Amount of maturity = ₹ 12,440
Amount of interest = ₹ 12440 – ₹ 1200 x n ….(i)
Total principal for one month
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A 9.1
from (i) and (ii), we get,
4n (n + 1) = 12440 – 1200n
⇒ 4n² + 4n = 12440 – 1200n
⇒ 4n² + 1204n – 12440 = 0
Dividing by 4,
⇒ n² + 301n – 3110 = 0
⇒ n² + 311n – 10n – 3110 = 0
⇒ n (n + 311) – 10 (n + 311) = 0
⇒ (n + 311) (n – 10) = 0
Given n + 311 = 0, then n = – 311 Which is not possible,
or n – 10 = 0, then n = 10
Period = 10 months.

Question 10.
Mr. Gulati has a Recurring Deposit Account of ₹ 300 per month. If the rate of interest is 12% and the maturity value of this account is ₹ 8,100; find the time (in years) of this Recurring Deposit Account.
Solution:
Amount of recurring deposit per month = ₹ 300
Let Period = n months
Rate of interest (r) = 12% p.a.
Amount of maturity = ₹ 8,100
Interest = 8,100 – 300 x n ……. (i)
Total principal for 1 month
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A 10.1
⇒ 3n (n + 1) = 16,200 – 600 n
⇒ 3n² + 3n = 16,200 – 600 n
⇒ 3n² + 603n – 16,200 = 0
Dividing by 3, we get,
⇒ n² + 201n – 5,400 = 0
⇒ n² + 225n – 24n – 5,400 = 0
⇒ n(n + 225) – 24 (n + 225) = 0
⇒ (n + 225) (n – 24) = 0
Either n + 225 = 0, then n = – 225 Which is not possible
or n – 24 = 0, then n = 24
Period = 24 months or 2 years.

Question 11.
Mr. Gupta opened a recurring deposit account in a bank. He deposited ₹ 2,500 per month for two years. At the time of maturity he got ₹ 67,500. Find :
(i) the total interest earned by Mr. Gupta.
(ii) the rate of interest per annum. (2010)
Solution:
(i) Total amount deposited by Mr. Gupta in 24 months = ₹ 2500 x 24 = ₹ 60,000
Maturity amount = ₹ 67,500
Total interest earned by Mr. Gupta = ₹ 67,500 – ₹ 60,000 = ₹ 7,500
(ii) Total principal for 1 month
Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A 11.1

Hope given Selina Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking Ex 2A are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.