MCQ Questions for Class 10 Sanskrit Chapter 12 अनयोक्त्यः with Answers

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निम्नवाक्येषु रेखाकितानां पदानां स्थानेषु प्रश्नवाचकं पदं चित्वा लिखत

Question 1.
एकेन एव राजहंसेन सरसः या शोभा भवेत्।
(i) कः
(i) कति
(iii) कस्य
(iv) किम्

Answer

Answer: (iii) कस्य


Question 2.
न सा परितः तीरवासिना बकसहस्रेण भवेत्।
(i) कथम्
(ii) केण
(iii) केन
(iv) कीदृशेण

Answer

Answer: (iii) केन


Question 3.
हे राजहंस! भवता मृणालपटली भुक्ता।
(i) का
(ii) काः
(iii) कः
(iv) किम्

Answer

Answer: (i) का


Question 4.
एवं नलिनानि अनेकानि निषेविहानि।
(i) के
(ii) कति
(iii) किम्
(iv) कानि

Answer

Answer: (iv) कानि


Question 5.
तस्य सरोवरस्य केन कृत्येन कृतोपकारः त्वं भवितासि?
(i) कीदृशः
(ii) कः
(iii) का
(iv) कथम्

Answer

Answer: (i) कीदृशः


Question 6.
मालाकार! भवता करुणया तरोः अस्य तोयैरल्पैरपि पुष्टिः व्यरचि।
(i) का
(ii) कः
(iii) केन
(iv) काः

Answer

Answer: (iii) केन


Question 7.
भवता भीमभानौ निदाघे करुणया पुष्टिः व्यरचि।
(i) कदा
(ii) कीदृशः
(iii) कौ
(iv) कीदृशौ

Answer

Answer: (i) कदा


Question 8.
प्रावृषेण्येन वारिदेन वाराम् विश्वतः इह जनयितुं शक्या।
(i) केन
(ii) कीदृशेन
(iii) कथम्
(iv) कदा

Answer

Answer: (ii) कीदृशेन


Question 9.
पतङ्गाः परितः अम्बरपथं आपेदिरे।
(i) के
(ii) काः
(iii) कः
(iv) का

Answer

Answer: (i) के


Question 10.
भृङ्गाः रसालमुकुलानि समाश्रयन्ते।
(i) किम्
(ii) कानि
(iii) के
(iv) कति

Answer

Answer: (ii) कानि


Question 11.
सरः त्वयि दीनदीनः सङ्कोचम् अञ्चति।
(i) कति
(ii) कानि
(iii) कस्मै
(iv) कस्मिन्

Answer

Answer: (iv) कस्मिन्


Question 12.
मीनः नु कतमा गतिम् अभ्युपैतु।
(i) का
(ii) कः
(iii) के
(iv) किम्

Answer

Answer: (ii) कः


Question 13.
चातक: मानी खगः भवति।
(i) कीदृशः
(ii) कीदृशी
(iii) कीदृशम्
(iv) कीदृशा

Answer

Answer: (i) कीदृशः


Question 14.
एकः चातकः वने वसति।
(i) कः
(ii) का
(iii) कति
(iv) किम्

Answer

Answer: (iii) कति


Question 15.
चातक: पिपासितः एव म्रियते।
(i) कीदृशः
(ii) कीदृशी
(iii) कीदृशम्
(iv) कीदृशाः

Answer

Answer: (i) कीदृशः


निम्नलिखितान् श्लोकान् पठित्वा तदाधारितानां प्रश्नानामुत्तराणि लिखत

(क) एकेन राजहंसेन या शोभा सरसो भवेत।
न सा बकसहस्रेण परितस्तीरवासिना॥

Question 1.
कति राजहंसेन सरसः शोभा भवति?

Answer

Answer: एकेन


Question 2.
केन सरसः शोभा भवति?

Answer

Answer: राजहंसेन


Question 3.
केन सरसः शोभा न भवति?

Answer

Answer: परितः तीरवासिना बकसहस्रेण सरसः शोभा न भवति।


Question 4.
‘एकेन राजहंसेन’ अनयोः पदयोः विशेषणपदं किमस्ति?

Answer

Answer: एकेन


Question 5.
श्लोकस्य ‘शोभा’ इति कर्तृपदस्य क्रियापदं किम्?

Answer

Answer: भवेत्


Question 6.
श्लोके ‘सा’ इत्यस्य विशेषणस्य विशेष्यः कः?

Answer

Answer: शोभा


(ख) भुक्ता मृणालपटली भवता निपीता
न्यम्बूनि यत्र नलिनानि निषेवितानि।
रे राजहंस! वद तस्य सरोवरस्य,
कृत्येन केन भवितासि कृतोपकारः॥

Question 1.
‘यत्र भवता मृणालपाटली भुक्ता’। अत्र कर्तृपदं किम्?
(क) यत्र
(ख) भवता
(ग) भुक्ता
(घ) मृणालपाटली

Answer

Answer: (ख) भवता


Question 2.
श्लोके ‘केन कृत्येन’ अतयोः पदयोः विशेषणपदं किमस्ति?
(क) केन
(ख) किम्
(ग) कृत्येन
(घ) कृत्यम्

Answer

Answer: (क) केन


Question 3.
अस्मिन् श्लोके ‘जलानि’ पदस्य कः पर्यायः आगतः?
(क) नलिनानि
(ख) निपीतानि
(ग) अम्बूनि
(घ) निषेवितानि

Answer

Answer: (ग) अम्बूनि


Question 4.
राजहंसः कां भुनक्ति?

Answer

Answer: मृणालपाटलीम्


Question 5.
कः सरोवरस्य कृतोपारकः भवति?

Answer

Answer: राजहंसः सरोवरस्य कृतोपकारकः भवति।


(ग) तोयैरल्यैरपि करुणया भीमभानौ निदाघे,
मालाकार! व्यरचि भवता या तरोरस्य पुष्टिः।
सा किं शक्या जनयितुमिह प्रावृषेण्येन वारां,
धारासारानपि विकिरता विश्वतो वारिदेन॥

Question 1.
कः भीमभानौ निदाघे तरोः पुष्टिम् व्यरचयति?

Answer

Answer: मालाकारः


Question 2.
मालाकारः कति जलैः तरोः पुष्टिं करोति?

Answer

Answer: अल्पैः।


Question 3.
वारिदेन का कर्तम् न शक्या अस्ति?

Answer

Answer: वारिदेन इह जनयितुं पुष्टिं कर्तुं न शक्या अस्ति।


Question 4.
श्लोके ‘तोयैः’ इति विशेष्य पदस्य विशेषणं किमस्ति?

Answer

Answer: अल्पैः


Question 5.
‘भवता करुणया अस्य ……..’ अत्र ‘भवता’ पदं कस्मै आगतम्?

Answer

Answer: मालाकाराय


Question 6.
अस्मिन् श्लोके ‘वृक्षस्य’ इति पदस्य कः पर्यायः आगतः?

Answer

Answer: तरोः


(घ) आपेदिरेऽम्बरपथं परितः पतङ्गाः,
भृङ्गा रसालमुकुलानि समाश्रयन्ते।
सङ्कोचमञ्चति सरस्त्वयि दीनदीनो,
मीनो नु हन्त कतमां गतिमभ्युपैतु॥

Question 1.
श्लोके ‘कतमां गतिम्’ पदयोः कः विशेष्यः वर्तते?
(क) गतिः
(ख) कतमा
(ग) कतमां
(घ) गतिम्

Answer

Answer: (घ) गतिम्


Question 2.
अत्र श्लोके ‘आपेदिरे’ इति क्रियायाः कर्तृपदं किम्?
(क) परितः
(ख) पतङ्गाः
(ग) अम्बरपथम्
(घ) पथम्

Answer

Answer: (ख) पतङ्गाः


Question 3.
‘सरः त्वयि सङ्कोचम्’। अत्र ‘त्वयि’ पदं कस्मै आगतम्?
(क) सरसे
(ख) मीनाय
(ग) भृङ्गेभ्यः
(घ) पतङ्गेभ्यः

Answer

Answer: (क) सरसे


Question 4.
परितः पतङ्गाः कुत्र (कम्) आपेदिरे?

Answer

Answer: अम्बरपथम्


Question 5.
के रसालमुकुलानि समाश्रयन्ते?

Answer

Answer: भृङ्गाः


Question 6.
सरः सङ्कोचम् अञ्चति कः कतमां गतिम् अभ्युपैतु?

Answer

Answer: सरः सङ्कोचम् अञ्चति दीनदीनः मीनः कतमा गतिम् अभ्युपैतु।


(ङ) एक एव खगो मानी वने वसति चातकः।
पिपासितो वा म्रियते याचते वा पुरन्दरम्॥

Question 1.
चातकः कीदृशः खगः वर्तते?

Answer

Answer: मानी


Question 2.
कः वने वसति?

Answer

Answer: चातक:


Question 3.
कीदृशः चातकः म्रियते?

Answer

Answer: पिपासितः चातक: म्रियते।।


Question 4.
‘मानी’ इति विशेषणस्य कः विशेष्य श्लोके आगतोऽस्ति?

Answer

Answer: खगः


Question 5.
श्लोके ‘म्रियते’ इत्यस्य क्रियापदस्य कर्तृपदं किम्?

Answer

Answer: चातकः


Question 6.
अत्र श्लोके ‘नश्यति’ इत्यस्य कः पर्यायः आगतः?

Answer

Answer: म्रियते


(च) आश्वास्य पर्वतकुलं तपनोष्णतप्त
मुद्दामदावविधुराणि च काननानि।
नानानदीनदशतानि च पूरयित्वा,
रिक्तोऽसि यज्जलद! सैव तवोत्तमा श्रीः॥

Question 1.
श्लोके ‘सा’ पदं कस्मै आगतम्?
(क) श्रियै
(ख) उत्तमायै
(ग) जलदाय
(घ) काननेभ्यः

Answer

Answer: (क) श्रियै


Question 2.
अत्र श्लोके ‘पर्वतकुलम्’ इत्यस्य विशेष्यस्य विशेषणपदं किम्?
(क) तप्तम्
(ख) उष्णम्
(ग) तपनोष्णतप्तम्
(घ) तपनम्

Answer

Answer: (ग) तपनोष्णतप्तम्


Question 3.
‘असि तव सा एव।’ अत्र ‘तव’ पदं कं प्रति सङ्केतयति?
(क) जलदम्
(ख) श्रियम्
(ग) पर्वतकुलम्
(घ) काननम्

Answer

Answer: (क) जलदम्


Question 4.
अस्मिन् श्लोके कं संबोधनं कृतम्?

Answer

Answer: जलदम्


Question 5.
जलदः कीदृशं पर्वतकुलम् आश्वासयति?

Answer

Answer: तपनोष्णतप्तम्।


Question 6.
जलदः कानि पूरयित्वा स्वयं रिक्तो भवति?

Answer

Answer: जलद: नानानदीनदशतानि पूरयित्वा स्वयं रिक्तो भवति।


(छ) रे रे चातक! सावधानमनसा मित्र क्षणं श्रूयता
मम्भोदा बहवो हि सन्ति गगने सर्वेऽपि नैतादृशाः।
केचिद् वृष्टिभिरार्द्रयन्ति वसुधां गर्जन्ति केचिद् वृथा,
यं यं पश्यसि तस्य तस्य पुरतो मा ब्रूहि दीनं वचः॥

Question 1.
अस्मिन् श्लोके कविः कं सम्बोधयति?

Answer

Answer: चातकम्


Question 2.
के वृष्टिभिः वसुधाम् आर्द्रयन्ति?

Answer

Answer: अम्भोदाः


Question 3.
गगने हि बहवः के सन्ति?

Answer

Answer: गगने हि बहवः अम्भोदाः सन्ति।


Question 4.
‘त्वं दीनं वचः मा ब्रूहि’। अत्र क्रियापदं किम्?

Answer

Answer: ब्रूहि


Question 5.
‘बहव अम्भोदाः’ अनयोः पदयोः विशेषणपदं किम्?

Answer

Answer: बहवः


Question 6.
श्लोके ‘समक्षम्’ इत्यस्य पदस्य कः पर्यायः आगतोऽस्ति?

Answer

Answer: पुरतः


अधोलिखितानां श्लोकानाम् अन्वयं मञ्जूषायाः उचितैः पदैः सम्पूर्य लिखत

(क) एकेन राजहंसेन या शोभा सरसो भवेत्।
न सा बकसहस्त्रेण परितस्तीरवासिना॥

अन्वयः-एकेन (i) ……………… सरस: या (ii) …………….. भवेत्। परतिः (iii) …………….. बकसहस्रेण (iv) ………………….. (शोभा) न (भवति)।।
मञ्जूषा- शोभा, सा, राजहंसेन, तीरवासिना|

Answer

Answer:
(i) राजहंसेन
(ii) शोभा
(iii) तीरवासिना
(iv) सा


(ख) भुक्ता मृणालपटली भवता निपीता
न्यम्बूनि यत्र नलिनानि निषेवितानि।
रे राहजंस! वद तस्य सरोवरस्य,
कृत्येन केन भवितासि कृतोपकार॥

अन्वयः- (रे राजहंस!) यत्र भवता (i) ………………. भुक्ता, अम्बूनि निपीतानि (ii) ………….. निषेवितानि। रे राजहंस! तस्य (iii) …………………….. (भवतः) केन कृत्येन (iv) …………………. भविता असि, वद।
मञ्जूषा- सरोवरस्य, मृणालपटली, कृतोपकारः, नलिनानि

Answer

Answer:
(i) मृणालपटली
(ii) नलिनानि
(iii) सरोवरस्य
(iv) कृतोपकारः


(ग) तोयैरल्पैरपि करुणया भीमभानौ निदाघे,
मालाकार! व्यरचि भवता या तरोरस्य पुष्टिः।
सा किं शक्या जनयितुमिह प्रावृषेण्येन वारां,
धारासारानपि विकिरता विश्वतो वारिदेन॥

अन्वयः-हे मालाकार! (i) ………………… निदाघे अल्पैः तोयैः अपि भवता (ii) …………… अस्य तरोः या पुष्टिः व्यरचि। वाराम् (iii) ………………… विश्वतः धारासारान् अपि विकिरता (iv) ………… इह जनयितुम् सा किं शक्या?
मञ्जूषा- वारिदेन, करुणया, भीमभानौ, प्रावृषेण्येन

Answer

Answer:
(i) भीमभानौ
(ii) करुणया
(iii) प्रावृषेण्येन
(iv) वारिदेन


(घ) आपेदिरेऽम्बरपथं परितः पतङ्गाः,
भृङ्गा रसालमुकुलानि समाश्रयन्ते।
सङ्कोचमञ्चति सरस्त्वयि दीनदीनो,
मीनो नु हन्त कतमां गतिमभ्युपैतु॥

अन्वयः- पतङ्गाः परतिः (i) ……………….. आपेदिरे, (ii) ………………. रसालमुकुलानि सामश्रयन्ते। सरः (iii) …………….. सङ्कोचम् अञ्चति, हन्तः (iv) …………. मीनः नु कतमां गतिम् अभ्युपैतु।
मञ्जूषा- अम्बरपथम्, दीनदीनः, भृङ्गाः, त्वयि

Answer

Answer:
(i) अम्बरपथम्
(ii) भृङ्गाः।
(iii) त्वयि
(iv) दीनदीनः


(ङ) एक एव खगो मानी वने वसति चातकः।
पिपासितो वा म्रियते याचते वा पुरन्दरम्॥

अन्वयः एकः एव (i) ……………. खगः चातकः (ii) ……………….. वसति। वा (iii) ………………. म्रियते (iv) ……………. याचते वा।
मञ्जूषा- वने, पिपासितः, मानी, पुरन्दरम्

Answer

Answer:
(i) मानी
(ii) वने
(iii) पिपासितः
(iv) पुरन्दरम्


(च) आश्वास्य पर्वतकुलं तपनोष्णतप्त
मुद्दामदावविधुराणि च काननानि।
नानानदीनदशतानि च पूरयित्वा,
रिक्तोऽसि यज्जलद! सैव तवोत्तमा श्रीः॥

अन्वयः- (i) ……………. पर्वतकुलम् आश्वास्य उद्दामदावविधुराणि (ii) ……………. नानानदीनदशतानि (iii) ……………. च, हे जलद! यत् रिक्त असि तव सा एव (iv) ……………… (अस्ति)।
मञ्जूषा- काननानि, तपनोष्णतप्तम्, उत्तमा, पूरयित्वा

Answer

Answer:
(i) तपनोष्णतप्तम्
(ii) काननानि
(iii) पूरयित्वा
(iv) उत्तमा


(छ) रे रे चातक! सावधानमनसा मित्र क्षणं श्रूयता
मम्भोदा बहवो हि सन्ति गगने सर्वेऽपि नैतादृशाः।
केचिद् वृष्टिभिरार्द्रयन्ति वसुधां गर्जन्ति केचिद् वृथा,
यं यं पश्यसि तस्य तस्य पुरतो मा ब्रूहि दीनं वचः॥

अन्वयः-रे रे मित्र चातक! (i) ……………..
क्षणं श्रूयताम् गगने हि बहवः (ii) …………. सन्ति, सर्वे अपि एतादृशाः न (सन्ति)। केचिद् (iii) …………………. वृष्टिभिः आर्द्रयन्ति, केचित् (च) वृथा गर्जन्ति, यं यम् पश्यसि तस्य तस्य
(iv) ………….. दीनं वचः मा ब्रूहि।।
मञ्जूषा- पुरतः, अम्भोदाः, सावधानमनसा, वसुधां

Answer

Answer:
(i) सावधानमनसा
(ii) अम्भोदाः
(iii) वसुधां
(iv) पुरतः


निम्नलिखितानि श्लोकानि पठित्वा मञ्जूषायाः सहायतया तेषां भावपूर्तिं कृत्वा लिखत

(क) एकेन राजहंसेन या शोभा सरसो भवेत्।
न सा बकसहस्रेण परितस्तीरवासिना॥

भावार्थ:-अस्य भावोऽस्ति यत् सरसः या (i) ……………….. एकेन राजहंसेन भवति सा एव शोभा तस्य तीरे वसता (ii) ……………… अपि न भविष्यति तथैव एकेनापि (iii) ……………….. समाजस्य देशस्य वा या शोभा भवति सा तु (iv) ……………. अपि भवितुं कदापि न शक्नोति।
मञ्जूषा- मूर्खसहस्रेण, शोभा, बकसहस्रेण, सज्जनेन (विदुषा)

Answer

Answer:
(i) शोभा
(ii) बकसहस्रेण
(iii) सज्जनेन (विदुषा)
(iv) मूर्खसहस्रेण


(ख) भुक्ता मृणालपटली भवता निपीता
न्यम्बूनि यत्र नलिनानि निषेवितानि।
रे राहजंस! वद तस्य सरोवरस्य,
कृत्येन केन भवितासि कृतोपकारः॥

भावार्थ:- अस्य भावोऽस्ति यत् हे राजहंस! भवता यत्र कमलनालानां समूहं खादितम् (i) ……………. च पीतानि एवं कमलानि अपि सेवितानि। त्वमेव वद तस्य (ii) ………….. केन प्रकारेण प्रत्युकारं करिष्यसि अर्थात् स्व जन्मनः देशस्य जातेः, धर्मस्य (iii) …………….. च केन रूपेण ऋणम् अवतारयिष्यसि अतः एतेषां सर्वेषां (iv) ………………. कुरु।
मञ्जूषा- सम्मान, जलानि, सरोवरस्य, संस्कृतेः

Answer

Answer:
(i) जलानि
(ii) सरोवरस्य
(iii) संस्कृतेः
(iv) सम्मानं


(ग) तोयैरल्पैरपि करुणया भीमभानौ निदाघे,
मालाकार! व्यरचि भवता या तरोरस्य पुष्टिः।
सा किं शक्या जनयितुमिह प्रावृषेण्येन वारां,
धारासारानपि विकिरता विश्वतो वारिदेन॥

भावार्थ:-अर्थात् हे मालाकार! त्वम् भीषणतया ग्रीष्मौ (i) ………………. तपति सति अल्पेन जलेन या सेवा भवता अस्य (ii) ………………. पोषणार्थं कृता किं सा एव सेवा (iii) ………………..”परितः धारासु प्रवाहतै जलैः वारिदेन अपि कर्तुं सक्षमेन भूयते? अर्थात् मानवजीवनं केवलं सुखैरेव न प्रवर्धते तदर्धं दुःखमपि तथैव अनिवार्यं वर्तते यथा सुखम् अस्ति। सुखदुःखम् तु मानवजीवनस्य द्वौ (iv) …………… इव वर्तते?
मञ्जूषा- वृक्षस्य, स्कन्धौ, भानौ, वर्षाकाले

Answer

Answer:
(i) भानौ
(ii) वृक्षस्य
(iii) वर्षाकाले
(iv) स्कन्धौ


आपेदिरेऽम्बरपथं परितः पतङ्गाः,
भृङ्गा रसालमुकुलानि समाश्रयन्ते।
सङ्कोचमञ्चति सरस्त्वयि दीनदीनो,
मीनो नु हन्त कतमा गतिमभ्युपैतु॥

भावार्थ:- खगा: ग्रीष्मौ सर्वतः आकाशमार्ग (i) ………… भ्रमराः अपि आम्र मञ्जरी: आश्रिताः अभवन्। अतः सरोवरे (ii) ………….. भवति सति मत्स्याः निराश्रिताः भूत्वा कुत्र (iii) ……………… .ग्रहीष्यन्ति अर्थात् कुत्रापिन। मत्स्याः स्वाश्रयस्य सरोवरस्य दुर्दिने आगते अपि ते (iv) …………… कदापि न त्यक्ष्यन्ति। एतदेव सन्मित्रस्य लक्षणं वर्तते।
मञ्जूषा- प्राप्नुवन्ति, तम्, निर्जले, आश्रयम्

Answer

Answer:
(i) प्राप्नुवन्ति
(ii) निर्जले
(iii) आश्रयम्
(iv) तम्


(ङ) एक एव खगो मानी वने वसति चातकः।
पिपासितो वा म्रियते याचते वा पुरन्दरम्॥

भावार्थ:- स्वाभिमानी खगः (i) ……………… वने उषित्वा (ii) ……………… एव मृत्युम् आ. प्नोति अथवा मेघं स्वात्मने वर्षायाः जलं याचते। सः कदापि (iii) ……………….. जलं न पिबति। एवमेव स्वाभिमानी जनोऽपि स्व सम्मानेन मर्यादितेन जीवनेन सह एव जीवनं याषयन्ति ते कदापि स्वजीवनाय (iv) ………………………. मर्यादाञ्च न त्यजन्ति। अनेन गुणेनैव ते अमराः भवन्ति।
मञ्जूषा- आत्मसम्मानं, धरायाः, चातकः, पिपासितः

Answer

Answer:
(i) चातक:
(ii) पिपासितः
(iii) धरायाः
(iv) आत्मसम्मानं


(च) आश्वास्य पर्वतकुलं तपनोष्णतप्त
मुद्दामदावविधुराणि च काननानि।
नानानदीनदशतानि च पूरयित्वा,
रिक्तोऽसि यज्जलद! सैव तवोत्तमा श्रीः॥

भावार्थ:- सूर्यस्य प्रकाशेन संतप्तं (i) ……………… तृप्तं कृत्वा, उच्चैः वृक्षैः रहितानि वनानि च तृप्तानि कृत्वा नाना नदीः शतानि (ii) …………….. पूरयित्वा अपि यदि जलदः रिक्तोऽवर्तन एन्ततु तस्य उदारता (iii) ……………….. वा भवति। एवमेव सज्जनाः अपि महादानीनाः इव सर्वस्वं दानं कृत्वा (iv) …………….. भवन्ति। इयमेव तेषां शोभा वर्तते।
मञ्जूषा- शोभा, पर्वतसमूह, अतृप्ताः, नदान्।

Answer

Answer:
(i) पर्वतसमूह
(ii) नदान्
(iii) शोभा
(iv) अतृप्ताः


(छ) रे रे चातक! सावधानमनसा मित्र क्षणं श्रूयता
‘मम्भोदा बहवो हि सन्ति गगने सर्वेऽपि नैतादृशाः।
केचिद् वृष्टिभिरार्द्रयन्ति वसुधां गर्जन्ति केचिद् वृथा,
यं यं पश्यसि तस्य तस्य पुरतो मा ब्रूहि दीनं वचः।।

भावार्थ:- अस्य भावोऽस्ति यत् हे मित्र चातक! सावधानं भूत्वा मम वचांसि (i) ………………… अवधीर्यताम् यतः गगने अनेके बद्दलाः सन्ति परन्तु तेषु सर्वे स्व (ii) ………………. धरां न तर्पयन्ति अपितु केचिदेव वर्षन्ति केचित्त वृथा एव गर्जन्ति। अतः यं यं बद्दलं त्वं पश्यसि तस्य-तस्य (सर्वस्य) अग्रे स्वदीनं वचः मा (iii) …………….. एवमेव संसारेऽपि अनेके जनाः सन्ति ते सर्वे स्वमित्राणां सहाय्यं न कुर्वन्ति अतः (iv) …………….. अग्रे स्वदुःखानि प्रकटानि न कुर्युः अनेन आत्मसम्मान समाप्यते जर्गात हास्यं च भवति।
मञ्जूषा- ब्रूहि, सर्वेषाम्, श्रुत्वा, वर्षाभिः

Answer

Answer:
(i) श्रुत्वा
(ii) वर्षाभिः
(iii) ब्रूहि
(iv) सर्वेषाम्


रेखाकितानां पदानां स्थाने प्रश्नवाचकं पदं लिखत

(क) परं धरायाः जलं न पिबति।
(ख) सः चातकः पुरन्दरं जलं याचते।
(ग) तपनोष्णतप्तम् पर्वतकुलम आश्वास्य।
(घ) जलदः रिक्तः भवति।
(ङ) उद्दामदावविधुराणि काननानि च आश्वास्यपि जलदः रिक्तः भवति।
(च) सा एव तस्य जलदस्य उत्तमा श्रीः वर्तते।
(छ) चातक! सावधानमनसा क्षणं श्रूयताम्।
(ज) गगने बहवः अम्भोदाः सन्ति।
(झ) परं सर्वेऽपि एतादृशाः नसन्ति।
(ञ) केचिद् वृष्टिभिः वसुधाम् आद्रियन्ते।
(ट) केचिद् वृथा गर्जन्ति।
(ठ) त्वं यं यं पश्यसि।
(ड) तस्य तस्य पुस्तः दीनं वचः मा ब्रूहि।
(ढ) भवता अस्य तरोः या पुष्टिः कृता।
(ण) भृङ्गाः रसालस्य मुकुलानि समाश्रयन्ते।

Answer

Answer:
(क) कस्याः
(ख) कम्
(ग) कम्
(घ) कीदृशः
(ङ) कः
(च) का
(छ) कथम् केन
(ज) कति
(झ) के
(ञ) काभिः
(ट) कथम्
(ठ) कः
(ड) किम्
(ढ) कस्य
(ण) कस्य


निम्न वाक्येषु रेखाकितानां पदानां पर्यायं लिखत

Question 1.
एकेन राजहंसेन या शोभा सरसः भवेत्।
(i) नद्याः
(ii) सागरस्य
(iii) तडागस्य
(iv) कूपस्य

Answer

Answer: (iii) तडागस्य


Question 2.
भवता मृणालपटली भुकता।
(i) कमलस्य
(ii) फलस्य
(iii) पुष्पस्य
(iv) पादपय

Answer

Answer: (i) कमलस्य


Question 3.
निपीतानि अम्बूनि भवता।
(i) जलम्
(ii) जलानि
(iii) रसानि
(iv) फलानि

Answer

Answer: (ii) जलानि


Question 4.
भवता या अस्य तरोः पुष्टिः व्यरचि।
(i) बीजस्य
(ii) पादपस्य।
(iii) वृक्षस्य
(iv) छायायाः

Answer

Answer: (iii) वृक्षस्य


Question 5.
धारासारानपि विकिरता विश्वतो वारिदेन।
(i) देहेन
(ii) वृक्षण
(iii) जलेन
(iv) मेघेन

Answer

Answer: (iv) मेघेन


Question 6.
पतङ्गा परितः अम्बरपथम् आपेदिरे।
(i) जनाः
(ii) खगाः
(iii) पशवः
(iv) कीटाः

Answer

Answer: (ii) खगाः


Question 7.
भृङ्गा रसालमुकुलानि समाश्रयन्ते।
(i) खगाः
(ii) जनाः
(iii) पशवः
(iv) भ्रमराः

Answer

Answer: (iv) भ्रमराः


Question 8.
सङ्कोचमञ्चति सरस्त्वयि दीनदीनो।
(i) आश्रितः
(ii) निराश्रितः
(iii) आश्रयः
(iv) निराश्रयः

Answer

Answer: (ii) निराश्रितः


Question 9.
एकः एव खगः मानी वने वसति चातकः।
(i) मानयुक्तः
(ii) सम्मानम्
(iii) अभिमानी
(iv) प्रमाणी

Answer

Answer: (i) मानयुक्तः


Question 10.
रिक्तोऽसि यज्जलद! सैव तवोत्तमा श्रीः।
(i) मानम्
(ii) स्वाभिमानम्
(iii) शोभा
(iv) अभिमानम्

Answer

Answer: (iii) शोभा


निम्नपदानां विपर्ययपदानि लिखत

पदानि – विपर्ययाः
(क) मध्यवासिना – अम्बरमथम्
(ख) भुक्ता – मानी
(ग) तरोः – करुणया
(घ) धरापथम् – दीनदीनः
(ङ) तृप्तः – काननानि
(च) धरायाम् – तीरवासिना
(छ) निर्दयतया – सङ्कोचम्
(ज) जीवति (जायते) – सरः
(झ) पशवः – गगने
(ञ) अपमानम् – पीता
(ट) आश्रयः – पिपासितः
(ठ) अभिमानी – श्री.
(ड) नगराणि – पादयस्य
(ढ) सागरः – म्रियते
(ण) विस्तारम् – पतङ्गाः

Answer

Answer:
पदानि – विपर्ययाः
(क) मध्यवासिना – तीरवासिना
(ख) भुक्ता – पीता
(ग) तरोः – पादयस्य
(घ) धरापथम् – अम्बरपथम्
(ङ) तृप्तः – पिपासितः
(च) धरायाम् – गगने
(छ) निर्दयतया – करुणया
(ज) जीवति (जायते) – म्रियते
(झ) पशवः – पतङ्गाः
(ञ) अपमानम् – श्री.
(ट) आश्रयः – दीनदीनः
(ठ) अभिमानी – मानी
(ड) नगराणि – काननानि
(ढ) सागरः – सरः
(ण) विस्तारम् – सङ्कोचम्


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States of Matter Class 11 Notes Chemistry Chapter 5

By going through these CBSE Class 11 Chemistry Notes Chapter 5 States of Matter, students can recall all the concepts quickly.

States of Matter Notes Class 11 Chemistry Chapter 5

Most of the observable characteristics of chemical systems represent the bulk properties of matter. These are the properties associated with a collection of a large number of atoms, ions or molecules. For example, an individual molecule of a liquid does not boil, but the bulk boils.

Intermolecular Forces: Intermolecular forces are the forces of attraction and repulsion between interacting particles (atoms and molecules). This term does not include electrostatic forces that exist between the two oppositely charged ions and the forces that hold the atoms together in a molecule, i.e., a covalent bond.

Attractive intermolecular forces are known as van der Waals forces. They vary considerably in magnitude and include:

  1. Dispersion or London forces
  2. Dipole-dipole forces
  3. Dipole-induced-dipole forces
  4. A particularly strong type of dipole-dipole interaction is hydrogen bonding. But only a few elements (F, O, N) can participate in hydrogen bond formation.

Attractive forces between an ion and a dipole are known as ion-dipole forces and these are not van der Waals forces.

Dispersion Forces or London Forces: Atoms and non-polar molecules are electrically symmetrical and have no dipole moment because their electronic charge cloud is symmetrically distributed. But a dipole may develop momentarily even in such atoms and molecules. Suppose we have two atoms A and B close to each other [Fig. (a)]. It may so happen that momentarily electronic charge distribution in one of the atom A becomes unsymmetrical [Fig. (b) and (c)]. This results in the development of instantaneous dipole on atom A, for a very short time. This distorts the electron results a dipole is included in the atom.
States of Matter Class 11 Notes Chemistry 1
Dispersion forces of London forces between atoms

The temporary dipole of atom ‘A’ and ‘B’ attract each other. Similarly, temporary dipoles are induced in molecules also. This force of attraction was first calculated by the German physicist Fritz London. For this reason force of attraction between two temporary dipoles is known as the London forces. Another name for this force is dispersion force.

These forces are always attractive and interaction energy is inversely proportional to the sixth power of the distance between two interacting particles (i.e., \(\frac{1}{r^{6}}\) where r is the distance between two particles). These forces are important only at short distances (~ 500 pm) and the magnitude of the force depends on the polarisability of the particle. Dispersion forces are present among all particles.

Dipole-Dipole Forces:
Dipole-dipole forces act between molecules possessing permanent dipole. Ends of the dipole possess “partial charges” and these charges are shown by the Greek letter delta (5) Partial charges are always less than the unit charge (1.6 × 10-19 C) because of the electron sharing effect.

The polar molecules interact with neighbouring molecules. This interaction is weak compared to ion-ion interaction because only partial charges are involved. The interaction energy decreases with the increase of distance between the dipoles. It is proportional to \(\frac{1}{r^{6}}\) where r is the distance between polar molecules. Besides dipole-dipole interaction, polar molecules can interact by London forces also. Thus the cumulative effect is that total of intermolecular forces in polar molecules increase. Fig. shows electron cloud distribution in the dipole of hydrogen chloride.
States of Matter Class 11 Notes Chemistry 2
(a) Distribution of electron cloud in HCl a polar molecule
(b) Dipole-dipole interaction between two HCl molecules

Dipole-Induced Dipole Forces
This type of attractive forces operates between polar molecules having permanent dipole and molecules lacking permanent dipole. The permanent dipole of the polar molecule induces dipole of the electrically neutral molecule by deforming its electronic cloud.

Thus induced dipole is developed in the other molecule. In this case, also interaction energy is proportional to -4 where r is the distance between two molecules Induced dipole moment depends UpOn the dipole moment present in the permanent dipole and the polarizability of the electrically neutral molecule.
States of Matter Class 11 Notes Chemistry 3
Dipole-induced dipole interaction between a permanent dipole and induced dipole

In this case, the cumulative effect of dispersion forces and dipole- included dipole interactions exists.

Hydrogen Bond
The bond formed between the hydrogen atom of one molecule with the more electronegative atom (like N, O or F) of another molecule is called a hydrogen bond Such a molecule is highly polar. The electronegative atom of the covalent bond possesses lone pair of electrons. When two such molecules containing these type of bonds come close to each other, the hydrogen of one molecule is attracted towards the electronegative atom of the other molecule This interaction is represented by a dotted line and is called a hydrogen bond.

The energy of hydrogen bond varies between 10 to 100 kJ mol-1. This is a very significant amount of energy, therefore hydrogen bonds are a powerful force in determining the structure and properties of many compounds. The strength of the hydrogen bond is determined by the Coulomb interaction between the lone-pair electrons of the electronegative atom and the hydrogen atom. The following diagram shows the formation of the hydrogen bond.
States of Matter Class 11 Notes Chemistry 4
The intermolecular forces discussed so far are all attractive. Molecules also exert repulsive forces on one another. When two molecules are brought into close contact with each other, the repulsion between the electrons and between the nuclei in the molecules come into play. The magnitude of the repulsion rises very rapidly as the distance separating the molecules decreases. This is the reason that liquids and solids are hard to compress. In these states molecules are already in close contact, therefore they resist further compression.

→ Thermal Energy: Thermal energy is the energy of a body arising from the motion of its atoms or molecules. It is directly proportional to the temperature of the substance. It is the measure of the average kinetic energy of the particles of the matter and is thus responsible for the movement of particles. The movement of particles is called thermal motion.

Intermolecular Forces Vs Thermal Interactions
Intermolecular forces tend to keep molecules together but the thermal energy of the molecules tend to keep them apart. Three states of matter are the result of a balance between intermolecular forces and the thermal energy of the molecules.

The predominance of thermal energy and the molecular interaction energy of a substance in three states is depicted as follows:
States of Matter Class 11 Notes Chemistry 5
The Gaseous State: Only 11 elements in the periodic table exist in the form of gases under normal conditions:

Gases are classified by the following properties.

  1. Gases are the most compressible out of all the 3 states of matter.
  2. Gases exert pressure equally in all directions.
  3. Gases have a much lower density than solids and liquids.
    States of Matter Class 11 Notes Chemistry 6
    elements that exist as gases
  4. They assume the volume and shape of the container in which they are kept.
  5. Gases mix evenly, and completely without any mechanical help.

Gas Law: Boyle’s Law (Pressure-Volume Relationship)
“Volume of a given mass of a gas is inversely proportional to its pressure provided the temperature is kept constant.”
V ∝ \(\frac{1}{P}\) (mass and temperature kept constant)
or
PV = constant = k
or
P1V1 = P2V2, where P1V1 are the initial pressure and volume of the gas. P2 and V2 are the final values.

The value of k depends upon the amount of the gas, temperature of the gas, its nature and the units in which P and V are expressed.
Graphical Representation of Boyle’s Law
States of Matter Class 11 Notes Chemistry 7
(a) Graph of Pressure Vs Volume (b) Graph of pressure p Vs \(\frac{1}{V}\)

Each curve in (a) above corresponds to a different constant temperature and is known as an Isotherm
States of Matter Class 11 Notes Chemistry 8
(c) Graph of PV against P

  1. A plot of P versus V at constant temperature for a fixed mass of gas would be a rectangular hyperbola (a)
  2. A plot of P versus \(\frac{1}{v}\) at constant temperature for a fixed mass of gas would be a straight line passing through the origin (b)
  3. A plot of P versus PV at a constant temperature. In a fixed mass of a gas is a straight line parallel to the pressure axis:

Relationship between density and pressure
States of Matter Class 11 Notes Chemistry 9
Charle’s Law (Temp. Volume Relationship): The law states, “At constant pressure, the volume of a given mass of a gas increases or decreases by \(\frac{1}{273.15}\) of its volume at 0°C and 1°C rise or fall in temperature.” Thus if the volume of the gas at 0°C and at t°C is Vo and Vt. Then
States of Matter Class 11 Notes Chemistry 10
At this stage, we define a new scale of temperature such that f°C on the new scale is given by T = 273.15 + t and 0°C will be given by To = 273.15. This new temperature scale is called the Kelvin temperature scale or Absolute temperature scale. It can be represented as follows:
States of Matter Class 11 Notes Chemistry 11
Relationship between Kelvin Scale and Celsius Scale

One degree Celsius (1 °C) is equal to one Kelvin (K) in magnitude (Note that degree sign is not used while writing the temperature in absolute temperature scale, i.e. Kelvin scale). Only the position of zero has been shifted. Kelvin scale of temperature is also called the Thermodynamic scale of temperature and is used in all scientific works.

Thus we add 273 (more precisely 273.15) to Celsius temperature to obtain temperature at Kelvin scale.

A graph of volume Vs temperature at Kelvin scale will look like as shown.

If we write Tf = 273.15 + t and To = 273.15 in the equation we obtain the relationship
Vt = Vo(\(\frac{\mathrm{T}_{t}}{\mathrm{~T}_{0}}\))
⇒ \(\frac{V_{t}}{V_{0}}=\frac{T_{t}}{T_{0}}\)

Thus we can write a general equation as follows:
\(\frac{V_{2}}{V_{1}}=\frac{T_{2}}{T_{1}}\)
or
\(\frac{V}{T}\) = constant = k

Each line of V vs T graph is called Isobar
States of Matter Class 11 Notes Chemistry 12
At constant pressure for a given mass of a gas
V ∝ T
or
V = kT (where k is a constant, the value of k depends upon nature and amount of the gas)
or
\(\frac{V}{T}\) = constant

If V1 = initial volume of the gas
T1 = initial temperature (absolute)
V2 = Final volume
T2 = Final temperature .
Then \(\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}\) (mass and pressure kept constant)

Relationship between density and temperature
V ∝ T
or
\(\frac{1}{d}\) ∝ T
or
dT = constant
or
d1T1 = d2T2

Gay-Lussac’s Law (Pressure-Temperature Relationship): It states that at constant volume, the pressure of a given mass of a gas varies directly with temperature on the Kelvin scale
Mathematically P ∝ T
It is also called Amonton’s Law
or
\(\frac{P}{T}\) = constant
States of Matter Class 11 Notes Chemistry 13
Pressure Vs Temperature (K) graph (Isometrics) of a gas

Avogadro’s Law (Volume-Amount Relationship)
It states, “Equal volumes of all gases under similar conditions of temperature and pressure contain an equal number of molecules.”

Mathematically v ∝ n where n = no. of moles of the gas if T and P are constant.
n = \(\frac{m}{M}\); where n = number of moles of gas
m = mass of the gas;
M = Molar mass of the gas
States of Matter Class 11 Notes Chemistry 14
where d is the density of the gas.

Thus the density of a gas is directly proportional to its formula mass.

Avogadro’s number or Avogadro’s constant is the number of particles present in 1 mole of a substance. This number is 6.023 × 1023.

One mole of each gas will have volume = 22.4 L at STP.

A gas that follows Boyle’s Law, Charle’s and Avogadro’s law strictly is called an ideal gas. Such gas is a hypothetical gas. It is assumed that intermolecular forces are not present between the molecules of an ideal gas. Real gases follow these laws only under certain specific conditions when forces of interaction are practically negligible. In all other situations, these deviate from ideal behaviour.

Ideal Gas Equation

  1. At constant T and n, V ∝ \(\frac{1}{P}\) Boyle’s Law
  2. At constant P and n, V ∝ T Charle’s Law
  3. At constant T and P, V ∝ n Avogadro’s Law
    Thus
    States of Matter Class 11 Notes Chemistry 15
    On rearrangingPV= nRT … (1)

R is called Gas Constant. It is the same for all gases. Therefore, it is called Universal Gas Constant, equation (1) above is called Ideal Gas Equation.

The value of R for 1 Mole of an ideal gas can be calculated ai 273.15 K and 1 atm (1.013 × 105 Pascal) [Most of the real gases behave like ideal gases under these conditions) as follows.
R = \(\frac{\left(1.0325 \times 10^{5} \mathrm{~Pa}\right) \times\left(22.41383 \times 10^{-3} \mathrm{~m}^{3} / \mathrm{mol}\right)}{298.15 \mathrm{~K}}\)
= 8.31441 Pa m3 k-1 mol-1
= 8.3144 JK-1 mol-1

[For one mole V = 22.413832 for all gases at STP] For all practical purposes approximate value of R, i.e., 8.314 JK-1 mol-1 can be used.

In the equation PV = nRT

  • P and T are Intensive properties. Intensive properties are independent of the ‘quantity’ or ‘bulk’ of the substance.
  • n and V are Extensive properties. Extensive properties are dependent upon the ‘quantity’ or ‘bulk’ of the substance.

If temperature, volume and pressure of a fixed amount of the gas vary from T1, V1 and P1 to T2, V2 and P2.
Then \(\frac{\mathrm{P}_{1} \mathrm{~V}_{1}}{\mathrm{~T}_{1}}\) = nR and \(\frac{\mathrm{P}_{2} \mathrm{~V}_{2}}{\mathrm{~T}_{2}}\) = nR
or
\(\frac{P_{1} V_{1}}{T_{1}}=\frac{P_{2} V_{2}}{T_{2}}\)

It is called General Gas Equation or Combined gas law. Density and Molar Mass of a Gaseous substance
States of Matter Class 11 Notes Chemistry 16
Dalton’s Law of Partial Pressures: The law states, “Total pressure exerted by a mixture of non-reacting gases is equal to the sum of partial pressures exerted by the individual gases-all measurement being made at the same temperature.” Thus at constant temperature and volume:

PTotal = p1 + p2 + p3 + ………; PTotal = Total pressure.
p1, p2, …. are the partial pressures of the different non-reacting gases. ,

Gases are generally collected over water. The pressure of dry gas can be calculated by subtracting the vapour pressure of water from the moist gas which contains water vapours also. The pressure exerted by saturated water vapour is called aqueous tension.
Pdry gas = PTotal – Aqueous tension

Partial pressure in terms of mole fraction: Suppose three gases, enclosed in the volume V, exert partial pressure p1, p2 and p3 respectively. Then
p1 = \(\frac{n_{1} \mathrm{RT}}{\mathrm{V}}\)
p2 = \(\frac{n_{2} \mathrm{RT}}{\mathrm{V}}\)
p3 = \(\frac{n_{3} \mathrm{RT}}{\mathrm{V}}\)
where n1, n2 and n3 are number of moles of these gases. Thus expression for total pressure will be
PTotal = P1 + P2 + P3
= n1\(\frac{\mathrm{RT}}{\mathrm{V}}\) + n2\(\frac{\mathrm{RT}}{\mathrm{V}}\) + n3\(\frac{\mathrm{RT}}{\mathrm{V}}\)

= (n1 + n2 + n3)\(\frac{\mathrm{RT}}{\mathrm{V}}\)
On dividing p1 by PTotal we get
\(\frac{p_{1}}{P_{\text {Total }}}=\left(\frac{n}{n_{1}+n_{2}+n_{3}}\right) \frac{\mathrm{RTV}}{\mathrm{RTV}}=\frac{n_{1}}{n_{1}+n_{2}+n_{3}}\) = x1

x1 is called mole fraction of first gas
Thus, p1 = x1 PTotal.

Similarly, for the other two gases, we can write
P2 = x2PTotal and P3 = x3PTotal

Thus a general equation can be written as
pi = xi PTotal

where pixi, and PTotalare partial pressure and mole fraction of with gas and total pressure of the gas mixture respectively. If the total pressure of the gases is known, the equation can be used to find out the pressure exerted by the individual gas.

Molar Volume of the gas under different conditions
(a) Standard temperature and pressure (STP) conditions are 0° C or 273,15 K and one atmospheric pressure. Under these conditions, 1 mole of the gas occupies a volume of 22.413996 L = 22.4 L or 22400 mL.

When STP conditions are taken as 0°C and 1 bar pressure [as 1 bar < 1 atom and 1 bar = 0.987 atm) molar volume is slightly higher and = 22.71098 L mol-1 = 22.7 L mol-1 or 22700 mL.

→ Standard Ambient Temperature and Pressure (SATP): Conditions are also used in some scientific works. SATP conditions mean 298.15 K and 1 bar (i.e. exactly 10s Pa). At SATP (1 bar and 298.15 K), the molar volume of an ideal gas is 22.789 mol-1 or 22800 mL.

→ Graham’s Law of Effusion/Diffusion: It states, “Under similar conditions of temperature and pressure, rate of diffusion of a gas is inversely proportional to the square root of the density of a gas.”

Mathematically Rd ∝ \(\sqrt{\frac{1}{d}}\)
Rd = Rate of diffusion, d = density of the gas
Rate of diffusion Rd = R\(\sqrt{\frac{1}{d}}\)

If two gases A and B diffuse under similar conditions of temperature and pressure rate rA and rB respectively and their densities are dA and dB respectively then
rA = k\(\sqrt{\frac{1}{d_{\mathrm{A}}}}\)
rB = k\(\sqrt{\frac{1}{d_{\mathrm{B}}}}\)

On dividing rA and rB we obtain
\(\frac{r_{\mathrm{A}}}{r_{\mathrm{B}}}=\sqrt{\frac{d_{\mathrm{B}}}{d_{\mathrm{A}}}}=\sqrt{\frac{d_{\mathrm{B}} \mathrm{V}}{d_{\mathrm{A}} \mathrm{V}}}=\sqrt{\frac{\mathrm{M}_{\mathrm{B}}}{\mathrm{M}_{\mathrm{A}}}}\)
where V is the volume of gas A and gas B which undergoes diffusion and MA and MB are molecular masses of gas A and gas B respectively. Rate of diffusion should be proportional to the average speed of the molecules of a gas. If average speed of molecules of gas A and gas B are nA and nB then
\(\frac{u_{\mathrm{A}}}{u_{\mathrm{B}}}=\sqrt{\frac{\mathrm{M}_{\mathrm{B}}}{\mathrm{M}_{\mathrm{A}}}}\)

Above equation can be used to determine the molar mass of gases.

→ Student’s Note: Though Graham’s Law of Diffusion is not included in the CBSE syllabus, but students are advised to go through it for various competitive examinations.

Kinetic Molecular Theory of Gases Postulates. Assumption of Kinetic Theory of Gases
1. Every gas is made up of a large number of extremely small particles called molecules. All the molecules of a particular gas are identical in mass and size and differ, in these from gas to gas.

2. The molecules of a gas are separated from each other by large distances so that the actual volume of the molecules is negligible as compared to the total volume of the gas.

3. The distances of separation between the molecules are so large that the forces of attraction or repulsion between them are negligible.

4. The force of gravitation on the molecules is also supposed to be negligible.

5. The molecules are supposed to be moving continuously in different directions with different velocities. Hence they keep on colliding with one another (called molecular collisions) as well as on the walls of the containing vessel.

6. The pressure exerted on the walls of the containing vessel is due to the bombardment of the molecules on the walls of the containing vessel.

7. The molecules are supposed to be perfectly elastic hard spheres so that no energy is wasted when the molecules collide with one another or with the walls of the vessel. The energy may, however, be transferred from some molecules to the other on collision.

8. Since the molecules are moving with different velocities, they possess different kinetic energies. However, the average kinetic energy of the molecules of a gas is directly proportional to the absolute temperature of the gas.

The behaviour of Real Gases
Deviation from ideal gas behaviour: A gas that obeys the ideal gas equation. (PV = nRT) at all temperatures and pressure is called Ideal Gas or Perfect Gas. Actually, none of the known gases obeys the ideal gas equation under all conditions of temperature and pressure. Such gases which do not obey the gas equation are called Real Gases.

However, most of the gases follow the ideal gas equation at low pressures and high temperatures. Appreciable deviation from the ideal gas behaviour is observed at low temperature and high pressure.

The temperature at which a real gas obeys the ideal gas law over an appreciable range of pressure is called Boyle Temperature or Boyle Point. Boyle point of a gas depends upon its nature.

A gas deviates from ideal behaviour when the product of the observed pressure and volume (P × V) is lower or higher than that expected from the ideal gas equation. Thus for a gas showing deviations from ideal behaviour (PV) observed < nRT
or
(PV)observed > nRT

Thus, to describe the behaviour of real gases, the ideal gas equation should be modified. This is conveniently done by inviting the ideal gas equation ‘in’ the form PV = Z(nRT).
or
Z = \(\frac{P V}{n R T}\)
States of Matter Class 11 Notes Chemistry 17
The plot of PV Vs Pressure for real and ideal gas
States of Matter Class 11 Notes Chemistry 18
The plot of Pressure Vs Volume for real gas and ideal gas

Where Z can have a value of one, less than one or more than one. The factor Z is called Compressibility Factor.
(a) When Z = 1, then PV = nRT, i.e., the gas shows an ideal gas behaviour. For an ideal gas Z = 1 under all conditions of temperature and pressure.
(b) When Z < 1, the observed PV value is less than the value for an ideal gas. Thus the gas shows a negative deviation when Z < 1.
(c) When Z > 1, the observed PV value is higher than that for an ideal gas. So when Z > 1, the gas shows positive deviations.

Equation of state for Real Gases (Van der Waal’s equation)
The van der Waal’s equation for one mole of a real gas is written
(P + \(\frac{a}{v^{2}}\))(v-b) = RT
If n moles of a real gas is taken

The equation becomes
(P + \(\frac{a n^{2}}{v^{2}}\))(v – b) = nRT
Here ‘a’ and ‘b’ are called van der Waals parameters or constants which vary from gas to gas. Their value depends upon the gas nature.

The cause of the deviation is actually due to two faulty assumptions of the kinetic theory
They are

  • There is no force of attraction and repulsion between the molecules of a gas.
  • The volume of the molecules of a gas is negligibly small as compared to the empty space between them.

Derivation of van der Waal’s equation
1. Correction for volume: Suppose the volume occupied by the gas molecules is v. When the molecules are moving, their effective volume is four times the actual volume i.e., 4v. Let us called it b i.e. b = 4v (called excluded volume of co-volume). Thus the free volume available to the gas molecules for movement i.e.

Corrected volume = (V – b) for one mole
= (V – rib) for n moles

2. Correction for pressure. A molecule (A) lying within the vessel is attracted equally by other molecules on all sides but a molecule near the wall (B) is attracted (pulled back) by the molecules inside (Fig.) Hence it exerts less pressure. In other words, the observed pressure is less than the ideal pressure. Hence

Corrected pressure = P + p
States of Matter Class 11 Notes Chemistry 19
Backward pull on molecule B by other molecules

Evidently, the correction term p is proportional to density of the gas near the wall and the density of the gas inside i.e.
p ∝ (density)2
or
p ∝ d2
But d ∝ \(\frac{1}{V}\) for one mole
or
d ∝ \(\frac{1}{\mathrm{~V}^{2}}\) for 1 mole
or
p = \(\frac{a}{\mathrm{~V}^{2}}\)
or
p ∝ \(\frac{n^{2}}{\mathrm{~V}^{2}}\) for n moles
or
p = \(\frac{a n^{2}}{V^{2}}\)

∴ Corrected pressure = (P + \(\frac{a}{\mathrm{~V}^{2}}\)) for 1 mole
= (P + \(\frac{a n^{2}}{V^{2}}\)) for n moles
where a is constant depending upon the nature of the gas.

Substituting the correct values of volume and pressure in the ideal gas equation we get
(P + \(\frac{a}{\mathrm{~V}^{2}}\))(V – b) = RT for 1 mole
or
(P + \(\frac{a n^{2}}{V^{2}}\))(V – nb) = nRT for n moles

Significance of van der Waal’s constants
1. van der Waal’s constant ‘a’: Its value is a measure of the magnitude of the attractive forces among the molecules of the gas. The greater the value of ‘a’, the larger is the intermolecular forces of attraction.

2. van der Waal’s constant ‘b’: Its value is a measure of the effective size of the gas molecules. Its value is equal to four times the actual volume of the gas molecules. It is called excluded volume or co-volume.

Units of van der Waal’s constant
1. Units of ‘a’. As p = \(\frac{a n^{2}}{V^{2}}\)
∴ a = \(\frac{p \times V^{2}}{n^{2}}\)
= atm L2 mol2 or bar dm6 mol-2

2. Units of ‘b’. As volume correction
v = nb,
∴ b = \(\frac{v}{n}\) = K mol-1dm3mol-1.

Explanation of the behaviour of Real gases by van der Waal’s equation
1. At very low pressure, V is very large. Hence the correction term a.V2 is so small that it can also be neglected in comparison to V. Thus van der Waal’s equation reduces to the form PV = RT. This explains why at very low pressures, the real gases behave like ideal gases.

2, At moderate pressures, V decreases. Hence a/V2 increases and cannot be neglected. However, V is still large enough in comparison to ‘b’ so that ’b’ can be neglected. Thus van der Waal’s equation becomes
States of Matter Class 11 Notes Chemistry 20
Thus compressibility factor is less than 1. As pressure is increased at a constant temperature, V decreases so that the factor n/RTV increases. This explains why initially a dip in the plot of Z versus P is observed.

3. AT high pressures, V is so small that ‘b’ cannot be neglected in comparison to V. The factor a/V2 is no doubt large but as P is very high, a/V2 can be neglected in comparison to P. Thus van der Waal’s equation reduces to the form
P(V -b) = RT
or
PV = RT + Pb ⇒ \(\frac{\mathrm{PV}}{\mathrm{RT}}\) = 1 + \(\frac{\mathrm{P} b}{\mathrm{RT}}\)
or
Z = 1 + \(\frac{\mathrm{P} b}{\mathrm{RT}}\)

Thus compressibility factor is greater than 1. As P is increased (at constant T), the factor Pb/RT increases. This explains why after minima in the curves, the compressibility fact of increases continuously with pressure.

4. At high temperatures, V is very large (at a given pressure) so that both the correction factors (a/V2 and b) become negligible as in case (i). Hence at high temperature, real gases behave like an ideal gas.

→ Explanation of the exceptional behaviour of hydrogen and helium may be seen that for H2 and He, the compressibility factor Z is always greater than l and increases with the increase of pressure: This is because H2 and He being very small molecules, the intermolecular forces of attraction in them are negligible i.e., V is very very small so that a/V2 is negligible
P(V -b) = RT
or
PV = RT + Pb
or
\(\frac{\mathrm{PV}}{\mathrm{RT}}\) = 1 + \(\frac{\mathrm{PB}}{\mathrm{RT}}\)

Thus, \(\frac{\mathrm{PV}}{\mathrm{RT}}\) i.e., Z > 1 and increases with increase in the value of P at constant.
States of Matter Class 11 Notes Chemistry 21
(a) Z vs P for different gases
States of Matter Class 11 Notes Chemistry 22
(b) Z as P to N2 gas at different temperatures

Plots in Fig. (b) show that as the temperature increases, the minimum in the curve shifts upwards. Ultimately, a temperature is reached at which the value of Z remains close to 1 over an appreciable range of pressure. For example, in the case of N2 at 323 K, the value of Z remains close to 1 up to nearly 100 atmospheres.

For a real gas Z = \(\frac{p V_{\text {real }}}{n \mathrm{RT}}\) ……….(1)
If the gas shows ideal behaviour then
V ideal = \(\frac{nRT}{p}\)
On putting the value of \(\frac{nRT}{p}\) in the above equation (1)
Z = \(\frac{\mathrm{V}_{\text {real }}}{\mathrm{V}_{\text {ideal }}}\)

Thus compressibility factor may also be defined as the ratio of actual molar volume of a gas to the molar volume of it if it were ideal at that temperature and pressure.

→ Liquefaction of Gases and Critical Point: At high pressures and lower temperatures deviation from ideal behaviour for gases is observed. At high pressures, molecules of the gas come closer and attractive forces start operating. As the temperature is lowered further, the attractive forces draw the molecules together to form a ‘liquid’. This temperature is called liquefaction temperature. It depends upon the nature of the gas and its pressure.

The critical temperature for gas is that temperature above which it is not possible to liquefy it, however large is the pressure applied on it. CO2 gas remains a gas even when a pressure of 73 atmospheres is applied to it. However at this pressure when it is cooled to 30.98°C, it starts liquifying. So for CO2 30.98°C is its critical temperature. The volume of a gas at critical temperature is called its critical volume and pressure (73 atm. for CO2) is critical pressure.

Critical pressure is the pressure required to liquefy the gas at the critical temperature. All three of them are collectively called critical constants of the gas and are represented by Tc, Pc and Vc. For example, critical constants of CO2 are:
Tc = 31.1°C, Pc = 73.9 atm, Vc = 95.6 cm3 mol-1
States of Matter Class 11 Notes Chemistry 23
Isotherms of CO2 (From Andrew’s experiment)

At the lowest temperature employed i.e., 13.1°C, at low pressure. CO2 exists as a gas, as shown at point A. As the pressure is increased, the volume of the gas starts. Hence volume decreases rapidly along with BC because the liquid has much less volume than gas. At point C, liquefaction is complete. Now the increase in pressure has very little effect upon volume because liquids are very little compressible.

Hence a step curve CD is obtained. As the temperature is increased, the horizontal portion becomes smaller and smaller and at 31.1°C it is reduced at a point, P. This means that above 31.1°C, the gas cannot be liquefied at all, however, high pressure may be applied. Thus 31.1°C, is the critical temperature. The corresponding pressure to liquefy the gas at the critical temperature is its critical pressure, P (i.e., 73.9 atm). The volume occupied by 1 mole of the gas under these conditions is its critical volume, V. (i.e., 95.6 ml).

→ Liquid State: In liquids, intermolecular forces of attraction are much large than in gases. Unlike gases, liquids have a definite volume, but no definite shape. The molecules in a liquid are in constant random motion. The average kinetic energy of the molecules in a liquid is proportional to absolute temperature.

→ Vapour Pressure: Vapour pressure of a liquid at any temperature is the pressure exerted by the vapour present above the liquid in equilibrium with the liquid. The magnitude of vapour pressure depends upon the nature of, liquid and temperature. At equilibrium between the liquid and the vapour phase, the vapour pressure becomes steady or constant and at this stage, it is called Equilibrium Vapour Pressure or saturated vapour pressure.

The Boiling Point of a liquid is the temperature at which its vapour pressure becomes equal to external pressure. At 1 atm pressure boiling temperature is called the normal boiling point. If pressure is one bar, then the boiling point is called standard boiling point standard boiling point of a liquid is slightly lower than the normal boiling point (because 1 bar < 1 atm)

The normal boiling point of water is 100°C (373 K) and its standard boiling point is 99.6°C (373.6 K).

The Vapour pressure of a liquid increases with an increase in temperature, with more molecules of the liquid going into the vapour phase, the liquid becomes less dense and the density of the vapour phase increases. When the density of the liquid and vapours becomes the same the clear boundary between the liquid and the vapour disappears. This temperature is called the critical temperature of the liquid.

→ Surface Tension: The surface tension of a liquid is defined as the tangential force acting along the surface of a liquid at right angles along one unit length drew on the surface of the liquid.

It is the work done to increase the free surface area of any liquid by one unit at constant temperature and pressure.

The S.I. unit of surface tension is Nm-1. The C.G.S. unit of surface tension is dyne-1 cm-1. The lowest energy state of the liquid will be when its surface area is minimum. Spherical shape satisfies this condition. Hence raindrops or mercury drops are spherical in shape. Liquids tend to rise in the capillary due to surface tension. Surface tension decreases as the temperature is raised. It has dimensions of kg s-2. In terms of surface energy per unit area, its dimensions are Jm-2. ,

→ Viscosity: Viscosity is a measure of resistance that arise due to the internal friction between layers of fluid as they slip past one another. It is the internal resistance to the flow of liquid. The liquids which flow rapidly have low internal resistance and hence are said to be less viscous, i.e., their viscosity is low. On the other hand, the liquids which flow slowly have high internal resistance and hence are said to be more viscous, i.e., their viscosity is high The viscosity of honey or glycerol is higher than, say, water.

The coefficient of viscosity is defined as the force applied per unit area which will maintain a unit relative velocity between the two layers of a liquid at unit distance from each other. It is represented by q. Liquids having low q values are called mobile while those having high q value are termed as viscous.

If f is the force required to maintain the flow of layers, then
f ∝ A [A is the area of contact]
f ∝ \(\frac{d u}{d Z}\)
or
f = ηA\(\frac{d u}{d Z}\); η is called coefficient of viscosity.

S.I. unit of viscosity coefficient is 1 newton second per square metre [Nsm-2]

In the CGS system, its unit is poise
1 poise = 1 gm cm-1 s-1 = 10-1 kg m-1 s-1

Viscosity decreases with an increase in temperature. Hydrogen bonding and van der Waal’s forces are strong enough to cause High viscosity.

→ van der Waals forces: Attractive intermolecular forces between interacting particles (atoms and molecules) are called van der Waals forces.

→ Dispersion Force/London Force: Atoms and non-polar molecules are electrically symmetrical and hence no dipole moment. But a dipole may develop momentarily even in such atoms and molecules. This force of attraction between two temporary dipoles is called the London force or dispersion force.

→ Dipole-Dipole Forces: Dipole-dipole forces act between the molecules possessing permanent dipole. The polar molecules interact with neighbouring molecules as in the case of HCl molecules.

→ Dipole-induced Dipole Forces: This type of attractive forces operate between the polar molecules having permanent dipole and the molecules lacking permanent dipole. The permanent dipole of the polar molecule induces dipole on the electrically neutral molecule by deforming its electronic cloud Thus an induced dipole is developed in the other molecule.

→ Hydrogen Bond: It is a special case of dipole-dipole interaction It is present in molecules having H-atom attached to a small-sized highly electronegative atom like F, O, N. The highly electronegative attracts H-atom of the neighbouring molecule through electrostatic force of attraction It is a weak bond and present in molecules like I IF, FRO, R-OH etc.

→ Thermal Energy: It is the energy of a body arising due to the motion of its atoms or molecules.

→ Boyle’s Law: At constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.

→ Charles’ Law: Pressure remaining constant, the volume of a given mass of a gas is directly proportional to its absolute temperature.

→ Isotherm: Each curve obtained on plotting different values of, pressure against volume at constant temperature is called Isotherm.

→ Isobar: Each line of the volume vs temperature graph at constant j pressure is called Isobar.

→ Kelvin temperature/Absolute temperature scale. It is obtained by adding 273.15 to the temperature on the Celsius scale.
Kelvin-Tem. = T = t°C + 273.15. It is also called the Thermodynamic ’ scale.

→ Absolute zero: The volume of all gases becomes zero at – 273.15°C. The lowest hypothetical or imaginary temperature at which gases cease to exist is called absolute zero.

→ Gay-Lussac’s Law: At constant volume, the pressure of a given j mass of a gas varies directly with the pressure.

→ Isochore: Each line of the graph obtained by plotting pressure vs Kelvin temperature at constant volume is called.Isochore.

→ Avogadro’s Law: Equal volumes of all gases under the similar condition of temperature and pressure contain an equal number of molecules.

→ Avogadro’s constant: The number of molecules in one mole of a gas is – 6.022 × 1023 and the number 6.022 × 1023 is called Avogadro’s constant.

→ Ideal Gas Equation.
PV = nRT
where P = Pressure,
V = volume,
R = Universal gas constant
n = no. of moles,
T = absolute temperature

For 1 mole of an ideal gas PV = RT.

Combined gas law \(\frac{\mathrm{P}_{1} \mathrm{~V}_{1}}{\mathrm{~T}_{1}}=\frac{\mathrm{P}_{2} \mathrm{~V}_{2}}{\mathrm{~T}_{2}}\)

→ Dalton’s Law of Partial Pressures: The total pressure exerted by the mixture of non-reactive gases is equal to the sum of partial pressures exerted by individual gases under similar conditions of temperature and volume.

→ Aqueous Tension: Pressure exerted by the saturated water vapour is called Aqueous Tension. ,

→ Compressibility Factor: The deviation of a gas from ideal behaviour can be measured in terms of compressibility factor Z which is the ratio of product pV and nRT.
Z = \(\frac{pV}{nRT}\)

→ Boyle Point or Boyle Temperature: The temperature at which a real gas obeys the ideal gas law is called Boyle point/temperature.

→ Critical Temperature: The temperature above which a gas cannot be liquified, however large may be the pressure applied on it.
Or
It is a temperature below which a gas can be liquified with the application of pressure is called its critical temperature (Tc) Critical Pressure: The pressure required to liquefy a gas at its critical temperature is called its critical pressure (Pc).

→ Critical Volume: The volume possessed by gas at its critical temperature is called its critical volume (Vc).

→ Boiling Point: It is a temperature at which the vapour pressure of a liquid becomes equal to external pressure.

→ Normal Boiling Point: At 1 atmospheric pressure, the boiling temperature of a liquid is called its normal boiling point.

→ Standard Boiling Point: If the pressure is 1 bar, the boiling temperature of the liquid is called standard boiling point, the standard boiling point of a liquid is slightly lower than the normal boiling point (as 1 bar is slightly < 1 atm).

→ Surface Tension: It is defined as the force acting per unit length perpendicular to the line drawn on the surface of the liquid.

→ Unit: Surface Tension (γ-Gamma) in S.I. scale = Nm-1 V Its dimensions are kgs-2.

→ Viscosity: It is a measure of the resistance of the flow of a liquid which arises due to internal friction between layers of it as they slip past one another while liquid flows.

Important Formulae
→ Boyle’s Law: At T constant
V ∝ \(\frac{1}{P}\)
or
PV = constant
If P1, V1 are the initial pressure, the volume of a gas at constant temperature and P2, V2 are its final pressure and volume respectively.
then P1V1 = P2V2

→ Charles’ Law: At constant pressure
V ∝ T, where T is the absolute temperature
or
\(\frac{V}{T}\) = Constant
or
\(\frac{\mathrm{V}_{1}}{\mathrm{~T}_{1}}=\frac{\mathrm{V}_{2}}{\mathrm{~T}_{2}}\)
or
\(\frac{\mathrm{V}_{1}}{\mathrm{~V}_{2}}=\frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}\)
Gay Lassac’s Law : P ∝ T if volume is kept constant
or
\(\frac{P}{T}\) = constant

→ Ideal Gas Equation:
PV = nRT

→ Combined Gas Law:
\(\frac{P_{1} V_{1}}{T_{1}}=\frac{P_{2} V_{2}}{T_{2}}\)

→ Coefficient of Viscosity : If the velocity of the layer at a distance dZ is changed by a value du, then velocity gradient is given by the amount \(\frac{d u}{d Z}\). The force required lo maintain the flow of layers is proportional to the area of contact of layers and velocity gradient,
i.e., f ∝ A [A is the area of contact]
f ∝ \(\frac{d u}{d Z}\)
∴ f ∝ A\(\frac{d u}{d Z}\)
or
f = ηA\(\frac{d u}{d Z}\)

where η is proportionality constant called coefficient of viscosity.
If A = 1 \(\frac{d u}{d Z}\) = 1
then f = η
Therefore, the Coefficient of viscosity is defined as the force when the velocity gradient is unity and the area of contact is unity.

SI unit of viscosity coefficient is 1 newton sec m-2
= Ns m-2 = pascal second
1 Pa s = 1 kg m-1 s-1

In CGS system coefficient of viscosity is poise
1 poise = 1 g cm-1 s-1 = 10-1 kg m-1 s-1.

Tools For Genetic Engineering

Learninsta presents the core concepts of Biology with high-quality research papers and topical review articles.

Tools For Genetic Engineering

In order to generate recombinant DNA molecule, certain basic tools are necessary. The basic tools are enzymes, vectors and host organisms. The most important enzymes required for genetic engineering are the restriction enzymes, DNA ligase and alkaline phosphatase.

Restriction Enzymes

The two enzymes responsible for restricting the growth of bacteriophage in Escherichia coli were isolated in the year 1963. One was the enzyme which added methyl groups to DNA, while the other cut DNA. The latter was called restriction endonuclease.

A restriction enzyme or restriction endonuclease is an enzyme that cleaves DNA into fragments at or near specific recognition sites within the molecule known as restriction sites. Based on their mode of action restriction enzymes are classified into Exonucleases and Endonucleases.

  • Exonucleases are enzymes which remove nucleotides one at a time from the end of a DNA molecule. e.g. Bal 31, Exonuclease III.
  • Endonucleases are enzymes which break the internal phosphodiester bonds within a DNA molecule. e.g. Hind II, EcoRI, Pvul, BamHI, TaqI.

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Restriction endonucleases: Molecular scissors

The restriction enzymes are called as molecular scissors. These act as foundation of recombinant DNA technology. These enzymes exist in many bacteria where they function as a part of their defence mechanism called restrictionmodifiation system. There are three main classes of restriction endonucleases: Type I, Type II and Type III, which differ slightly by their mode of action.

Only type II enzyme is preferred for use in recombinant DNA technology as they recognise and cut DNA within a specific sequence typically consisting of 4-8 bp. Examples of certain enzymes are given in table 5.1.

The restriction enzyme Hind II always cut DNA molecules at a point of recognising a specific sequence of six base pairs. This sequence is known as recognition sequence. Today more than 900 restriction enzymes have been isolated from over 230 strains of bacteria with different recognition sequences. This sequence is referred to as a restriction site and is generally palindromic which means that the sequence in both DNA strands at this site read same in 5’ – 3’ direction and in the 3’ – 5’ direction

Example:
MALAYALAM: This phrase is read the same in either of the directions.
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Restriction endonucleases are named by a standard procedure. The first letter of the enzymes indicates the genus name, followed by the first two letters of the species, then comes the strain of the organism and fially a roman numeral indicating the order of discovery. For example, EcoRI is from Escherichia (E) coli (co), strain RY 13 (R) and fist endonuclease (I) to be discovered.

The exact kind of cleavage produced by a restriction enzyme is important in the design of a gene cloning experiment. Some cleave both strands of DNA through the centre resulting in blunt or flush end. These are known as symmetric cuts. Some enzymes cut in a way producing protruding and recessed ends known as sticky or cohesive end. Such cut are called staggered or asymmetric cuts.
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Two other enzymes that play an important role in recombinant DNA technology are DNA ligase and alkaline phosphatase.

DNA Ligase

DNA ligase enzyme joins the sugar and phosphate molecules of double stranded DNA (dsDNA) with 5’-PO4 and a 3’-OH in an Adenosine Triphosphate (ATP) dependent reaction. This is isolated from T4 phage.
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Alkaline Phosphatase

It is a DNA modifying enzyme and adds or removes specific phosphate group at 5’ terminus of double stranded DNA (dsDNA) or single stranded DNA (ssDNA) or RNA. Thus it prevents self ligation. This enzyme is purified from bacteria and calf intestine.
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Vectors

Another major component of a gene cloning experiment is a vector such as a plasmid. A Vector is a small DNA molecule capable of self-replication and is used as a carrier and transporter of DNA fragment which is inserted into it for cloning experiments. Vector is also called cloning vehicle or cloning DNA.

Vectors are of two types:

  • Cloning Vector, and
  • Expression Vector. Cloning vector is used for the cloning of DNA insert inside the suitable host cell. Expression vector is used to express the DNA insert for producing specifi protein inside the host.

Properties of Vectors

Vectors are able to replicate autonomously to produce multiple copies of them along with their DNA insert in the host cell.

1. It should be small in size and of low molecular weight, less than 10 Kb (kilo base pair) in size so that entry/transfer into host cell is easy.

2. Vector must contain an origin of replication so that it can independetly replicate within the host.

3. It should contain a suitable marker such as antibiotic resistance, to permit its detection in transformed host cell.

4. Vector should have unique target sites for integration with DNA insert and should have the ability to integrate with DNA insert it carries into the genome of the host cell. Most of the commonly used cloning vectors have more than one restriction site. These are Multiple Cloning Site (MCS) or polylinker. Presence of MCS facilitates the use of restriction enzyme of choice.

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The following are the features that are required to facilitate cloning into a vector.

1. Origin of replication (ori):

This is a sequence from where replication starts and piece of DNA when linked to this sequence can be made to replicate within the host cells.
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2. Selectable marker:

In addition to ori the vector requires a selectable marker, which helps in identifying and eliminating non transformants and selectively permitting the growth of the transformants.

3. Cloning sites:

In order to link the alien DNA, the vector needs to have very few, preferably single, recognition sites for the commonly used restriction enzymes.

Types of vector

Few types of vectors are discussed in detail below:
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Plasmid

Plasmids are extra chromosomal, self replicating ds circular DNA molecules, found in the bacterial cells in addition to the bacterial chromosome. Plasmids contain Genetic information for their own replication.

pBR 322 Plasmid

pBR 322 plasmid is a reconstructed plasmid and most widely used as cloning vector; it contains 4361 base pairs. In pBR, p denotes plasmid, Band R respectively the names of scientist Boliver and Rodriguez who developed this plasmid. The number 322 is the number of plasmid developed from their laboratory.

It contains ampR and tetR two different antibiotic resistance genes and recognition sites for several restriction enzymes. (Hind III, EcoRI, BamH I, Sal I, Pvu II, Pst I, Cla I), ori and antibiotic resistance genes. Rop codes for the proteins involved in the replication of the plasmid.
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Ti Plasmid Bacteria

Ti plasmid is found in Agrobacterium tumefaciens, a bacteria responsible for inducing tumours in several dicot plants. The plasmid carries transfer (tra) gene which help to transfer T – DNA from one bacterium to other bacterial or plant cell.

It has Onc gene for oncogenecity, ori gene for origin for replication and inc gene for incompatibility. T – DNA of Ti – Plasmid is stably integrated with plant DNA. Agrobacterium plasmids have been used for introduction of genes of desirable traits into plants.
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Competent Host (For Transformation with Recombinant DNA)

The propagation of the recombinant DNA molecules must occur inside a living system or host. Many types of host cells are available for gene cloning which includes E.coli, yeast, animal or plant cells. The type of host cell depends upon the cloning experiment.

E.coli is the most widely used organism as its genetic make-up has been extensively studied, it is easy to handle and grow, can accept a range of vectors and has also been studied for safety. One more important feature of E.coli to be preferred as a host cell is that under optimal
growing conditions the cells divide every 20 minutes.

Since the DNA is a hydrophilic molecule, it cannot pass through cell membranes, In order to force bacteria to take up the plasmid, the bacterial cells must first be made competent to take up DNA. This is done by treating them with a specific concentration of a divalent cation such as calcium.

Recombinant DNA can then be forced into such cells by incubating the cells with recombinant DNA on ice, followed by placing them briefl at 420C (heatshock) and then putting them back on ice. This enables bacteria to take up the Recombinant DNA.

For the expression of eukaryotic proteins, eukaryotic cells are preferred because to produce a functionally active protein it should fold properly and post translational modifiations should also occur, which is not possible by prokaryotic cell (E.coli).

Advancements In Modern Biotechnology

Learninsta presents the core concepts of Biology with high-quality research papers and topical review articles.

Advancements In Modern Biotechnology

Modern biotechnology embraces all the genetic manipulations, protoplasmic fusion techniques and the improvements made in the old biotechnological processes. Some of the major advancements in modern biotechnology are described below.

Genetic Engineering

Genetic engineering or recombinant DNA technology or gene cloning is a collective term that includes different experimental protocols resulting in the modifiation and transfer of DNA from one organism to another.

The definition for conventional recombination was already given in Unit II. Conventional recombination involves exchange or recombination of genes between homologous chromosomes during meiosis. Recombination carried out artificially using modern technology is called recombinant DNA technology (r-DNA technology). It is also known as gene manipulation technique.

This technique involves the transfer of DNA coding for a specific gene from one organism into another organism using specific agents like vectors or using instruments like electroporation, gene gun, liposome mediated, chemical mediated transfers and microinjection.

Steps involved in Recombinant DNA Technology

The steps involved in recombinant DNA technology are:

  • Isolation of a DNA fragment containing a gene of interest that needs to be cloned. This is called an insert.
  • Generation of recombinant DNA (rDNA) molecule by insertion of the DNA fragment into a carrier molecule called a vector that can self-replicate within the host cell.
  • Selection of the transformed host cells is carrying the rDNA and allowing them to multiply thereby multiplying the rDNA molecule.
  • The entire process thus generates either a large amount of rDNA or a large amount of protein expressed by the insert.
  • Wherever vectors are not involved the desired gene is multiplied by PCR technique. The multiple copies are injected into the host cell protoplast or it is shot into the host cell protoplast by shot gun method.

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Methods Of Biotechnology

Learninsta presents the core concepts of Biology with high-quality research papers and topical review articles.

Methods Of Biotechnology

Fermentation

The word fermentation is derived from the Latin verb ‘fervere’ which means ‘to boil’. Fermentation refers to the metabolic process in which organic molecules (normally glucose) are converted into acids, gases, or alcohol in the absence of oxygen or any electron transport chain.

The study of fermentation, its practical uses is called zymology and originated in 1856, when French chemist Louis Pasteur demonstrated that fermentation was caused by yeast.

Fermentation occurs in certain types of bacteria and fungi that require an oxygenfree environment to live. The processes of fermentation are valuable to the food and beverage industries, with the conversion of sugar into ethanol to produce alcoholic beverages, the release of CO2 by yeast used in the leavening of bread, and with the production of organic acids to preserve and flavour vegetables and dairy products.

Bioreactor (Fermentor)

Bioreactor (Fermentor) is a vessel or a container that is designed in such a way that it can provide an optimum environment in which microorganisms or their enzymes interact with a substrate to produce the required product. In the bioreactor aeration, agitation, temperature and pH are controlled. Fermentation involves two process namely upstream and downstream process.

(i) Upstream process

All the process before starting of the fermenter such as sterilization of the fermenter, preparation and sterilization of culture medium and growth of the suitable inoculum are called upstream process.

(ii) Downstream process

All the process after the fermentation process is known as the downstream process. This process includes distillation, centrifuging filtration and solvent extraction. Mostly this process involves the purification of the desired product.
Methods Of Biotechnology img 1

Procedure of Fermentation

  • Depending upon the type of product, bioreactor is selected.
  • A suitable substrate in liquid medicine is added at a specific temperature, pH and then diluted.
  • The organism (microbe, animal/plant cell, sub-cellular organelle or enzyme) is added to it.
  • Then it is incubated at a specific temperature for the specified time.
  • The incubation may either be aerobic or anaerobic.
  • Withdrawal of product using downstream processing methods.

Application of fermentation in industries

Fermentation has industrial application such as:

1. Microbial biomass production

Microbial cells (biomass) like algae, bacteria, yeast, fungi are grown, dried and used as source of a complete protein called ‘single cell protein (SCP)’ which serves as human food or animal feed.

2. Microbial metabolites

Microbes produce compounds that are very useful to man and animals. These compounds called metabolites, can be grouped into two categories:

a. Primary metabolites:

Metabolites produced for the maintenance of life process of microbes are known as primary metabolites Eg. Ethanol, citric, acid, lactic acid, acetic acid.

b. Secondary metabolites:

Secondary metabolites are those which are not required for the vital life process ofmicrobes, but have value added nature, this includes antibiotics e.g – Amphotericin – B (Streptomyces nodosus), Penicillin (Penicillium chryosogenum) Streptomycin (S. grises), Tetracycline (S. aureofacins), alkaloids, toxic pigments, vitamins etc.

3. Microbial enzymes

When microbes are cultured, they secrete some enzymes into the growth media. These enzymes are industrially used in detergents, food processing, brewing and pharmaceuticals. Eg. protease, amylase, isomerase, and lipase.

4. Bioconversion, biotransformation or modification of the substrate

The fermenting microbes have the capacity to produce valuable products, eg. conversion of ethanol to acetic acid (vinegar), isopropanol to acetone, sorbitol to sorbose (this is used in the manufacture of vitamin C), sterols to steroids.

Single Cell Protein (SCP)

Single cell proteins are dried cells of microorganism that are used as protein supplement in human foods or animal feeds. Single Cell Protein (SCP) offers an unconventional but plausible solution to protein deficiency faced by the entire humanity.

Although single cell protein has high nutritive value due to their higher protein, vitamin, essential amino acids and lipid content, there are doubts on whether it could replace conventional protein sources due to its high nucleic acid content and slower in digestibility. Microorganisms used for the production of Single Cell Protein are as follows:

  • Bacteria – Methylophilus methylotrophus, Cellulomonas, Alcaligenes
  • Fungi – Agaricus campestris, Saccharomyces cerevisiae (yeast), Candida utilis
  • Algae – Spirulina, Chlorella, Chlamydomonas

The single cell protein forms an important source of food because of their protein content, carbohydrates, fats, vitamins and minerals. It is used by Astronauts and Antarctica expedition scientists.

Spirulina can be grown easily on materials like waste water from potato processing plants (containing starch), straw, molasses, animal manure and even sewage, to produce large quantities and can serve as food rich in protein, minerals, fats, carbohydrate and vitamins. Such utilization also reduces environmental pollution. 250 g of Methylophilus methylotrophus, with a high rate of biomass production and growth, can
be expected to produce 25 tonnes of protein.

Applications of Single-Cell Protein

  • It is used as protein supplement
  • It is used in cosmetics products for healthy hair and skin
  • It is used as the excellent source of protein for feeding cattle, birds, fihes etc.
  • It is used in food industry as aroma carriers, vitamin carrier, emulsifying agents to improve the nutritive value of baked products, in soups, in ready-to-serve-meals, in diet recipes.
  • It is used in industries like paper processing, leather processing as foam stabilizers.