RS Aggarwal Class 8 Solutions Chapter 3 Squares and Square Roots Ex 3G

RS Aggarwal Class 8 Solutions Chapter 3 Squares and Square Roots Ex 3G

These Solutions are part of RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 3 Squares and Square Roots Ex 3G.

Other Exercises

Evaluate:

Question 1.
Solution:
\(\sqrt { \frac { 16 }{ 81 } } \)
= \(\frac { \sqrt { 16 } }{ \sqrt { 81 } } \)
= \(\sqrt { \frac { 4X4 }{ 9X9 } } \)
= \(\\ \frac { 4 }{ 9 } \)

Worksheets for Class 8 Maths

Question 2.
Solution:
\(\sqrt { \frac { 64 }{ 225 } } \)
= \(\frac { \sqrt { 64 } }{ \sqrt { 225 } } \)
= \(\sqrt { \frac { 8X8 }{ 15X15 } } \)
= \(\\ \frac { 8 }{ 15 } \)

Question 3.
Solution:
\(\sqrt { \frac { 121 }{ 256 } } \)
= \(\frac { \sqrt { 121 } }{ \sqrt { 256 } } \)
= \(\sqrt { \frac { 11X11 }{ 16X16 } } \)
= \(\\ \frac { 11 }{ 16 } \)

Question 4.
Solution:
\(\sqrt { \frac { 625 }{ 729 } } \)
RS Aggarwal Class 8 Solutions Chapter 3 Squares and Square Roots Ex 3G Q4.1

Question 5.
Solution:
\(\sqrt { 3\frac { 13 }{ 36 } } \)
= \(\sqrt { \frac { 3X36+13 }{ 36 } } \)
= \(\sqrt { \frac { 108+13 }{ 36 } } \)
= \(\sqrt { \frac { 121 }{ 36 } } \)
= \(\sqrt { \frac { 11X11 }{ 6X6 } } \)
= \(\\ \frac { 11 }{ 6 } \)

Question 6.
Solution:
\(\sqrt { 4\frac { 73 }{ 324 } } \)
= \(\sqrt { \frac { 4X324+73 }{ 324 } } \)
= \(\sqrt { \frac { 1296+73 }{ 324 } } \)
= \(\sqrt { \frac { 1369 }{ 324 } } \)
RS Aggarwal Class 8 Solutions Chapter 3 Squares and Square Roots Ex 3G Q6.1

Question 7.
Solution:
\(\sqrt { 3\frac { 33 }{ 289 } } \)
= \(\sqrt { \frac { 3X289+33 }{ 289 } } \)
= \(\sqrt { \frac { 867+33 }{ 289 } } \)
= \(\sqrt { \frac { 900 }{ 289 } } \)
RS Aggarwal Class 8 Solutions Chapter 3 Squares and Square Roots Ex 3G Q7.1

Question 8.
Solution:
\(\frac { \sqrt { 80 } }{ \sqrt { 405 } } \)
= \(\sqrt { \frac { 80 }{ 405 } } \)
= \(\sqrt { \frac { 16 }{ 81 } } \)
= \(\frac { \sqrt { 16 } }{ \sqrt { 81 } } \)
= \(\\ \frac { 4 }{ 9 } \)

Question 9.
Solution:
\(\frac { \sqrt { 1183 } }{ \sqrt { 2023 } } \)
= \(\sqrt { \frac { 1183 }{ 2023 } } \)
= \(\sqrt { \frac { 1183\div 7 }{ 2023\div 7 } } \)
= \(\frac { \sqrt { 169 } }{ \sqrt { 289 } } \)
= \(\frac { \sqrt { 13X13 } }{ \sqrt { 17X17 } } \)
= \(\\ \frac { 13 }{ 17 } \)

Question 10.
Solution:
\(\sqrt { 95 } \times \sqrt { 162 } \)
= \(\sqrt { 98\times 162 }\)
= \(\sqrt { 2\times 7\times 7\times 2\times 3\times 3\times 3\times 3 } \)
RS Aggarwal Class 8 Solutions Chapter 3 Squares and Square Roots Ex 3G Q10.1

Hope given RS Aggarwal Solutions Class 8 Chapter 3 Squares and Square Roots Ex 3G are helpful to complete your math homework.

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