RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6A

RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6A

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 6 Simplification Ex 6A.

Other Exercises

Simplify

Question 1.
Solution:
21 – 12 ÷ 3 x 2
= 21 – 4 x 2
= 21 – 8
= 13. Ans

Question 2.
Solution:
16 + 8 ÷ 4 – 2 x 3
= 16 + 2 – 2 x 3
= 16 + 2 – 6
= 18 – 6
= 12. Ans.

Question 3.
Solution:
13 – (12 – 6 ÷ 3)
= 13 – (12 – 2)
= 13 – (10)
= 13 – 10
= 3 Ans.

Question 4.
Solution:
19 – [4 + {16 – (12 – 2)}]
= 19 – [4 + {16 – 10}]
= 19 – [4 + 6]
= 19 – 10
= 9. Ans

Question 5.
Solution:
36 – [18 – {14 – (15 – 4 ÷ 2 x 2)}]
= 36 – [18 – {14 – (15 – 2 x 2)}]
= 36 – [18 – {14 – (15 – 4)}]
= 36 – [18 – {14 – 11}]
= 36 – [18 – 3]
= 36 – 15
= 21. Ans.

Question 6.
Solution:
\(27-[18-\{ 16-(5-\overline { 4-1 } )\} ] \)
= 27 – [18 – {16 – (5 – 3)}]
= 27 – [18 – {16 – 2}]
= 27 – [18 – 14]
= 27 – 4
= 23. Ans.

Question 7.
Solution:
\(4\frac { 4 }{ 3 } \div \frac { 3 }{ 5 } of5+\frac { 4 }{ 5 } \times \frac { 3 }{ 10 } -\frac { 1 }{ 5 } \)
RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6A 7.1

Question 8.
Solution:
\(\left( \frac { 2 }{ 3 } +\frac { 4 }{ 9 } \right) of\frac { 3 }{ 5 } \div 1\frac { 2 }{ 3 } \times 1\frac { 1 }{ 4 } -\frac { 1 }{ 3 } \)
RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6A 8.1

Question 9.
Solution:
\(7\frac { 1 }{ 3 } \div \frac { 2 }{ 3 } of2\frac { 1 }{ 5 } +1\frac { 3 }{ 8 } \div 2\frac { 3 }{ 4 } -1\frac { 1 }{ 2 } \)
RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6A 9.1

Question 10.
Solution:
\(5\frac { 1 }{ 7 } -\left\{ 3\frac { 3 }{ 10 } \div \left( 2\frac { 4 }{ 5 } -\frac { 7 }{ 10 } \right) \right\} \)
RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6A 10.1

Question 11.
Solution:
\(9\frac { 3 }{ 4 } \div \left[ 2\frac { 1 }{ 6 } +\left\{ 4\frac { 1 }{ 3 } -\left( 1\frac { 1 }{ 2 } +1\frac { 3 }{ 4 } \right) \right\} \right] \)
RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6A 11.1
RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6A 11.2

Question 12.
Solution:
\(4\frac { 1 }{ 10 } -\left[ 2\frac { 1 }{ 2 } -\left\{ \frac { 5 }{ 6 } -\left( \frac { 2 }{ 5 } +\frac { 3 }{ 10 } -\frac { 4 }{ 15 } \right) \right\} \right] \)
RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6A 12.1

Question 13.
Solution:
\(1\frac { 5 }{ 6 } +\left[ 2\frac { 2 }{ 3 } -\left\{ 3\frac { 3 }{ 4 } \left( 3\frac { 4 }{ 5 } \div 9\frac { 1 }{ 2 } \right) \right\} \right] \)
RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6A 13.1

Question 14.
Solution:
\(4\frac { 4 }{ 5 } \div \left\{ 2\frac { 1 }{ 5 } -\frac { 1 }{ 2 } \left( 1\frac { 1 }{ 4 } -\overline { \frac { 1 }{ 4 } -\frac { 1 }{ 5 } } \right) \right\} \)
RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6A 14.1

Question 15.
Solution:
\(7\frac { 1 }{ 2 } -\left[ 2\frac { 1 }{ 4 } \div \left\{ 1\frac { 1 }{ 4 } -\frac { 1 }{ 2 } \left( \frac { 3 }{ 2 } -\overline { \frac { 1 }{ 3 } -\frac { 1 }{ 6 } } \right) \right\} \right] \)
RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6A 15.1

Hope given RS Aggarwal Solutions Class 6 Chapter 6 Simplification Ex 6A are helpful to complete your math homework.

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RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5G

RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5G

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5G.

Other Exercises

Objective Questions :
Tick the correct answer in each of the following :

Question 1.
Solution:
(c) ∴ canceling the common factor 2, we get \(\\ \frac { 3 }{ 5 } \)

Question 2.
Solution:
(c) ∴ multiplying numerator and denominator by 4, we get \(\\ \frac { 8 }{ 12 } \)

Question 3.
Solution:
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5G 3.1

Question 4.
Solution:
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5G 4.1

Question 5.
Solution:
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5G 5.1

Question 6.
Solution:
(c) each of the fractions has the same denominator.

Question 7.
Solution:
(d) none of these has greater denominator than its numerator.

Question 8.
Solution:
(a) its denominator is greater than its numerator.

Question 9.
Solution:
(b) their numerators are same and 4 < 5 , \(\frac { 3 }{ 4 } >\frac { 3 }{ 5 } \)

Question 10.
Solution:
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5G 10.1

Question 11.
Solution:
(b) In \(\frac { 4 }{ 5 } ,\frac { 2 }{ 7 } ,\frac { 4 }{ 9 } ,\frac { 4 }{ 11 } \) numerator is same then the smallest denominator’s fraction is greater.

Question 12.
Solution:
(a) Denominators are same, then fraction of smallest numerator will be smallest.

Question 13.
Solution:
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5G 13.1

Question 14.
Solution:
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5G 14.1

Question 15.
Solution:
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5G 15.1

Question 16.
Solution:
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5G 16.1

Question 17.
Solution:
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5G 17.1

Question 18.
Solution:
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5G 18.1

Question 19.
Solution:
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5G 19.1

Question 20.
Solution:
RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5G 20.1

Hope given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5G are helpful to complete your math homework.

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RS Aggarwal Class 6 Solutions Chapter 24 Bar Graph Ex 24

RS Aggarwal Class 6 Solutions Chapter 24 Bar Graph Ex 24

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 24 Bar Graph Ex 24

Question 1.
Solution:
(i) The given bar graph shows the marks obtained by a student in each of the four subjects in an examination.
(ii) The student is poorest in Science.
(iii) The student is best in Mathematics.
(iv) He got more than 40 marks in Hindi and Mathematics.

Question 2.
Solution:
(i) The given bar graph shows the number of members in each of the 60 families of a colony.
(ii) 10 families have 3 members each.
(iii) 5 couples have no child.
(iv) A family of 4 members is most common.

Question 3.
Solution:
(i) The production was maximum in the 2nd week.
(ii) The production was minimum in the 4th week.
(iii) The average production is 720 per week.
(iv) 2400 cycles were produced in the first three weeks.

Question 4.
Solution:
(i) The given bar graph shows the different modes of transport to a school used by 51 students of a locality.
(ii) Maximum number of students use bicycle for going to school.
(iii) 14 students use bus for going to school.
(iv) 37 students do not use bus for going to school.

 

 

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RS Aggarwal Class 6 Solutions Chapter 23 Pictograph Ex 23

RS Aggarwal Class 6 Solutions Chapter 23 Pictograph Ex 23

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 23 Pictograph Ex 23

Question 1.
Solution:
RS Aggarwal Class 6 Solutions Chapter 23 Pictograph Ex 23 Q1.1

Question 2.
Solution:
RS Aggarwal Class 6 Solutions Chapter 23 Pictograph Ex 23 Q2.1

Question 3.
Solution:
RS Aggarwal Class 6 Solutions Chapter 23 Pictograph Ex 23 Q3.1

Question 4.
Solution:
RS Aggarwal Class 6 Solutions Chapter 23 Pictograph Ex 23 Q4.1

Question 5.
Solution:
(i) 24
(ii) 32
(iii) 40
(iv) 96 Ans.

Question 6.
Solution:
(i) 30
(ii) 24
(iii) Friday = 42
(iv) Saturday = 12 Ans.

 

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RS Aggarwal Class 6 Solutions Chapter 22 Data Handling Ex 22

RS Aggarwal Class 6 Solutions Chapter 22 Data Handling Ex 22

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 22 Data Handling Ex 22

Question 1.
Solution:
(i) Data. The word data means information in the form of numerical figures.
(ii) Raw data. Data obtained in the original form is called raw data.
(iii) Array. Arranging the numerical figures (data) in an order i.e. ascending or descending order is called an array.
(iv) Tabulation of data. Arranging the given data in a systematic form in the form of a table is called tabulation of the data.
(v) Observations. Each numerical figure in a data is called an observation.
(vi) Frequency of an observation. The number of times a particular observation occurs is called its frequency.
(vii) Statistics. Statistics is a science which deals with the collection, presentation, analysis and interpretation of numerical data.

Question 2.
Solution:
Arranging the given data in ascending order, we get :
0, 0, 1, 1, 1, 1, 1, 1,2, 2, 2, 2,2, 2,2, 2, 2, 3, 3, 3, 3, 3, 4, 4, 4
RS Aggarwal Class 6 Solutions Chapter 22 Data Handling Ex 22 Q2.1

Question 3.
Solution:
Below is given the frequency distribution table of the given data :
RS Aggarwal Class 6 Solutions Chapter 22 Data Handling Ex 22 Q3.1

Question 4.
Solution:
Below is given the frequency distribution table of the given data :
RS Aggarwal Class 6 Solutions Chapter 22 Data Handling Ex 22 Q4.1

Question 5.
Solution:
Below is given the frequency distribution table of the given data
RS Aggarwal Class 6 Solutions Chapter 22 Data Handling Ex 22 Q5.1

Question 6.
Solution:
(i) numerical figures
(ii) original
(iii) array
(iv) frequency
(v) tabulation

 

Hope given RS Aggarwal Solutions Class 6 Chapter 22 Data Handling Ex 22 are helpful to complete your math homework.

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