RD Sharma Class 9 Solutions Chapter 9 Triangle and its Angles Ex 9.1

RD Sharma Class 9 Solutions Chapter 9 Triangle and its Angles Ex 9.1

These Solutions are part of RD Sharma Class 9 Solutions. Here we have given RD Sharma Class 9 Solutions Chapter 9 Triangle and its Angles Ex 9.1

Other Exercises

Question 1.
Define the following tenns :
(i) Line segment
(ii) Collinear points
(iii) Parallel lines  
(iv) Intersecting lines
(v) Concurrent lines   
(vi) Ray
(vii) Half-line.
Solution:
(i) A line segment is a part of a line which lies between two points on it and it is denoted as \(\overline { AB }\)   or only by AB. It has two end points and is measureable.
RD Sharma Class 9 Solutions Chapter 9 Triangle and its Angles Ex 9.1 Q1.1
(ii) Three or more points which lie on the same straight line, are called collinear points.
(iii) Two lines which do not intersect each other at any point are called parallel lines.
(iv) If two lines have one point in common, are called intersecting lines.
(v) If two or more lines which pass through a common point are called concurrent lines.
(vi) Ray : A part of a line which has one end point.
(vii) Half line : If A, B, C, be the points on a line l, such that A lies between B and C and we delete the point from line l, two parts of l that remain are each called a half-line.
RD Sharma Class 9 Solutions Chapter 9 Triangle and its Angles Ex 9.1 Q1.2

Question 2.
(i) How many lines can pass through a given point?
(ii) In how many points can two distinct lines at the most intersect?
Solution:
(i) Infinitely many lines can pass through a given point.
(ii) Two distinct lines at the most intersect at one point.

Question 3.
(i) Given two points P and Q, find how many line segments do they determine?
(ii) Name the line segments determined by the three collinear points P, Q and R.
Solution:
(i) Only one line segment can be drawn through two given points P and Q.
(ii) Three collinear points P, Q and R, three lines segments determine : \(\overline { PQ }\) , \(\overline { QR }\)  and \(\overline { PR }\) .

Question 4.
Write the truth value (T/F) of each of the following statements:
(i) Two lines intersect in a point.
(ii) Two lines may intersect in two points.
(iii) A segment has no length.
(iv) Two distinct points always determine a line.
(v) Every ray has a finite length.
(vi) A ray has one end-point only.
(vii) A segment has one end-point only.
(viii) The ray AB is same as ray BA.
(ix) Only a single line may pass through a given point.
(x) Two lines are coincident if they have only one point in common.
Solution:
(i)  False : As two lines do not intersect also any a point.
(ii) False : Two lines intersect at the most one point.
(iii) False : A line segment has definitely length.
(iv) True.
(v) False : Every ray has no definite length.
(vi) True.
(vii) False : A segment has two end point.
(viii)False : Rays AB and BA are two different rays.
(ix) False : Through a given point, infinitely many lines can pass.
(x) False : Two lines are coincident of each and every points coincide each other.

Question 5.
In the figure, name the following:
RD Sharma Class 9 Solutions Chapter 9 Triangle and its Angles Ex 9.1 Q5.1
RD Sharma Class 9 Solutions Chapter 9 Triangle and its Angles Ex 9.1 Q5.2
(i) Five line segments.
(ii) Five rays.
(iii) Four collinear points.
(iv) Two pairs of non-intersecting line segments.
Solution:
From the given figure,
(i) Five line segments are AC, PQ, PR, RS, QS.
(ii) Five rays : \(\xrightarrow { PA }\)  , \(\xrightarrow { RB }\)  , \(\xrightarrow { PB }\)  , \(\xrightarrow { CS }\)  , \(\xrightarrow { DS }\)  .
(iii) Four collinear points are : CDQS, APR, PQL, PRB.
(iv) Two pairs of non-intersecting line segments an AB and CD, AP and CD, AR and CS, PR and QS.

Question 6.
Fill in the blanks so as to make the following statements true:
(i) Two distinct points in a plane determine a _____ line.
(ii) Two distinct_____ in a plane cannot have more than one point in common.
(iii) Given a line and a point, not on the line, there is one and only _____  line which passes through the given point and is_____ to the given line.
(iv) A line separates a plane into ____ parts namely the____  and the____  itself.
Solution:
(i) Two distinct points in a plane determine a unique line.
(ii) Two distinct lines in a plane cannot have more than one point in common.
(iii) Given a line and a point, not on the line, there is one and only perpendicular line which passes through the given point and is perpendicular to the given line.
(iv) A line separates a plane into three parts namely the two half planes, and the one line itself.

 

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RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B

RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B

These Solutions are part of RS Aggarwal Solutions Class 9. Here we have given RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B.

Other Exercises

Question 1.
Solution:
Radius of the base of a cylinder (r) = 5cm.
and height (h) = 21cm
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B Q1.1

Question 2.
Solution:
Diameter of the base of the cylinder = 28cm
Radius = \(\frac { 1 }{ 2 } \) x 28 = 14 cm
Height (h) = 40cm.
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B Q2.1
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B Q2.2

Question 3.
Solution:
Radius of cylinder (r) = 10.5cm
Height (h) = 60cm.
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B Q3.1

Question 4.
Solution:
Diameter of cylinder = 20cm
Radius (r) = \(\frac { 20 }{ 2 } \) = 10cm
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 04.1

Question 5.
Solution:
Curved surface area of cylinder = 4400 cm²
Circumference of its base = 110 cm
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 05.1

Question 6.
Solution:
The ratio of the radius and height of a cylinder = 2:3
Volume =1617 cm³
Let radius = 2x
and height = 3x.
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 06.1
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 06.2

Question 7.
Solution:
Total surface area of the cylinder = 462 cm²
Curved surface area = \(\frac { 1 }{ 3 } \) x 462 = 154
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 07.1
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 07.2

Question 8.
Solution:
Total surface area of solid
cylinder = 231 cm²
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 08.1
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 08.2

Question 9.
Solution:
Sum of radius and height = 37m.
and total surface area = 1628 m²
Let r be the radius
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 09.1

Question 10.
Solution:
Total surface area = 616 cm²
Curved surface area = \(\frac { 616X1 }{ 2 } \) = 308
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 010.1
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 010.2

Question 11.
Solution:
Volume of gold = 1 cm³
diameter of wire = 0.1 mn
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 011.1

Question 12.
Solution:
Ratio in the radii of two cylinders = 2:3
and ratio in the heights = 5:3
If r1 and r2 and the radii and h1 and h2 are the heights, then
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 012.1

Question 13.
Solution:
Side of square = 12cm
and height = 17.5cm
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 013.1
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 013.2

Question 14.
Solution:
Diameter of cylindrical bucket = 28cm
Radius (r) = \(\frac { 28 }{ 8 } \) = 14cm
Height (h) = 72cm.
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 014.1

Question 15.
Solution:
Length of pipe (l) = 1m = 100cm
diameter of pipe = 3cm.
Inner radius = \(\frac { 3 }{ 2 } \) cm
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 015.1
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 015.2

Question 16.
Solution:
Internal diameter of cylindrical tube = 10.4 cm
Radius (r) = \(\frac { 10.4 }{ 2 } \) = 5.2cm.
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 016.1

Question 17.
Solution:
Length of barrel (h) = 7cm
Diameter = 5mm.
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 017.1

Question 18.
Solution:
Diameter of pencil = 7mm
.’. Radius (R) = \(\frac { 7 }{ 2 } \) mm = \(\frac { 7 }{ 20 } \) cm.
and diameter of graphite in it = 1mm
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 018.1
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 018.2
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13B 018.3

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RD Sharma Class 9 Solutions Chapter 8 Lines and Angles MCQS

RD Sharma Class 9 Solutions Chapter 8 Lines and Angles MCQS

These Solutions are part of RD Sharma Class 9 Solutions. Here we have given RD Sharma Class 9 Solutions Chapter 8 Lines and Angles MCQS

Other Exercises

Mark the correct alternative in each of the following:
Question 1.
The point of intersect of the co-ordiante axes is
(a) ordinate
(b) abscissa
(c) quadrant                 
(d) origin
Solution:
Origin    (d)

Question 2.
The abscissa and ordinate of the origin are
(a) (0, 0)
(b) (1, 0)
(c) (0, 1)                     
(d) (1, 1)
Solution:
The abscissa and ordinate of the origin are (0, 0).     (a) 

Question 3.
The measure of the angle between the co-ordinate axes is
(a) 0°                          
(b)   90°
(c) 180°                      
(d)   360°
Solution:
The measure of the angle between the coordinates of axes is 90°.     (b)

Question 4.
A point whose abscissa and ordinate are 2 and -5 respectively, lies in
(a) First quadrant
(b) Second quadrant
(c) Third  quadrant
(d) Fourth quadrant
Solution:
The point whose abscissa is 2 and ordinate -5 will lies in fourth quadrant.     (d)

Question 5.
Points (-4, 0) and (7, 0) lie
(a) on x-axis                
(b)   y-axis
(c) in first quadrant
(d) in second quadrant
Solution:
∵ 
The ordinates of both the points are 0
∴ They lie on x-axis            (a)

Question 6.
The ordinate of any point on x-axis is
(a) 0                           
(b) 1
(c) -1                          
(d) any number
Solution:
The ordinate of any point lying on x-axis is 0.          (a)

Question 7.
The abscissa of any point on y-axis is
(a) 0                           
(b) 1
(c) -1                          
(d) any number
Solution:
The abscissa of any point on y-axis is 0.          (a)

Question 8.
The abscissa of a point is positive in the
(a) First and Second quadrant
(b) Second and Third quadrant
(c) Third and Fourth quadrant
(d) Fourth and First quadrant
Solution:
The abscissa of a point is positive in the fourth and First quadrant.   (d)

Question 9.
A point whose abscissa is -3 and ordinate 2 lies in
(a) First quadrant         
(b) Second quadrant
(c) Third quadrant         
(d) Fourth quadrant
Solution:
A point (-3, 2) will lies in second quadrant.         (b)

Question 10.
Two points having same abscissae but different ordinates lie on
(a) x-axis
(b) y-axis
(c) a line parallel to y-axis
(d) a line parallel to x-axis
Solution:
Two points having same abscissae but different ordinates is a line parallel to y- axis.           (c)

Question 11.
The perpendicular distance of the point P (4, 3) from x-axis is
(a) 4                          
(b) 3
(c) 5                          
(d) none   of these
Solution:
The perpendiculat distance of the point P (4, 3) from x-axis is 3.         (b)

Question 12.
The perpendicular distance of the point P (4, 3) from y-axis is
(a) 4                          
(b) 3
(c) 5                          
(d) none of these
Solution:
perpendicular distance of the point P (4, 3) from y-axis is 4.         (a)

Question 13.
The distance of the point P (4, 3) from the origin is
(a) 4                          
(b) 3
(c) 5     
(d) 7
Solution:
The distance of the point P (4, 3) from origin is \(\sqrt { { 4 }^{ 2 }+{ 3 }^{ 3 } }\)
= \(\sqrt { 16+9 }\)
= \(\sqrt { 25 }\)   = 5        (c) 

Question 14.
The area of the triangle formed by the points A (2, 0), B (6, 0) and C (4, 6) is
(a) 24 sq. units
(b) 12 sq. units
(c) 10 sq. units            
(d) none of these
Solution:
RD Sharma Class 9 Solutions Chapter 8 Lines and Angles MCQS Q14.1

Question 15.
The area of the triangle formed by the points P (0, 1), Q (0, 5) and R (3, 4) is
(a) 16 sq. units
(b) 8 sq. units
(c) 4 sq. units             
(d) 6 sq. units
Solution:
RD Sharma Class 9 Solutions Chapter 8 Lines and Angles MCQS Q15.1

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RD Sharma Class 9 Solutions Chapter 8 Lines and Angles Ex 8.1

RD Sharma Class 9 Solutions Chapter 8 Lines and Angles Ex 8.1

These Solutions are part of RD Sharma Class 9 Solutions. Here we have given RD Sharma Class 9 Solutions Chapter 8 Lines and Angles Ex 8.1

Other Exercises

Question 1.
Plot the following points on the graph paper:
(i)  (2, 5)                    
(ii) (4, -3)
(iii) (-5, -7)                  
(iv) (7, -4)
(v) (-3, 2)        
(vi) (7, 0)
(vii) (-4, 0)               
(viii) (0, 7)
(ix) (0, -4)                    
(x) (0, 0)
Solution:
The given points have been plotted on the graph as given below:
RD Sharma Class 9 Solutions Chapter 8 Lines and Angles Ex 8.1 Q1.1

Question 2.
Write the coordinates of each of the following points marked in the graph paper.
RD Sharma Class 9 Solutions Chapter 8 Lines and Angles Ex 8.1 Q2.1
Solution:
The co-ordinates of the points given in the graph are A (3, 1), B (6, 0), C (0, 6), D (-3, 0), E (-4, 3), F (-2, -4), G (0, -5), H (3, -6), P (7, -3).

 

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RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A

RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A

These Solutions are part of RS Aggarwal Solutions Class 9. Here we have given RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A.

Other Exercises

Question 1.
Solution:
(i) Length of cuboid (l) = 12cm
Breadth (b) = 8cm
and height (h) = 4.5cm
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q1.1
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q1.2
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q1.3
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q1.4

Question 2.
Solution:
Length of closed rectangular cistern (l) = 8m
breadth (b) = 6m
and depth (b) = 2.5m.
(i) .’. Volume of cistern = l.b.h.
= 8 x 6 x 2.5 m³ = 120m³
(ii) Total surface area = 2(lb + bh + hl)
= 2(8 x 6 + 6 x 2.5 + 2.5 x 8) cm²
= 2(48 + 15 + 20)
= 2 x 83 m²
= 166 m² Ans.

Question 3.
Solution:
Length of room (l) = 9m
Breadth (b) = 8m
and height (h) = 6.5m
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q3.1

Question 4.
Solution:
Length of pit (l) = 20m
Breadth (b) = 6m
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q4.1

Question 5.
Solution:
Length of wall (l) = 8m.
Width (b) = 22.5 cm = \(\frac { 225 }{ 10X100 } =\frac { 9 }{ 40 } m\)
and height (h) = 6m.
Volume of wall = l.b.h.
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q5.1

Question 6.
Solution:
Length of wall (l) = 15m.
Width (b) = 30cm = \(\frac { 30 }{ 100 } =\frac { 3 }{ 10 } m\)
Height (h) = 4m
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q6.1
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q6.2

Question 7.
Solution:
Outer length of opened cistern = 1.35m = 135 cm
Breadth = 1.08 m = 108 cm
Depth = 90cm
Thickness of iron = 2.5cm.
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q7.1

Question 8.
Solution:
Depth of river = 2m
width = 45m.
Length of current in 60 minutes = 3km
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q8.1

Question 9.
Solution:
Total cost of box = Rs. 1620
Rate per sq. m = Rs. 30

RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q8.2
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q8.3

Question 10.
Solution:
Length of room (l) = 10m
Breadth (b) = 10m
Height (h) = 5m
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q10.1

Question 11.
Solution:
Length of hall (l) = 20m
Breadth (b) = 16m
and height (h) = 4.5m.
Volume of the air inside the hall
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q11.1

Question 12.
Solution:
Length of class room (l) = 10m
Width (b) = 6.4 m
Height (h) = 5m.
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q12.1

Question 13.
Solution:
Volume of cuboid = 1536 m³
Length (l) = 16m
Ratio in breadth and height = 3:2
Let breadth (b) = 3x
their height (h) = 2x
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q13.1

Question 14.
Solution:
Length of cuboid (l) = 14 cm
Breadth (b) = 11 cm .
Let height (h) =x cm
Surface area = 2(lb + bh + hl)
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q14.1

Question 15.
Solution:
(a) Edge of cube (a) = 9m .
(i) volume = a³ = (9)³ m³ = 729 m³
(ii) Lateral surface area = 4a²
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q15.1
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q15.2

Question 16.
Solution:
Total surface area of a cube = 1176 cm²
Let each edge he ‘a’
then 6a² =1176
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q1.16.1

Question 17.
Solution:
Lateral surface area of a cube = 900 cm²
Let ‘a’ be the edge of the cube
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q17.1

Question 18.
Solution:
Volume of a cube = 512 cm³
Let ‘a’ be its edge, then
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q18.1

Question 19.
Solution:
Edge of first-cube = 3 cm.
Volume = (3)³ = 27 cm³
RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A Q19.1

Question 20.
Solution:
Area of ground = 2 hectares
= 2 x 10000 = 20000 m²
Height of rain falls 5cm = \(\frac { 5 }{ 100 } \)m
∴ Volume of rain water = 20000 x \(\frac { 5 }{ 100 } \) m³
= 1000 m³ Ans.

Hope given RS Aggarwal Class 9 Solutions Chapter 13 Volume and Surface Area Ex 13A are helpful to complete your math homework.

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