## RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder VSAQS

These Solutions are part of RD Sharma Class 9 Solutions. Here we have given RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder VSAQS

Other Exercises

- RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder Ex 19.1
- RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder Ex 19.2
- RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder VSAQS
- RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder MCQS

Question 1.

Write the number of surface of a right circular cylinder.

Solution:

Three, two circular and one curved.

Question 2.

Write the ratio of total surface area to the curved surface area of a cylinder of radius r and height h.

Solution:

∵ Radius = r

and height = h

∴ Curved surface area = 2πrh

and total surface area = 2πr(h + r)

∴ Ratio = 2πr(h + r) : 2πrh

= h + r : h

Question 3.

The ratio between the radius of the base and height of a cylinder is 2 : 3. If its volume is 1617 cm3, find the total surface area of the cylinder.

Solution:

Ratio in radius and height of the cylinder = 2 : 3

Let radius (r) = 2x

Then height (h) = 3x

∴ Volume = πr^{2}h

Question 4.

If the radii of two cylinders are in the ratio 2 : 3 and their heights are in the ratio 5 : 3, then find the ratio of their volumes.

Solution:

Ratio of radii of two cylinder = 2:3

Let radius of first cylinder (r* _{1}*) = 2x

and second cylinder (r

_{2}) = 3x

and ratio in their heights = 5:3

Let height of first cylinder (h

_{1}) = 5y

and height of second (h

_{2}) = 3y

∴ Volume of the first cylinder =πr

^{2}h

= π x (2x)

^{2}x 5y = 20πx

^{2}y

and volume of second cylinder = π(3x)2 x 3y = 27πx

^{2}y

Now ratio between then,

= 20πx

^{2}y: 21πx

^{2}y

= 20 : 27

Hope given RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder VSAQS are helpful to complete your math homework.

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