## RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5A

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5A.

**Other Exercises**

- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5A
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5B
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5C
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5D
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5E
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5F
- RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5G

**Question 1.**

**Solution:**

(i) \(\\ \frac { 3 }{ 4 } \)

(ii) \(\\ \frac { 1 }{ 4 } \)

(iii) \(\\ \frac { 2 }{ 3 } \)

(iv) \(\\ \frac { 3 }{ 10 } \)

(v) \(\\ \frac { 4 }{ 9 } \)

(vi) \(\\ \frac { 3 }{ 8 } \)

**Question 2.**

**Solution:**

In the figure, \(\\ \frac { 4 }{ 9 } \) is shaded

**Question 3.**

**Solution:**

In the figure, whole rectangle is not divided into four equal parts.

**Question 4.**

**Solution:**

(i) Three-fourths = \(\\ \frac { 3 }{ 4 } \)

(ii) Four-sevenths = \(\\ \frac { 4 }{ 7 } \)

(iii) Two-fifths = \(\\ \frac { 2 }{ 5 } \)

(iv) Three-tenths = \(\\ \frac { 3 }{ 10 } \)

(v) One-eighth = \(\\ \frac { 1 }{ 8 } \)

(vi) three-tenths = \(\\ \frac { 5 }{ 6 } \)

(vii) five-sixths = \(\\ \frac { 8 }{ 9 } \)

(vii) seven-twelfths = \(\\ \frac { 7 }{ 12 } \)

**Question 5.**

**Solution:**

(i) In \(\\ \frac { 4 }{ 9 } \), numerator is 4 and denominator is 9.

(ii) In \(\\ \frac { 6 }{ 11 } \), numerator is 6 and denominator is 11.

(iii) In \(\\ \frac { 8 }{ 15 } \), numerator is 8 and denominator is 15.

(iv) In \(\\ \frac { 12 }{ 17 } \), numerator is 12 and denominator is 17.

(v) \(\\ \frac { 5 }{ 1 } \) , numerator is 5 and denominator is 1.

**Question 6.**

**Solution:**

(z) Numerator = 3, Denominator = 8, then fraction = \(\\ \frac { 3 }{ 8 } \).

(ii) Numerator = 5, Denominator = 12, then fraction = \(\\ \frac { 5 }{ 12 } \)

(iii) Numerator = 7, Denominator = 16, then fraction = \(\\ \frac { 7 }{ 16 } \).

(iv) Numerator = 8, Denominator = 15, then fraction = \(\\ \frac { 8 }{ 15 } \)

**Question 7.**

**Solution:**

(i) \(\\ \frac { 2 }{ 3 } \) = two-thirds

(ii) \(\\ \frac { 4 }{ 9 } \) = four-ninths

(iii) \(\\ \frac { 2 }{ 5 } \) = two-fifths

(iv) \(\\ \frac { 7 }{ 10 } \) = seven-tenths

(v) \(\\ \frac { 1 }{ 3 } \) = one-thirds

(vi) \(\\ \frac { 3 }{ 4 } \) = three-fourth

(vii) \(\\ \frac { 3 }{ 8 } \) = three-eighths

(viii) \(\\ \frac { 9 }{ 14 } \) = nine-fourteenths

(ix) \(\\ \frac { 5 }{ 11 } \) = five-elevanths

(x) \(\\ \frac { 6 }{ 15 } \) = six-fifteenths

**Question 8.**

**Solution:**

24 minutes is the fraction of 1 hour i.e.,

60 minutes = \(\\ \frac { 24 }{ 60 } \)

**Question 9.
**

**Solution:**

Natural number between 2 to 10 are 2, 3, 4, 5, 6, 7, 8, 9, 10 = 9

Out of these prime number are 2, 3, 5, 7 = 4

Fraction = \(\\ \frac { 4 }{ 9 } \)

**Question 10.**

**Solution:**

(i) \(\\ \frac { 2 }{ 3 } \) of 15 pens = \(\\ \frac { 2 }{ 3 } \) x 15 = 2 x 5 = 10 pens.

(ii) \(\\ \frac { 2 }{ 3 } \) of 27 balls = \(\\ \frac { 2 }{ 3 } \) x 27 = 2 x 9 = 18 balls.

(iii) \(\\ \frac { 2 }{ 3 } \) of 36 balloons = \(\\ \frac { 2 }{ 3 } \) x 36 = 2 x 12 = 24 balloons. Ans.

**Question 11.**

**Solution:**

(i) \(\\ \frac { 3 }{ 4 } \) of 16 cups = \(\\ \frac { 3 }{ 4 } \) x 16 = 3 x 4

= 12 cups.

(ii) \(\\ \frac { 3 }{ 4 } \) of 28 rackets = \(\\ \frac { 3 }{ 4 } \) x 28 = 3 x 7

= 21 rackets.

(iii) \(\\ \frac { 3 }{ 4 } \) of 32 books = \(\\ \frac { 3 }{ 4 } \) x 32 = 3 x 8

= 24 books. Ans.

**Question 12.**

**Solution:**

Total number of pencils Neelam has = 25

No. of pencils given to Meena

= \(\\ \frac { 4 }{ 5 } \) of 25

= \(\\ \frac { 4 }{ 5 } \) x 25 – 20

No. of pencils left with Neelam = 25 – 20 = 5

**Question 13.**

**Solution:**

(i) \(\\ \frac { 3 }{ 8 } \)

Take a line segment OA = one unit of length

Divide it into 8 equal parts and take 3 parts at P, then P represents \(\\ \frac { 3 }{ 8 } \).

(ii) \(\\ \frac { 5 }{ 9 } \)

(a) Take a line segment OA = one unit of length.

(b) Divide it into nine equal parts and take 5 parts at P, then P represents \(\\ \frac { 5 }{ 9 } \).

(iii) \(\\ \frac { 4 }{ 7 } \)

(a) Take a line segment OA = one unit of length.

(b) Divide it into 7 equal parts and take 4 parts at P then P represents \(\\ \frac { 4 }{ 7 } \).

(iv) \(\\ \frac { 2 }{ 5 } \)

(a) Take a line segment OA = 1 unit of length.

(b) Divide it with 5 equal parts and take 2 parts and P then P represents \(\\ \frac { 2 }{ 5 } \).

(v) \(\\ \frac { 1 }{ 4 } \)

(a) Take a line segment OA = 1 unit of length.

(b) Divide it with 4 equal parts and take 1 parts and P then P represents \(\\ \frac { 1 }{ 4 } \).

Hope given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5A are helpful to complete your math homework.

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