MCQ Questions for Class 7 Maths Chapter 3 Data Handling with Answers

MCQ Questions for Class 7 Maths Chapter 3 Data Handling with Answers

Check the below NCERT MCQ Questions for Class 7 Maths Chapter 3 Data Handling with Answers Pdf free download. MCQ Questions for Class 7 Maths with Answers were prepared based on the latest exam pattern. We have provided Data Handling Class 7 Maths MCQs Questions with Answers to help students understand the concept very well. https://mcqquestions.guru/mcq-questions-for-class-7-maths-chapter-3/

Students can also refer to NCERT Solutions for Class 7 Maths Chapter 3 Data Handling for better exam preparation and score more marks.

Data Handling Class 7 MCQs Questions with Answers

The number of tourists visiting a historical place in a week is shown in the following table :
Data Handling Class 7 MCQ
Answer the following related questions.

Data Handling Class 7 MCQ Question 1.
On which day is the number of tourists maximum?
(a) Sunday
(b) Wednesday
(c) Tuesday
(d) Saturday

Answer

Answer: (a) Sunday
Hint:
Sunday → 160.


Class 7 Maths Chapter 3 MCQ Question 2.
On which day is the number of tourists minimum?
(a) Friday
(b) Monday
(c) Thursday
(d) Saturday

Answer

Answer: (a) Friday
Hint:
Friday → 60.


MCQ On Data Handling For Class 7 Question 3.
On which day 60 tourists visit?
(a) Monday
(b) Tuesday
(c) Friday
(d) Sunday

Answer

Answer: (c) Friday
Hint:
60 → Friday.


MCQ Questions For Class 7 Maths Chapter 3 Question 4.
What is the difference between the number of tourists visiting on Friday and Monday?
(a) 10
(b) 24
(c) 38
(d) 5

Answer

Answer: (d) 5
Hint:
65 – 60 = 5.


Class 7 Maths Chapter 3 MCQ With Answers Question 5.
The sum of the number of tourists visiting on Sunday and Friday is
(a) 160
(b) 60
(c) 220
(d) 100

Answer

Answer: (c) 220
Hint:
160 + 60 = 220.


Data Handling MCQ Class 7 Question 6.
The difference between the maximum and minimum number of tourists is
(a) 50
(b) 80
(c) 90
(d) 100

Answer

Answer: (d) 100
Hint:
160 – 60 = 100.


Class 7 Math Chapter 3 MCQ Question 7.
A batsman scored the following number of runs in six innings:
35, 30, 45, 65, 39, 20
The mean runs scored by him in an inning is
(a) 39
(b) 38
(c) 37
(d) 40

Answer

Answer: (a) 39
Hint:
Mean = \(\frac { 35+30+45+65+39+20 }{ 6 } \)
= \(\frac { 234 }{ 6 } \) = 39


Class 7 Maths Ch 3 MCQ Question 8.
The mean of the numbers 10,20, 30 and 40 is
(a) 20
(b) 25
(c) 30
(d) 50

Answer

Answer: (b) 25
Hint:
Mean = \(\frac { 10+20+30+40 }{ 4 } \) = \(\frac { 100 }{ 4 } \) = 25.


MCQ Class 7 Maths Chapter 3 Question 9.
The range of the weights (in kg) of a students of a class given below is:
49, 60, 47, 50, 47, 59, 58, 45, 53
(a) 10
(b) 15
(c) 20
(d) 2

Answer

Answer: (b) 15
Hint:
Range = 60 – 45 = 15.


Class 7 Data Handling MCQ Question 10.
The marks of 11 students of a class are as given below:
78, 11, 99, 63, 94, 6, 78, 36, 30, 55, 22
The range of marks is
(a) 90
(b) 91
(c) 92
(d) 93

Answer

Answer: (d) 93
Hint:
Range = 99 – 6 = 93.


Ncert Class 7 Maths Chapter 3 MCQ Question 11.
The rainfall (in mm) in a city on 7 days of a certain week was recorded as follows:
Ncert Class 7 Maths Chapter 3 MCQ
On how many days was the rainfall less than 6 mm?
(a) 0
(b) 3
(c) 6
(d) 7

Answer

Answer: (d) 7
Hint:
On each day,rainfall < 6 mm.


Class 7th Maths Chapter 3 MCQ Question 12.
The mode of the distribution 3,5, 7, 4, 2, 1, 4, 3, 4 is
(a) 7
(b) 4
(c) 3
(d) 1

Answer

Answer: (b) 4
Hint:
4 occurs maximum number (3) times.


MCQ Questions For Class 7 Maths Data Handling Question 13.
The marks of some students are as given below:
30, 31, 32, 32, 33, 32, 34, 35, 30, 31, 33, 32
Find the mode of their marks.
(a) 30
(b) 31
(c) 32
(d) 33

Answer

Answer: (c) 32
Hint:
32 occurs maximum number (4) times.


Class 7 Chapter 3 Maths MCQ Question 14.
The median of the distribution 2, 3, 4, 7, 5, 1, 6 is
(a) 1
(b) 2
(c) 3
(d) 4

Answer

Answer: (d) 4
Hint:
1, 2, 3, 4, 5, 6, 7.


Class 7 Maths MCQ Chapter 3 Question 15.
The median of the data 20, 30, 40, 10, 15, 25, 35 is
(a) 20
(b) 25
(c) 30
(d) 40

Answer

Answer: (b) 25
Hint:
10, 15, 20, 25, 30, 35, 40.


Question 16.
Which of the following statements is true?
(a) The mode is always one of the numbers in a data
(b) The mean is always one of the numbers in a data
(c) Mean < Mode in a data
(d) Median < Mode in a data

Answer

Answer: (a) The mode is always one of the numbers in a data


Question 17.
A coin is tossed. What is the probability of getting head?
(a) 0
(b) 1
(c) \(\frac { 1 }{ 2 } \)
(d) 2

Answer

Answer: (c) \(\frac { 1 }{ 2 } \)
Hint:
A coin has two faces.


Question 18.
A coin is tossed. What is the probability of getting tail?
(a) 1
(b) \(\frac { 1 }{ 2 } \)
(c) 2
(d) 0

Answer

Answer: (b) \(\frac { 1 }{ 2 } \)
Hint:
A coin has two faces.


Question 19.
A die is thrown. What is the probability of getting 1?
(a) 0
(b) 1
(c) \(\frac { 1 }{ 2 } \)
(d) \(\frac { 1 }{ 6 } \)

Answer

Answer: (d) \(\frac { 1 }{ 6 } \)
Hint:
A die has six faces.


Question 20.
A die is thrown. What is the probability of getting 6?
(a) 0
(b) \(\frac { 1 }{ 6 } \)
(c) \(\frac { 1 }{ 2 } \)
(d) 1

Answer

Answer: (b) \(\frac { 1 }{ 6 } \)
Hint:
A die has six faces.


Read the following bar graph and answer the following related questions :
Class 7 Chapter 3 Maths MCQ

Question 21.
Who got the maximum marks?
(a) Apala
(b) Meenu
(c) Saroj
(d) Indu

Answer

Answer: (a) Apala
Hint:
Apala → 600.


Question 22.
Who got the minimum marks?
(a) Apala
(b) Meenu
(c) Vimla
(d) Indu

Answer

Answer: (b) Meenu
Hint:
Meenu → 100.


Question 23.
The difference between maximum and minimum marks is
(a) 100
(d) 200
(c) 400
(d) 500

Answer

Answer: (d) 500
Hint:
600 – 100 = 500.


Question 24.
The ratio between the marks obtained by Saroj and Vimla is
(a) 1 : 2
(b) 2 : 3
(c) 3 : 4
(d) 1 : 6

Answer

Answer: (a) 1 : 2
Hint:
200 : 400 = 1 : 2.


Question 25.
How many girls have got marks more than 100?
(a) 2
(b) 3
(c) 4
(d) 1

Answer

Answer: (c) 4
Hint:
200, 300, 400, 500 → 4.


Question 26.
Who has got 400 marks?
(a) Vimla
(b) Saroj
(c) Indu
(d) Apala

Answer

Answer: (a) vimla
Hint:
400 → Vimla.


Question 27.
The difference between the marks obtained by Vimla and Saroj is how many times the difference between the marks obtained by Meenu and Saroj?
(a) 2
(b) 3
(c) 4
(d) 6

Answer

Answer: (a) 2
Hint:
400 – 200 = 200; 200 – 100 = 100; 200 = 2 x 100.


Question 28.
How many girls have got marks less than 600?
(a) 1
(b) 2
(c) 3
(d) 4

Answer

Answer: (d) 4
Hint:
100, 200, 300, 400 → 4.


Sale of Mathematics and English books in the year 2005, 2006, 2007 and 2008 are given below :
Class 7 Data Handling MCQ
Answer the following related questions :

Question 29.
In which year is the difference in the sale minimum?
(a) 2008
(b) 2007
(c) 2006
(d) 2005

Answer

Answer: (a) 2008
Hint:
2008 → 500 – 500 = 0.


Question 30.
In which year is the difference in the sale maximum?
(a)2005
(b) 2006
(c) 2007
(d) 2008

Answer

Answer: (c) 2007
Hint:
400 – 200 = 200.


Question 31.
The ratio of sales in the year 2005 is
(a) 2 : 1
(b) 3 : 1
(c) 4 : 1
(d) 2 : 3

Answer

Answer: (a) 2 : 1
Hint:
200 : 100 = 2 : 1.


Question 32.
The rise in the sale of Mathematics books from 2005 to 2008 is
(a) 100
(b) 200
(c) 300
(d) 400

Answer

Answer: (c) 300
Hint:
500 – 200 = 300.


Question 33.
The fall in the sale of English books from 2006 to 2007 is
(a) 50
(b) 100
(c) 150
(d) 200

Answer

Answer: (a) 50
Hint:
250 – 200 = 50.


Number of children in six different classes are given below :
MCQ Questions for Class 7 Maths Chapter 3 Data Handling with Answers 5
Answer the following related questions.

Question 34.
In which class is the number of children maximum?
(a) 6
(b) 7
(c) 8
(d) 9

Answer

Answer: (a) 6
Hint:
6 → 400.


Question 35.
In which class is the number of children minimum?
(a) 8
(b) 9
(c) 10
(d) 11

Answer

Answer: (d) 11
Hint:
11 → 200.


Question 36.
The difference between the maximum and minimum number of children is
(a) 100
(b) 200
(c) 300
(d) 400

Answer

Answer: (b) 200
Hint:
400 – 200 = 200.


Question 37.
In how many classes is the number of children less than 500?
(a) 2
(b) 4
(c) 5
(d) 6

Answer

Answer: (d) 6
Hint:
In each class, number of students < 500.


Question 38.
In how many classes is the number of children more than 100?
(a) 6
(b) 4
(c) 3
(d) 1

Answer

Answer: (a) 6
Hint:
In each class, number of students > 100.


Question 39.
The ratio of the number of children of class 6 and 11 is
(a) 3 : 1
(b) 2 : 1
(c) 2 : 3
(d) 1 : 4

Answer

Answer: (b) 2 : 1
Hint:
400 : 200 = 2 : 1.


Question 40.
The total number of children is
(a) 1775
(b) 1675
(c) 1575
(d) 1785

Answer

Answer: (a) 1775
Hint:
400 + 350 + 320 + 280 + 225 + 200 = 1775.


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MCQ Questions for Class 7 Maths Chapter 4 Simple Equations with Answers

MCQ Questions for Class 7 Maths Chapter 4 Simple Equations with Answers

Check the below NCERT MCQ Questions for Class 7 Maths Chapter 4 Simple Equations with Answers Pdf free download. MCQ Questions for Class 7 Maths with Answers were prepared based on the latest exam pattern. We have provided Simple Equations Class 7 Maths MCQs Questions with Answers to help students understand the concept very well. https://mcqquestions.guru/mcq-questions-for-class-7-maths-chapter-4/

Students can also refer to NCERT Solutions for Class 7 Maths Chapter 1 Simple Equations for better exam preparation and score more marks.

Simple Equations Class 7 MCQs Questions with Answers

Simple Equations Class 7 MCQ Question 1.
Write the following statement in the form of an equation:
The sum of three times x and 10 is 13.
(a) 3x + 10 = 13
(b) 3x – 10 = 13
(c) 3x + 13 = 10
(d) none of these

Answer

Answer: (a) 3x + 10 = 13


Class 7 Maths Chapter 4 MCQ Question 2.
Write the following statement in the form of an equation:
If you subtract 3 from 6 times a number, you get 9
(a) 3x – 6 = 9
(b) 6x – 3 = 9
(c) 6x + 3 = 9
(d) 3x + 6 = 9

Answer

Answer: (b) 6x – 3 = 9


MCQ Questions For Class 7 Maths Chapter 4 Question 3.
Write the following statement in the form of an equation:
One fourth of n is 3 more than 2
(a) \(\frac { n }{ 4 } \) – 2 = 3
(b) \(\frac { n }{ 4 } \) + 2 = 3
(c) \(\frac { n }{ 2 } \) – 4 = 3
(d) \(\frac { n }{ 2 } \) + 4 = 3

Answer

Answer: (a) \(\frac { n }{ 4 } \) – 2 = 3


MCQ On Simple Equations For Class 7 Question 4.
Write the following statement in the form of an equation:
One third of a number plus 2 is 3
(a) \(\frac { m }{ 3 } \) – 2 = 3
(b) \(\frac { m }{ 3 } \) + 2 = 3
(c) \(\frac { m }{ 2 } \) – 3 = 3
(d) \(\frac { m }{ 2 } \) + 3 = 3

Answer

Answer: (b) \(\frac { m }{ 3 } \) + 2 = 3


Class 7 Maths Chapter 4 MCQ With Answers Question 5.
Write the following statement in the form of an equation:
Taking away 5 from x gives 10
(a) x – 5 = 10
(b) x + 5 = 10
(c) x – 10 – 5
(d) none of these

Answer

Answer: (a) x – 5 = 10


Class 7 Maths Ch 4 MCQ Question 6.
Write the following statement in the form of an equation:
Four times a number p is 8.
(a) 4P = 8
(b) P + 4 = 8
(c) p – 4 = 8
(d) p ÷ 4 = 8

Answer

Answer: (a) 4P = 8


Class 7 Math Chapter 4 MCQ Question 7.
Write the following statement in the form of an equation:
Add 1 to three times n to get 7
(a) 3n + 1 = 7
(b) 3n – 1 = 7
(c) 3n + 7 = 1
(d) none of these

Answer

Answer: (a) 3n + 1 = 7


Simple Equations MCQ Class 7 Question 8.
Write the following statement in the form of an equation:
The number b divided by 6 gives 5.
(a) \(\frac { b }{ 6 } \) = 5
(b) b – 5 = 6
(c) 5b = 6
(d) b + 5 = 6

Answer

Answer: (a) \(\frac { b }{ 6 } \) = 5


Class 7 Simple Equations MCQ Question 9.
The solution of the equation x + 3 = 0 is
(a) 3
(b) -3
(c) 0
(d) 1

Answer

Answer: (b) -3
Hint:
x + 3 = 0 ⇒ x = -3.


MCQ Questions On Simple Equations For Class 7 Question 10.
The solution of the equation x – 6 = 1 is
(a) 1
(b) 6
(c) -7
(b) 7

Answer

Answer: (d) 7
Hint:
x – 6 = 1 ⇒ x = 1 + 6 = 7.


Class 7th Maths Chapter 4 MCQ Question 11.
The solution of the equation 5x = 10 is
(a) 1
(b) 2
(c) 5
(d) 10

Answer

Answer: (b) 2
Hint:
5x = 10 ⇒ x = \(\frac{10}{5}\) = 2


MCQ Questions For Class 7 Maths Simple Equations Question 12.
The solution of the equation \(\frac { m }{ 2 } \) = 3 is
(a) 2
(b) 3
(c) 12
(d) 6

Answer

Answer: (d) 6
Hint:
\(\frac{m}{2}\) = 3 ⇒ m = 3 × 2 = 6.


Class 7 Maths Chapter 4 MCQ Online Test Question 13.
The solution of the equation 7n + 5 = 12 is
(a) 0
(b) – 1
(c) 1
(d) 5

Answer

Answer: (c) 1
Hint:
7n + 5 = 12 ⇒ 7n = 12 – 5
⇒ 7n = 1 ⇒ n = \(\frac{7}{7}\) = 1.


Class 7 Chapter 4 Maths MCQ Question 14.
The solution of the equation 4p – 3 = 9 is
(a) 1
(b) 2
(c) 3
(d) 4

Answer

Answer: (c) 3
Hint:
4p – 3 = 9 ⇒ 4p = 9 + 3 = 12
⇒ p = \(\frac{12}{4}\) = 3.


MCQ Class 7 Maths Chapter 4 Question 15.
The solution of the equation 5p + 2 = 7 is
(a) 0
(b) 1
(c) -1
(d) 2

Answer

Answer: (b) 1
Hint:
5p + 2 = 71 ⇒ 5p = 7 – 2 = 5
⇒ p = \(\frac{5}{5}\) = 1.


Question 16.
The solution of the equation 3p – 2 = 4 is
(a) 0
(b) 1
(c) 2
(d) 3

Answer

Answer: (c) 2
Hint:
3p – 2 = 4 ⇒ 3p = 4 + 2 = 6
⇒ P = \(\frac{6}{3}\) = 2


Question 17.
The solution of the equation p + 4 = 4 is
(a) 0
(b) 4
(c) -4
(d) 8

Answer

Answer: (a) 0
Hint:
p + 4 = 4 ⇒ P = 4 – 4 = 0.


Question 18.
The solution of the equation m – 1 = 2 is
(a) 1
(b) 2
(c) 3
(d) 6

Answer

Answer: (c) 3
Hint:
m – 1 = 2 ⇒ m = 2 + 1 = 3.


Question 19.
The solution of the equation 2m = 4 is
(a) 1
(b) 2
(c) -1
(d) -2

Answer

Answer: (b) 2
Hint:
2m = 4 ⇒ m = \(\frac{4}{2}\) = 2


Question 20.
The solution of the equation \(\frac { m }{ 3 } \) = 3 is
(a) 3
(b) 6
(c) 9
(d) 12

Answer

Answer: (c) 9
Hint:
\(\frac{m}{3}\) = 3 ⇒ m = 3 × 3 = 9.


Question 21.
The solution of the equation = 6 is
(a) 6
(b) 7
(c) 14
(d) 3

Answer

Answer: (c) 14
Hint:
\(\frac{3m}{7}\) = 6 ⇒ 3m = 7 × 6 = 42
⇒ m = \(\frac{42}{3}\) = 14


Question 22.
The solution of the equation 3p + 5 = 8 is
(a) -1
(b) 1
(c) 3
(d) 5

Answer

Answer: (b) 1
Hint:
3p + 5 = 8 ⇒ 3p = 8 – 5 = 3
⇒ P = \(\frac{3}{3}\) = 1 4p – 2 = 10


Question 23.
The solution of the equation 4p – 2 = 10 is
(a) 1
(b) 2
(c) 3
(d) 4

Answer

Answer: (c) 3
Hint:
4p – 2 = 10 ⇒ 4p = 10 + 2 = 12
⇒ p = \(\frac{12}{4}\) = 3.


Question 24.
The solution of the equation \(\frac { p }{ 2 } \) + 1 = 3 is
(a) 1
(b) 2
(c) 3
(d) 4

Answer

Answer: (d) 4
Hint:
\(\frac{p}{2}\) + 1 = 3 ⇒ \(\frac{p}{2}\) = 3 – 1 = 2
p = 2 × 2 = 4


Question 25.
The solution of the equation 3 m + 7=16 is
(a) 1
(b) 2
(c) 3
(d) 4

Answer

Answer: (c) 3
Hint:
3m + 7 = 16 ⇒ 3m = 16 – 7 = 9
⇒ m = \(\frac{9}{3}\) = 3


Question 26.
The solution of the equation 2p – 1 = 3 is
(a) 1
(b) 2
(c) 3
(d) 4

Answer

Answer: (b) 2
Hint:
2p – 1 = 3 ⇒ 2p = 3 + 1 = 4
⇒ p = \(\frac{4}{2}\) = 2.


Question 27.
The solution of the equation 4x + 5 = 9 is
(a) 1
(b) 2
(c) 3
(d) 4

Answer

Answer: (a) 1
Hint:
4x + 5 = 9 ⇒ 4x = 9 – 6 = 4
⇒ x = \(\frac{4}{4}\) = 1.


Question 28.
The solution of the equation 10 y – 20 = 30 is
(a) 1
(b) 2
(c) 3
(d) 5

Answer

Answer: (d) 5
Hint:
10y – 20 = 30 ⇒ 10y = 30 + 20 = 50
⇒ y = \(\frac{50}{10}\) = 5.


Question 29.
The solution of the equation y – 4 = – 1 is
(a) 1
(b) 2
(c) 3
(d) 4

Answer

Answer: (c) 3
Hint:
y – 4 = -1 ⇒ y = 4 – 1 = 3.


Question 30.
The solution of the equation y + 2 = -2 is
(a) 2
(b) -2
(c) 4
(d) -4

Answer

Answer: (d) -4
Hint:
y + 2 = -2 ⇒ y = -2 – 2 = -4.


Question 31.
The solution of the equation 10t = -20 is
(a) 1
(b) -1
(c) 2
(d) -2

Answer

Answer: (d) -2
Hint:
10t = -20 ⇒ t = –\(\frac{20}{10}\) = -2


Question 32.
The solution of the equation \(\frac { z }{ 2 } \) = \(\frac { 3 }{ 4 } \) is
(a) \(\frac { 1 }{ 2 } \)
(b) \(\frac { 3 }{ 2 } \)
(c) \(\frac { 1 }{ 4 } \)
(d) \(\frac { 3 }{ 4 } \)

Answer

Answer: (b) \(\frac { 3 }{ 2 } \)
Hint:
\(\frac{z}{2}\) = \(\frac{3}{4}\) ⇒ z = \(\frac{3×2}{4}\) = \(\frac{3}{2}\)


Question 33.
The solution of the equation 2s = 0 is
(a) 2
(b) -2
(c) 0
(d) \(\frac { 1 }{ 2 } \)

Answer

Answer: (c) 0
Hint:
2s = 0 ⇒ s = \(\frac{0}{2}\) = 0.


Question 34.
The solution of the equation – \(\frac { p }{ 7 } \) = 3 is
(a) -3
(b) -7
(c) -21
(d) 21

Answer

Answer: (c) -21
Hint:
–\(\frac{p}{7}\) = 3 ⇒ -p = 3 × 7 = 21
⇒ p = -21


Question 35.
The solution of the equation 3s + 6 = 0 is
(a) 1
(b) -1
(c) 2
(d) -2

Answer

Answer: (d) -2
Hint:
3s + 6 = 0
⇒ 3s = -6 ⇒ s = –\(\frac{6}{3}\) = -2.


Question 36.
The solution of the equation 10p = 10 is
(a) 1
(b) – 1
(c) 10
(d) – 10

Answer

Answer: (a) 1
Hint:
10p = 10 ⇒ p = \(\frac{10}{10}\) = 1.


Question 37.
The solution of the equation 10p + 10 = 110 is
(a) 10
(b) -10
(c) 100
(d) 110

Answer

Answer: (a) 10
Hint:
10p + 10 = 110
⇒ 10p = 110 – 10 = 100
⇒ p = \(\frac{100}{10}\) = 10.


Question 38.
The solution of the equation 12p – 11 = 13 is
(a) 1
(b) 2
(c) 3
(d) 4

Answer

Answer: (b) 2
Hint:
12p – 11 = 13 ⇒ 12p = 13 + 11 = 24
⇒ p = \(\frac{24}{12}\) = 2.


Question 39.
The solution of the equation 2 (m + 3) = 8 is
(a) 1
(b) 2
(c) 3
(d) 4

Answer

Answer: (a) 1
Hint:
2(m + 3) = 8 ⇒ m + 3 = \(\frac{8}{2}\) = 4
⇒ m = 4 – 3 = 1.


Question 40.
The solution of the equation – 2(x + 3) = 4 is
(a) -2
(b) -3
(c) -4
(d) -5

Answer

Answer: (d) -5
Hint:
-2 (x + 3) = 4 ⇒ x + 3 = \(\frac{4}{-2}\) = -2
⇒ x = -2 – 3 = -5.


Question 41.
The solution of the equation \(\frac { 5 }{ 2 } \) x = 15 is
(a) 2
(b) 4
(c) 6
(d) 10

Answer

Answer: (c) 6
Hint:
\(\frac{5}{2}\) x = 15 ⇒ x = \(\frac{15×2}{5}\) = 6


Question 42.
The solution of the equation 4(2 – x) = 4 is
(a) 1
(b) 2
(c) 3
(d) 4

Answer

Answer: (a) 1
Hint:
4 (2 – x) = 4 ⇒ 2 – x = \(\frac{4}{4}\) = 1
⇒ x = 2 – 1 = 1.


Question 43.
The solution of the equation -4(2 + x) = 4 is
(a) -1
(b) -2
(c) -3
(d) -4

Answer

Answer: (c) -3
Hint:
-4(2 + x) = 4 ⇒ 2 + x = \(\frac{4}{-4}\) = -1
⇒ x = -1 – 2 = -3.


Question 44.
The solution of the equation – 4 = 2 (p – 2) is
(a) 0
(b) 1
(c) 2
(d) 4

Answer

Answer: (a) 0
Hint:
-4 = 2(p – 2) ⇒ p – 2 = –\(\frac{4}{2}\) = -2
⇒ p = -2 + 2 = 0.


Question 45.
The solution of the equation 0 = 4 + 4(m + 1) is
(a) 1
(b) -1
(c) 2
(d) -2

Answer

Answer: (d) -2
Hint:
0 = 4 + 4 (m + 1)
⇒ 4(m + 1) = -4 ⇒ m + 1 = –\(\frac{4}{4}\) = -1
m = -1 – 1 = -2.


We hope the given NCERT MCQ Questions for Class 7 Maths Chapter 4 Simple Equations with Answers Pdf free download will help you. If you have any queries regarding Simple Equations CBSE Class 7 Maths MCQs Multiple Choice Questions with Answers, drop a comment below and we will get back to you soon.

MCQ Questions for Class 7 Maths Chapter 1 Integers with Answers

MCQ Questions for Class 7 Maths Chapter 1 Integers with Answers

Check the below NCERT MCQ Questions for Class 7 Maths Chapter 1 Integers with Answers Pdf free download. MCQ Questions for Class 7 Maths with Answers were prepared based on the latest exam pattern. We have provided Integers Class 7 Maths MCQs Questions with Answers to help students understand the concept very well. https://mcqquestions.guru/mcq-questions-for-class-7-maths-chapter-1/

Students can also refer to NCERT Solutions for Class 7 Maths Chapter 1 Integers for better exam preparation and score more marks.

Integers Class 7 MCQs Questions with Answers

Class 7 Maths Chapter 1 MCQ Question 1.
On a number line, when we add a positive integer, we
(a) move to the right
(b) move to the left
(c) do not move at all
(d) none of these.

Answer

Answer: (a) move to the right


Integers Class 7 MCQ Question 2.
On a number line, when we add a negative integer, we
(a) move to the right
(b) move to the left
(c) do not move at all
(d) none of these.

Answer

Answer: (b) move to the left


MCQ Questions For Class 7 Maths With Answers Chapter 1 Question 3.
On a number line, when we subtract a positive integer, we
(a) move to the right
(b) move to the left
(c) do not move at all
(d) none of these.

Answer

Answer: (b) move to the left


Integers MCQ Class 7 Question 4.
On a number line, when we subtract a negative integer, we
(a) move to the right
(b) move to the left
(c) do not move at all
(d) none of these.

Answer

Answer: (a) move to the right


MCQ Questions For Class 7 Maths Integers Question 5.
When two positive integers are added, we get
(a) a positive integer
(b) a negative integer
(c) sometimes a positive integer, sometimes a negative integer
(d) none of these.

Answer

Answer: (a) a positive integer


Class 7 Integers MCQ Question 6.
When two negative integers are added, we get
(a) a positive integer
(b) a negative integer
(c) sometimes a positive integer, sometimes a negative integer
(d) none of these.

Answer

Answer: (b) a negative integer


Integers Class 7 MCQ Test Question 7.
Which of the following statements is wrong?
(а) When a positive integer and a negative integer are added, we always get a negative integer
(b) Additive inverse of 8 is (-8)
(c) Additive inverse of (-8) is 8
(d) For subtraction, we add the additive inverse of the integer that is being subtracted, to the other integer.

Answer

Answer: (а) When a positive integer and a negative integer are added, we always get a negative integer


MCQ On Integers For Class 7 Question 8.
Which of the following is true?
(а) (- 8) + (- 4) > (- 8) – (- 4)
(b) (- 8) + (- 4) < (- 8) – (- 4)
(c) (-8) + (- 4) = (- 8) – (- 4)
(d) none of these.

Answer

Answer: (b) (- 8) + (- 4) < (- 8) – (- 4)
Hint:
(-8) + (-4) = -12
(-8) – (-4) = -4


Class 7 Math Chapter 1 MCQ Question 9.
The product of two negative integers is
(a) a positive integer
(b) a negative integer
(c) either a positive integer or a negative integer
(d) none of these.

Answer

Answer: (a) a positive integer


Class 7 Maths Ch 1 MCQ Question 10.
The product of three negative integers is
(a) a positive integer
(b) a negative integer
(c) either a positive integer or a negative integer
(d) none of these.

Answer

Answer: (b) a negative integer


Class 7 Maths MCQ Chapter 1 Question 11.
(-1) × (-1) × (-1) × ……… 10 times is equal to
(a) 1
(b) -1
(c) 1 or -1
(d) none of these.

Answer

Answer: (a) 1


Class 7th Maths Chapter 1 MCQ Question 12.
(-1) × (-1) × (-1) × …….. 5 times is equal to
(a) 1
(b) -1
(c) 1 or -1
(d) none of these.

Answer

Answer: (b) -1


MCQ Class 7 Maths Chapter 1 Question 13.
(-1) × (-1) × (-1) × …… 2 m times, where m is a natural number, is equal to
(a) 1
(b) -1
(c) 1 or -1
(d) none of these.

Answer

Answer: (a) 1


Ncert Class 7 Maths Chapter 1 MCQ Question 14.
(-1) × (-1) × (-1) × (2m + 1) times,
where m is a natural number, is equal to
(a) 1
(b) -1
(c) 1 or -1
(d) none of these.

Answer

Answer: (b) -1


Class 7 Maths Chapter 1 MCQ With Answers Question 15.
(-20) × (-5) is equal to
(a) 100
(b) – 100
(c) 20
(d) 5.

Answer

Answer: (a) 100


Question 16.
(-30) × 20 is equal to
(a) 600
(b) -600
(c) 50
(d) 10.

Answer

Answer: (b) – 600


Question 17.
10 × (-20) is equal to
(a) 200
(b) -200
(c) 30
(s) 20

Answer

Answer: (b) -200


Question 18.
3 × 0 is equal to
(a) 0
(b) 3
(c) 1
(d) -3

Answer

Answer: (a) 0


Question 19.
0 × (-5) is equal to
(a) 0
(b) 5
(c) -5
(d) 1.

Answer

Answer: (a) 0


Question 20.
(-2) × 1 is equal to
(a) 2
(b) -2
(c) 1
(d) – 1.

Answer

Answer: (b) -2


Question 21.
1 × 6 is equal to
(a) 6
(b) -6
(c) 1
(d) -1.

Answer

Answer: (a) 6


Question 22.
4 × (-1) is equal to
(a) 4
(b) -4
(c) 1
(d) – 1.

Answer

Answer: (b) -4


Question 23.
(-10) × 0 × (-15) is equal to
(a) 0
(b) 10
(c) 15
(d) 150.

Answer

Answer: (a) 0


Question 24.
The integer whose product with (-1) is 0, is
(a) 1
(b) -1
(c) 0
(d) none of these

Answer

Answer: (c) 0


Question 25.
The integer whose product with (-1) is 1, is
(a) -1
(b) 1
(c) 0
(d) none of these.

Answer

Answer: (a) -1


Question 26.
10 ÷ (-5) is equal to
(a) 1
(b) 2
(c) -2
(d) 5.

Answer

Answer: (c) -2


Question 27.
(-6) ÷ (-3) is equal to
(a) 1
(b) 2
(c) 3
(d) 6.

Answer

Answer: (b) 2


Question 28.
(-5) ÷ 1 is equal to
(a) 5
(b) -5
(c) 1
(d) -1.

Answer

Answer: (b) -5


Question 29.
(-9) ÷ (-1) is equal to
(a) 1
(b) 9
(c) -1
(d) -9.

Answer

Answer: (b) 9


Question 30.
If 16 ÷ x = 16, then x is equal to
(a) 1
(b) 2
(c) 4
(d) 16.

Answer

Answer: (a) 1


Question 31.
If (-50) ÷ x = 1, then x is equal to
(a) 1
(b) 50
(c) -50
(d) 10.

Answer

Answer: (c) -50


Question 32.
If x ÷ 1 = 8, then x is equal to
(a) 8
(b) 1
(c) -8
(d) -1.

Answer

Answer: (a) 8


Question 33.
The additive identity for integers is
(a) 1
(b) -1
(c) 0
(d) none of these.

Answer

Answer: (c) 0


Question 34.
The multiplicative identity for integers is
(a) 1
(b) -1
(c) 0
(d) none of these.

Answer

Answer: (a) 1


Question 35.
a × (b + c) = a × b + a × c is called
(a) commutative property
(b) associative property
(c) distributive property
(d) closure property.

Answer

Answer: (c) distributive property


Question 36.
Manish deposits Rs 2000 in his bank account and withdraws Rs 1000 from it, the next day. Find the balance in Manish’s account after the withdrawal.
(a) Rs 2000
(b) Rs 3000
(c) Rs 1000
(d) none of these.

Answer

Answer: (c) Rs 1000
Hint:
2000 – 1000 = Rs 1000


We hope the given NCERT MCQ Questions for Class 7 Maths Chapter 1 Integers with Answers Pdf free download will help you. If you have any queries regarding Integers CBSE Class 7 Maths MCQs Multiple Choice Questions with Answers, drop a comment below and we will get back to you soon.

NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.4

NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.4 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.4. https://mcqquestions.guru/ncert-solutions-for-class-6-maths-chapter-3-ex-3-4/

BoardCBSE
TextbookNCERT
ClassClass 6
SubjectMaths
ChapterChapter 3
Chapter NamePlaying With Numbers
Exercise Ex 3.4
Number of Questions Solved7
CategoryNCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.4

Question 1.
Find the common factors of:
(a) 20 and 28
(b) 15 and 25
(c) 35 and 50
(d) 56 and 120.
Solution :
(a) 20 and 28
Factors of 20 are 1, 2,4, 5, 10 and 20.
Factors of 28 are 1, 2,4, 7, 14 and 28.
Hence, the common factors of 20 and 28 are 1, 2 and 4.

(b) 15 and 25
Factors of 15 are 1, 3, 5 and 15.
Factors of 25 are 1, 5 and 25.
Hence, the common factors of 15 and 25 are 1 and 5.

(c) 35 and 50
Factors of 35 are 1, 5, 7 and 35.
Factors of 50 are 1, 5, 10, 25 and 50.
Hence, the common factors of 35 and 50 are 1 and 5.

(d) 56 and 120
Factors of 56 are 1, 2,4, 7, 8, 14, 28 and 56. Factors of 120 are 1, 2, 3,4, 5, 6, 8,10, 12,15, 20, 24, 30,40, 60 and 120. ,
Hence, the common factors of 56 and 120 are 1, 2,4 and 8.

Question 2.
Find the common factors of:
(a) 4, 8 and 12
(b) 5, 15 and 25.
Solution :
(a) 4,8 and 12 Factors of 4 are 1,2 and 4.
Factors of 8 are 1, 2,4 and 8.
Factors of 12 are 1, 2, 3,4,6 and 12.
Hence, the common factors of 4,8 and 12 are 1, 2 and 4.

(b) 5,15 and 25
Factors of 5 are 1 and 5.
Factors of 15 are 1, 3 and 5.
Factors of 25 are 1,5 and 25.
Hence, the common factors of 5,15 and 25 are 1 and 5.

Question 3.
Find the first three common multiples of:
(a) 6 and 8
(b) 12 and 18.
Solution :
(a) 6 and 8
Multiples of 6 are 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72,78, 84,90,96,
Multiples of 8 are 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96
Common multiples of 6 and 8 are 24, 48, 72, 96,
∴ First three common multiples of 6 and 8 are 24, 48 and 72.

(b) 12 and 18
Multiples of 12 are 12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144, *
Multiples of 18 are 18,36,54,72,90,108,126, 144,
∴ Common multiples of 12 and 18 are 36, 72,108, 144,
∴ First three common multiples of 12 and 18 are 36, 72 and 108.

Question 4.
Write all the numbers less than 100 which are common multiples of 3 and 4.
Solution :
Multiples of 3 are : 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99, 102, 105, 108,
Multiples of 4 are : 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100, 104, 108,
Common multiples of 3 and 4 are : 12, 24, 36, 48, 60, 72, 84, 96, 108,
∴ All the numbers less than 100 which are common multiples of 3 and 4 are 12, 24, 36, 48, 60, 72, 84 and 96.

Question 5.
Which of the following numbers are co-prime :
(a) 18 and 35
(b) 15 and 37
(c) 30 and 415
(d) 17 and 68
(e) 216 and 215
(f) 81 and 16.
Solution :
(a) 18 and 35
Factors of 18 are 1, 2, 3, 6, 9 and 18.
Factors of 35 are 1, 5, 7 and 35.
∴ A common factor of 18 and 35 is 1.
∴ 18 and 3 5 have only 1 as the common factor
∴ 18 and 35 are co-prime numbers.

(b) 15 and 37
Factors of 15 are 1, 3, 5 and 15.
Factors of 37 are 1 and 37.
∴ A common factor of 15 and 37 is 1. v 15 and 37 have only 1 as the common factor ∴ 15 and 37 are co-prime numbers.

(c)
30 and 415
Factors of 30 are 1, 2, 3, 5, 6, 10, 15 and 30.
Factors of 415 are 1, 5, 83 and 415.
∴ Common factors of 30 and 415 are 1 and 5. v
∴ 30 and 415 have two common factors
∴ 30 and 45 are not co-prime numbers.

(d) 17 and 68 Factors of 17 are 1 and 17.
Factors of 68 are 1, 2, 4, 17, 34 and 68.
∴ Common factors of 17 and 68 are 1 and 17.
∴ 17 and 68 have two common factors
∴ 17 and 68 are not co-prime numbers.

(e) 216 and 215
Factors of 216 are 1,2, 3, 4, 6, 8, 9, 12, 18, 24, 27, 36, 54, 72, 108 and 216.
Factors of 215 are 1, 5 and 43
∴ A common factor of 216 and 215 is 1.
∴ 216 and 215 have only 1 as the common factor
∴ 216 and 215 are co-prime numbers.

(f) 81 and 16
Factors of 81 are 1, 3, 9, 27 and 81.
Factors of 16 are 1, 2, 4, 8 and 16.
∴ A common factor of 81 and 16 is 1.
∴ 81 and 16 have only 1 as the common factor
∴ 81 and 16 are co-prime numbers.

Question 6.
A number is divisible by both 5 and 12. By which other numbers will that number be always divisible?
Solution :
The number will be always divisible by 5 × 12 = 60.

Question 7.
A number is divisible by 12. By what other numbers will that number be divisible?
Solution :
Factors of 12 are 1, 2, 3, 4, 6 and 12. So, that number will be divisible by other numbers 1, 2, 3, 4 and 6.

 

We hope the NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.4 help you. If you have any query regarding NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.4, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.3

NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.3 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.3. https://mcqquestions.guru/ncert-solutions-for-class-6-maths-chapter-3-ex-3-3/

BoardCBSE
TextbookNCERT
ClassClass 6
SubjectMaths
ChapterChapter 3
Chapter NamePlaying With Numbers
Exercise Ex 3.3
Number of Questions Solved6
CategoryNCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.3

Question 1.
Using divisibility tests, determine which the following numbers are divisible by 2; by 3; by 4; by 5; by 6; by 8; by 9; by 10; by 11; (say yes or no):
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 2
Solution :
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 3
Question 2.
Using divisibility tests, determine which of the following numbers are divisible by 4: by 8:
(a) 572
(b) 726352
(C) 5500
(d) 6000
(e) 12159
(f) 14560
(g) 21084
(h) 31795072
(i) 1700
(j) 2150.
Solution :
(a) 572
(i) Divisibility by 4
The number formed by last two digits = 72
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 4
∵ Remainder is 0
∴ 72 is divisible by 4
∴ 572 is divisible by 4.

(ii) Divisibility by 8
The number formed by last three digits = 572
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 5
∵ Remainder = 4 ≠ 0
∴ 572 is not divisible by 8.

(b) 726352
(i) Divisibility by 4
The number formed by last two digits = 52
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 6
∵ Remainder is 0
∴ 52 is divisible by 4
∴ 726352 is divisible by 4.

(ii) Divisibility by 8
The number formed by last three digits = 352
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 7
∵ Remainder is 0
∴ 352 is divisible by 8
∴ 726352 is divisible by 8.

(c) 5500
(i) Divisibility by 4
The number formed by last two digits = 00, which is divisible by 4 5500 is divisible by 4.
∴ 500 is Divisibility by 4

(ii)
The number formed by last three digits = 500
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 8
∵ Remainder 4 0
∴ 500 is not divisible by 8
∴ 5500 is not divisible by 8.

(d) 6000
(i) Divisibility by 4
The number formed by last two digits = 00, which is divisible by 4
6000 is divisible by 4.

(ii) Divisibility by 8
The number formed by last three digits = 000, which is divisible by 8 6000 is divisible by 8.
6000 is divisible by 8

(e) 12159
(i) Divisibility by 4
The number formed by last two digits = 59
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 9
∵ Remainder = 3 ≠ 0
∴ 59 is not divisible by 4.
∴ 12159 is not divisible by 4.

(ii) Divisibility by 8
The number formed by last three digits =159
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 10
∵ Remainder 7 ≠ 0
∴ 159 is not divisible by 8
∴ 12159 is not divisible by 8.

(f) 14560
(i) Divisibility by 4
The number formed by last two digits = 60
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 11
∵ Remainder is 0
∴ 60 is divisible by 4
∴ 14560 is divisible by 4.

(ii) Divisibility by 8
The number formed by last three digits = 560
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 12
∵ Remainder is 0
∴ 560 is divisible by 8
∴ 14560 is divisible by 8.

(g) 21084
(i) Divisibility by 4
The number formed by last two digits = 84
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 13
∵ Remainder is 0
∴ 484 is divisible by 4
∴ 21084 is divisible by 4.

(ii) Divisibility by 8
The number formed by last three digits = 84
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 14
∵ The remainder is not 0
∴ 84 is not divisible by 8
∴ 21084 is not divisible by 8.

(h) 31795072
(i) Divisibility by 4
The number formed by last two digits = 72
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 15
∵ Remainder is 0
∴ 72 is divisible by 4
∴ 31795072 is divisible by 4.

(ii) Divisibility by 8
The number formed by last three digits = 72
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 16
∵ Remainder is 0
∴ 72 is divisible by 8
∴ 31795072 is divisible by 8.

(i) 1700
(i) Divisibility by 4
The number formed by last two digits = 00, which is divisible by 4
∴ 1700 is divisible by

(ii) Divisibility by 8
The number formed by last three digits = 700
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 17
∵ Remainder 4 ≠ 0
∴ 700 is not divisible by 8
∴ 1700 is not divisible by 8.

(j) 2150
(i) Divisibility by 4
The number formed by last two digits = 50
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 18
∵ Remainder = 2 ≠ 0
∴ 50 is not divisible by 4
∴ 2150 is not divisible by 4.

(ii) Divisibility by 8
The number formed by last three digits =150
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 19
∵ Remainder 6 ≠ 0
∴ 150 is not divisible by 8
∴ 2150 is not divisible by 8.

Question 3.
Using divisibility tests, determine which of following numbers are divisible by 6 :
(a)297144
(b) 1258
(c) 4335
(d) 61233
(e) 901352
(f) 438750
(g) 1790184
(h) 12583
(i) 639210
(j) 17852.
Solution :
We know that number is divisible by 6 if it is divisible by 2 and 3 both.
(a) 297144
(i) Divisibility by 2
Unit’s digit = 4
297144 is divisible by 2.

(ii) Divisibility by 3
Sum of the digits = 2 + 9 + 7 + 1+ 4 + 4 = 27, which is divisible by 3 297144 is divisible by 3 Since, 297144 is divisible by 2 and 3 both, so it is divisible by 6.

(b) 1258
(i) Divisibility by 2 Unit’s digit = 8 1258 is divisible by 2.
(ii) Divisibility by 3 Sum of the digits =1+2 + 5 + 8=16 which is not divisible by 3 1258 is not divisible by 3. Since 1258 is divisible by 2 but not by 3. so 1258 is not divisible by 6.

(c) 4335
(i) Divisibility by 2
Unit’s digit = 5, which is not any of the digits 0, 2, 4, 6 or 8 4335 is not divisible by 2 4335 is not divisible by 6.

(d) 61233
(i) Divisibility by 2
Unit’s digit = 3, which is not any of the digits 0, 2, 4, 6 or 8

61233 is not divisible by 2
61233 is not divisible by 6.

(e) 901352
(i) Divisibility by 2 v Unit’s digit = 2
901352 is divisible by 2.
(ii) Divisibility by 3
Sum of the digits = 9 + 0+1+3 + 5 + 2 = 20, which is not divisible by 3
901352 is not divisible by 3 Since, 901352 is divisible by 2 but not by 3, so it is not divisible by 6.

(f) 438750
(i) Divisibility by 2 v Unit’s digit = 0
438750 is divisible by 2.

(ii) Divisibility by 3
Sum of the digits = 4 + 3 + 8 + 7 + 5+ 0 = 27, which is divisible by 3
438750 is divisible by 3 Since, 438750 is divisible by 2 and 3 both, so it is divisible by 6.

(g) 1790184
(i) Divisibility by 2 v Unit’s digit = 4
1790184 is divisible by 2.
(ii) Divisibility by 3
Sum of the digits =1+7 + 9 + 0+1 + 8 + 4=30, which is divisible by 3
1790184 is divisible by 3 Since, 1790184 is divisible by 2 and 3 both, so it is divisible by 6.

(h) 12583,
(i) Divisibility by 2
Unit’s digit = 3, which is not any of the digits 0, 2, 4, 6 or 8
12583 is not divisible by 2
12583 is not divisible by 6.

(i) 639210
(i) Divisibility by 2
Unit’s digit = 0
639210 is divisible by 2.
(ii) Divisibility by 3
Sum of the digits = 6 + 3 + 9 + 2+1+0 = 21, which is divisible by 3
639210 is divisible by 3 Since, 639210 is divisible by 2 and 3 both, so it is divisible by 6.

(j) 17852
(i) Divisibility by 2
Unit’s digit = 2
∴ 17852 is divisible by 2.
(ii) Divisibility by 3 Sum of the digits =1+7 + 8 + 5 + 2 = 23, which is not divisible by 3
17852 is not divisible by 3
Since 17852 is divisible by 2 but not by 3, so it is not divisible by 6.

Question 4.
Using divisibility tests, determine which of the following numbers are divisible by 11:
(a) 5445
(b) 10824
(c) 7138965
(d) 70169308
(e) 10000001
(f) 901153.
Solution :
(a) 5445
Sum of the digits (at odd places) from the right =5+4=9
Sum of the digits (at even places) from the right =4+5=9
Difference of these sums = 9-9 = 0 v 0 is divisible by 11
5445 is divisible by 11.

(b) 10824
Sum of the digits (at odd places) from the right = 4 + 8+1 = 13
Sum of the digits (at even places) from the right = 2 + 0 = 2
Difference of these sums = 13 – 2 = 11
11 is divisible by 11
10824 is divisible by 11.

(c) 7138965
Sum of the digits (at odd places) from the right =5+9+3+7=24
Sum of the digits (at even places) from the right = 6 + 8 + 1 = 15
Difference of these sums = 24 – 15 = 9
Y 9 is not divisible by 11
∴ 7138965 is not divisible by 11.

(d) 70169308
Sum of the digits (at odd places) from the right = 8 + 3+6 + 0=17
Sum of the digits (at even places) from the right = 0 + 9 + 1+7=17 Difference of these sums = 17-17=0
Y 0 is divisible by 11
∴ 70169308 is divisible by 11.

(e) 10000001
Sum of the digits (at odd places) from the right =l+0+0+0=l
Sum of the digits (at even places) from the right =0+0+0+1=1 Difference of these sums =1-1=0 0 is divisible by 11
∴ 10000001 is divisible by 11.

(f) 901153
Sum of the digits (at odd places) from the right = 3+ 1 +0 = 4
Sum of the digits (at even places) from the right = 5+1+9=15
Difference of these sums =15-4=11
Y 11 is divisible by 11
∴ 901153 is divisible by 11.

Question 5.
Write the smallest digit and the largest digit in the blank space of each of the following numbers so that the number is divisible by 3:
(a) __ 6724
(b) 4765 __ 2.
Solution :
(a) __ 6724
(i) Smallest digit
Sum of the given digits = 6 + 7 + 2 + 4=19
19 is not divisible by 3
∴ Smallest digit (non-zero) is 2.

(ii)
Largest digit The largest digit is 8.

(b) 4765 _ 2
(i) Smallest digit
Sum of the given digits = 4 + 7 + 6 + 5 + 2 = 24 Y 24 is divisible by 3
∴ Smallest digit is 0.

(ii)
Largest digit The largest digit is 9.

Question 6.
Write digit in the blank space of each of the following numbers so that the number is divisible by 11:
(a) 92 __ 389
(b) 8 __ 9484.
Solution :
(a) 92 __ 389
Sum of the given digits (at odd places) from the right = 9 + 3 + 2= 14
Sum of the given digits (at even places) from the right = 8 + required digit + 9 = required digit + 17
Difference of these sums = required digit + 3 For the above difference to be divisible by 11, required digit = 8.
Hence, the required number is 92 8 389.

(b) 8 __ 9484
Sum of the given digits (at odd places) from the right = 4 + 4 + required digit = 8 + required digit
Sum of the given digits (at even places) from the right = 8 + 9 + 8 = 25
Difference of the sums = 17 – required digit For the above difference to be divisible by 11, required digit = 6.
Hence, the required number is 8 6 9484.

 

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