RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2A

NCERT Maths Solutions for Ex 2.1 class 10 Polynomials is the perfect guide to boost up your preparation during CBSE 10th Class Maths Examination.

RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2A

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Class 10 Solutions Chapter 2 Polynomials Ex 2A

Other Exercises

• RS Aggarwal Solutions Class 10 Chapter 2 Polynomials Ex 2A
• RS Aggarwal Solutions Class 10 Chapter 2 Polynomials Ex 2B
• RS Aggarwal Solutions Class 10 Chapter 2 Polynomials Ex 2C
• RS Aggarwal Solutions Class 10 Chapter 2 Polynomials MCQS
• RS Aggarwal Solutions Class 10 Chapter 2 Polynomials Test Yourself

Find the zeros of the following quadratic polynomials and verify the relationship between the zeros and the coefficients:
Question 1.
Solution:

Question 2.
Solution:
x² – 2x – 8
Let f(x) = x² – 2x – 8

Question 3.
Solution:

Question 4.
Solution:
4x² – 4x – 3

Question 5.
Solution:

Question 6.
Solution:

Question 7.
Solution:

Question 8.
Solution:

Question 9.
Solution:

Question 10.
Solution:

Question 11.
Solution:

Question 12.
Solution:

Question 13.
Solution:
Zeros of a quadratic polynomial are 2, -6

Question 14.
Solution:

Question 15.
Solution:
Sum of zeros = 8
Product of zeros = 12
Quadratic equation will be x² – (Sum of zeros) x + Product of zeros = 0
=> x² – 8x + 12 = 0
=> x² – 6x – 2x + 12 = 0
=> x (x – 6) – 2 (x – 6) = 0
=> (x – 6) (x – 2) = 0
Either x – 6 = 0, then x = 6
or x – 2 = 0, then x = 2
Zeros are 6, 2
and quadratic polynomial is x² – 8x + 12

Question 16.
Solution:
Sum of zeros = 0
and product of zeros = -1
Quadratic equation will be
x² – (Sum of zeros) x + Product of zeros = 0
=> x² – 0x – 1 = 0
=> x² – 1= 0
(x + 1)(x – 1) = 0
Either x + 1 = 0, then x = -1 or x – 1 =0, then x = 1
Zeros are 1, -1
and quadratic polynomial is x² – 1

Question 17.
Solution:
Sum of zeros = \(\frac { 5 }{ 2 }\)
Product of zeros = 1
Quadratic equation will be
x² – (Sum of zeros) x + Product of zeros = 0

and quadratic polynomial is 2x² – 5x + 2

Question 18.
Solution:

Question 19.
Solution:

Question 20.
Solution:

Question 21.
Solution:
One zero of the given polynomial is \(\frac { 2 }{ 3 }\)

=> (x + 3) (x + 3) = 0
x = -3, -3
Hence, other zeros are -3, -3

Hope given RS Aggarwal Solutions Class 10 Chapter 2 Polynomials Ex 2A are helpful to complete your math homework.

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