NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.2 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.2.

- Squares and Square Roots Class 8 Ex 6.1
- Squares and Square Roots Class 8 Ex 6.3
- Squares and Square Roots Class 8 Ex 6.4

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 6 |

Chapter Name |
Squares and Square Roots |

Exercise |
Ex 6.2 |

Number of Questions Solved |
2 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.2

**Question 1.**

**Find the square of the following numbers:**

**(i)** 32

**(ii)** 35

**(iii)** 86

**(iv)** 93

**(v)** 71

**(vi)** 46

**Solution.**

**(i) 32**

32 = 30 + 2

Therefore, \({ 32 }^{ 2 }\) = \({ \left( 30+2 \right) }^{ 2 }\)

= 30 (30 + 2) + 2 (30 + 2)

= 900 + 60 + 60 + 4

= 1024

**(ii) 35**

35 = 30 + 5

Therefore, \({ 35 }^{ 2 }\) = \({ \left( 30+5 \right) }^{ 2 }\)

= 30 (30 + 5) + 5 (30 + 5)

= 900 + 150 + 150 + 25

= 1225

**(iii) 86**

86 = 80 + 6

Therefore, \({ 86 }^{ 2 }\)= \({ \left( 80+6 \right) }^{ 2 }\)

= 80 (80 + 6) + 6 (80 + 6)

= 6400 + 480 + 480 + 36

= 7396

**(iv) 93**

93 = 90 + 3

Therefore, \({ 90 }^{ 2 }\)= \({ \left( 90+3\right) }^{ 2 }\)

= 90 (90 + 3) + 3 (90 + 3)

= 8100 + 270 + 270 + 9

= 8649

**(v) 71**

71 = 70 + 1

Therefore, \({ 70 }^{ 2 }\)= \({ \left( 70+1\right) }^{ 2 }\)

= 70 (70 + 1) + 1 (70 + 1)

= 4900 + 70 + 70 + 1

= 5041

**(vi) 46**

46 = 40 + 6

Therefore, \({ 40 }^{ 2 }\)= \({ \left( 40+6\right) }^{ 2 }\)

= 40 (40 + 6) + 6 (40 + 6)

= 1600 + 240 + 240 + 36

= 2116

**Question 2.**

**Write a Pythagorean triplet whose one number is**

**(i)** 6

**(ii)** 14

**(iii)** 16

**(iv)** 18

**Solution.**

**(i) 6**

Let 2m = 6

⇒ \(m=\frac { 6 }{ 2 } =3\)

**(ii) 14**

Let 2m = 14

**(iii) 16**

Let 2m = 16

**(iv) 18**

Let 2m = 18

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