NCERT Solutions for Class 8 Maths

NCERT Solutions for Class 8 Maths Chapter 5 Data Handling Ex 5.1 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 5 Data Handling Ex 5.1.

• Data Handling Class 8 Ex 5.2
• Data Handling Class 8 Ex 5.3

Board	CBSE
Textbook	NCERT
Class	Class 8
Subject	Maths
Chapter	Chapter 5
Chapter Name	Data Handling
Exercise	Ex 5.1
Number of Questions Solved	5
Category	NCERT Solutions

NCERT Solutions for Class 8 Maths Chapter 5 Data Handling Ex 5.1

Question 1.
For which of these would you use a histogram to show the data?
(a) The number of letters for different areas in a postman’s bag.
(b) The height of competitors in an athletics meet.
(c) The number of cassettes produced by 5 companies.
(d) The number of passengers boarding trains from 7:00 a.m. to 7:00 p.m at a station.
Give reasons for each.
Solution.
For (b) and (d) because in these two cases data can be grouped into class intervals.

Question 2.
The shoppers who come to a departmental store are marked as man (M), woman (W), boy (B) or girl (G). The following list gives the shoppers who came during the first hour in the morning.
WWWGBWWMGGMMWWWWG
BMWBGGMWWMMWW
WMWBWGMWWWWGWMMWW
MWGWMGWMMBGGW
Make a frequency distribution table using tally marks. Draw a bar graph to illustrate it.
Solution.

Question 3.
The weekly wages (in of 30 workers in a factory are:
830, 835, 890, 810, 835, 836, 869, 845, 898, 890, 820, 860,
832, 833, 855, 845, 804, 808, 812, 840, 885, 835, 835, 836,
878, 840, 868, 890, 806, 840.
Solution.

Question 4.
Draw a histogram for the frequency table made for the data in Question 3, and answer the following questions:
(i) Which group has the maximum number of workers?
(ii) How many workers earnt 850 and more?
(iii) How many workers earn less than? 850?
Solution.

(i) Group 830—840, has the maximum number of workers.
(ii) 1 + 3 + 1 + 1 + 4 = 10, workers earn ? 850 and more.
(iii) 3 + 2 + l + 9 + 5 = 20, workers earn less than ? 850.

Question 5.
The number of hours for which students of a particular class watched television during holidays is shown through the given graph:

Answer the following:
(i) For how many hours did the maximum number of students watch TV?
(ii) How many students watched TV for less than 4 hours?
(iii) How many students spent more than 5 hours watching TV?
Solution.
(i) The maximum number of students watch TV for 4 to 5 hours.
(ii) 4 + 8 + 22 = 34 students watch TV for less than 4 hours.
(iii) 8 + 6 = 14 students spend more than 5 hours in watching TV.

 

We hope the NCERT Solutions for Class 8 Maths Chapter 5 Data Handling Ex 5.1 help you. If you have any query regarding NCERT Solutions for Class 8 Maths Chapter 5 Data Handling Ex 5.1, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.1 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.1.

• Practical Geometry Class 8 Ex 4.2
• Practical Geometry Class 8 Ex 4.3
• Practical Geometry Class 8 Ex 4.4
• Practical Geometry Class 8 Ex 4.5

Board	CBSE
Textbook	NCERT
Class	Class 8
Subject	Maths
Chapter	Chapter 4
Chapter Name	Practical Geometry
Exercise	Ex 4.1
Number of Questions Solved	1
Category	NCERT Solutions

NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.1

Question 1.
Construct the following quadrilaterals:
(i) Quadrilateral ABCD
AB = 4.5 cm
BC = 5.5 cm
CD = 4 cm
AD = 6 cm
AC = 7 cm

(ii) Quadrilateral JUMP
JU = 3.5 cm
UM = 4 cm
MP = 5 cm
PJ = 4.5 cm
PU 6.5 cm

(iii) Parallelogram MORE
OR = 6 cm
RE = 4.5 cm
EO = 7.5 cm

(iv) Rhombus BEST
BE = 4.5 cm
ET = 6 cm
Solution.
(i) Steps of Construction

1. Draw AB 4.5 cm
2. With A as centre and radius AC = 7 cm, draw an arc.
   
3. With B as center and radius BC = 5.5 cm, draw another arc to intersect the arc drawn in step (2) at C.
4. With A as center and radius AD = 6 cm, draw an arc on the side of AC, opposite to that of B.
5. With C as center and radius CD = 4 cm, draw another arc to intersect the arc drawn in step (4) at D.
6. Join BC, CD, DA, and AC.

Then, ABCD is the required quadrilateral.

(ii) Steps of Construction

1. Draw JU = 3.5 cm
2. With J as center and radius JP = 4.5 cm, draw an arc.
3. With U as center and radius UP = 6.5 cm, draw another arc to intersect the arc drawn in step 2 at P.
   
4. With U as center and radius UM = 4 cm, draw an arc on the side of PU opposite to that of J.
5. With P as center and radius PM = 5 cm, draw another arc to intersect the arc drawn in step 4 at M.
6. Join UM, MP, PJ, and UP.

Then, JUMP is the required quadrilateral.

(iii) Steps of Construction
[We know that in a parallelogram, opposite sides are equal in length.
∴ MO = ER = 4.5 cm and ME – OR = 6 cm]

1. Draw MO = 4.5 cm
2. With M as center and radius ME = 6 cm, draw an arc.
   
3. With O as center and radius OE = 7.5 cm, draw an arc to intersect the arc drawn in step 2 at E.
4. With O as center and radius OR = 6 cm, draw an arc on the side of OE opposite to that of M.
5. With E as center and radius ER = 4.5 cm, draw another arc to intersect the arc drawn in step 4 at R.
6. Join OR, RE, EM, and EO.

Then, MORE is the required parallelogram.

(iv) Steps of Construction
[We know that in a rhombus, all the sides are equal in length.
∴ BE = ES = ST = TB = 4.5 cm]

1. Draw BE = 4.5 cm
2. With B as centre and radius BT = 4.5 cm, draw an arc.
   
3. With E as center and radius
   ET = 6 cm, draw another arc to intersect the arc drawn in step 2 at T.
4. With E as center and radius
   ES = 4.5 cm, draw an arc on the side of ET opposite to that of B.
5. With T as center and radius
   TS = 4.5 cm, draw another arc to
   intersect the arc drawn in step 4 at S.
6. Join ES, ST, TB, and TE.

Then, BEST is the required rhombus.

 

We hope the NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.1 help you. If you have any query regarding NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.1, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals Ex 3.1 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals Ex 3.1.

• Understanding Quadrilaterals Class 8 Ex 3.2
• Understanding Quadrilaterals Class 8 Ex 3.3
• Understanding Quadrilaterals Class 8 Ex 3.4

Board	CBSE
Textbook	NCERT
Class	Class 8
Subject	Maths
Chapter	Chapter 3
Chapter Name	Understanding Quadrilaterals
Exercise	Ex 3.1
Number of Questions Solved	7
Category	NCERT Solutions

NCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals Ex 3.1

Question 1.
Given here are some figures :

Classify each of them on the basis of the following :
(a) Simple curve
(b) Simple closed curve
(c) Polygon
(d) Convex polygon
(e) Concave polygon
Solution.
(a) ⟷ 1, 2, 5, 6, 7
(b) ⟷ 1, 2, 5, 6, 7

Question 2.
How many diagonals does each of the following have?
(a) A convex quadrilateral
(b) A regular hexagon
(c) A triangle.
Solution.
(a) → 2
(b) → 9
(c) → 0

Question 3.
What is the sum of the measures of the angles of a convex quadrilateral? Will this property hold if the quadrilateral is not convex? (Make a non-convex quadrilateral and j try!)
Solution.
The sum of the measures of the angles of a convex quadrilateral is 360°.
Yes! this property will hold if the; quadrilateral is not convex.
If the quadrilateral is not convex, then it will be concave.
Split the concave quadrilateral ABCD into two triangles ABD and CBD by joining BD.

Question 4.
Examine the table. (Each figure is divided into triangles and the sum of the angles deduced from that.)

What can you say about the angle sum of a convex polygon with number of sides ?
(a) 7
(b) 8
(c) 10
(d) n
Solution.
(a) 7
Angle sum = \(\left( 7-2 \right) \times { 180 }^{ \circ }\)
= \(5\times { 180 }^{ \circ }={ 900 }^{ \circ }\)

(b) 8
Angle sum = \(\left( 8-2 \right) \times { 180 }^{ \circ }\)
= \(6\times { 180 }^{ \circ }={ 1080 }^{ \circ }\)

(c) 10
Angle sum = \(\left( 10-2 \right) \times { 180 }^{ \circ }\)
= \(8\times { 180 }^{ \circ }={ 1440 }^{ \circ }\)

(d) n
Angle sum = \(\left( n-2 \right) \times { 180 }^{ \circ }\)

Question 5.
What is a regular polygon? State the name of a regular polygon of
(i) 3 slides
(ii) 4 slides
(iii) 6 slides
Solution.
A polygon, which is both ‘equilateral’ and ‘equiangular’, is called a regular polygon.
(i) 3 slides
The name of the regular polygon of 3 slides is an equilateral triangle.
(ii) 4 slides
The name of the regular polygon of 4 slides is square
(iii) 6 slides
The name of the regular polygon of 6 slides is a regular hexagon

Question 6.
Find the angle measure x in the following figures.

Solution.

Question 7.

(a) Find x+y+z

(b) Find x+y+z+w.
Solution.

 

We hope the NCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals Ex 3.1 help you. If you have any query regarding NCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals Ex 3.1, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1.

• Linear Equations in One Variable Class 8 Ex 2.2
• Linear Equations in One Variable Class 8 Ex 2.3
• Linear Equations in One Variable Class 8 Ex 2.4
• Linear Equations in One Variable Class 8 Ex 2.5
• Linear Equations in One Variable Class 8 Ex 2.6

Board	CBSE
Textbook	NCERT
Class	Class 8
Subject	Maths
Chapter	Chapter 2
Chapter Name	Linear Equations in One Variable
Exercise	Ex 2.1, Ex 2.2, Ex 2.3, Ex 2.4, Ex 2.5, Ex 2.6
Number of Questions Solved	1
Category	NCERT Solutions

NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1

Question 1.
Solve the following equations:

Solution.
1. x-2 = 7

2. y+3=10

3. 6=z+2

4. \(\frac { 3 }{ 7 } +x=\frac { 17 }{ 7 } \)

5. 6x=12

6. \(\frac { t }{ 5 } =10\)

7. \(\frac { 2x }{ 3 } =18\)

8. \(1.6=\frac { y }{ 1.5 }\)

9. 7x-9=16

10. 14y-8=13

11. 17+6p=9

12. \(\frac { x }{ 3 } +1=\frac { 7 }{ 15 } \)

 

We hope the NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1 help you. If you have any query regarding NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1, drop a comment below and we will get back to you at the earliest.