RS Aggarwal Maths Solutions Class 6

RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5E

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5E.

Other Exercises

• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5A
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5B
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5C
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5D
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5E
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5F
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5G

Find the sum :

Question 1.
Solution:
\(\frac { 5 }{ 8 } +\frac { 1 }{ 8 } \)

Question 2.
Solution:
\(\frac { 4 }{ 9 } +\frac { 8 }{ 9 } \)

Question 3.
Solution:
\(1\frac { 3 }{ 5 } +2\frac { 4 }{ 5 } \)
\(\frac { 8 }{ 5 } +\frac { 14 }{ 5 } \)

Question 4.
Solution:
\(\frac { 2 }{ 5 } +\frac { 5 }{ 6 } \)
= \(\\ \frac { 4+15 }{ 18 } \) (LCM of 9 and 6 = 18)
= \(\\ \frac { 19 }{ 18 } \)
= \(1 \frac { 1 }{ 18 } \)

Question 5.
Solution:
\(\frac { 7 }{ 12 } +\frac { 9 }{ 16 } \)

Question 6.
Solution:
\(\frac { 4 }{ 15 } +\frac { 17 }{ 20 } \)

Question 7.
Solution:
\(2\frac { 3 }{ 4 } +5\frac { 5 }{ 6 } \)
= \(\frac { 11 }{ 4 } +\frac { 35 }{ 6 } \)

Question 8.
Solution:
\(3\frac { 1 }{ 8 } +1\frac { 5 }{ 12 } \)
= \(\frac { 25 }{ 8 } +\frac { 17 }{ 12 } \)

Question 9.
Solution:
\(2\frac { 7 }{ 10 } +3\frac { 8 }{ 15 } \)
= \(\frac { 27 }{ 10 } +\frac { 53 }{ 15 } \)

Question 10.
Solution:
\(3\frac { 2 }{ 3 } +1\frac { 5 }{ 6 } +2 \)
\(\frac { 11 }{ 3 } +\frac { 11 }{ 6 } +\frac { 2 }{ 1 } \)

Question 11.
Solution:
\(3+1\frac { 4 }{ 15 } +1\frac { 3 }{ 20 } \)
=\(\frac { 3 }{ 1 } +\frac { 19 }{ 15 } +\frac { 23 }{ 20 } \)

Question 12.
Solution:
\( 3\frac { 1 }{ 3 } +4\frac { 1 }{ 4 } +6\frac { 1 }{ 6 } \)
\(\frac { 10 }{ 3 } +\frac { 17 }{ 4 } +\frac { 37 }{ 6 } \)
(changing into improper fractions)

Question 13.
Solution:
\(\frac { 2 }{ 3 } +3\frac { 1 }{ 6 } +4\frac { 2 }{ 9 } +2\frac { 5 }{ 18 } \)
\(\frac { 2 }{ 3 } +\frac { 19 }{ 6 } +\frac { 38 }{ 9 } +\frac { 41 }{ 18 } \)

Question 14.
Solution:
\(2\frac { 1 }{ 3 } +1\frac { 1 }{ 4 } +2\frac { 5 }{ 6 } +3\frac { 7 }{ 12 } \)

Question 15.
Solution:
\(2+\frac { 3 }{ 4 } +1\frac { 5 }{ 6 } +3\frac { 7 }{ 16 } \)
\(\frac { 2 }{ 1 } +\frac { 3 }{ 4 } +\frac { 13 }{ 8 } +\frac { 55 }{ 16 } \)

Question 16.
Solution:
Cost of a pencil = Rs. \(3 \frac { 2 }{ 5 } \)
Cost of an eraser = Rs.\(2 \frac { 7 }{ 10 } \)

Question 17.
Solution:
Length of cloth for kurta = \(4 \frac { 1 }{ 2 } \) metres
Length of cloth for pyjamas = \(2 \frac { 2 }{ 3 } \) metres

Question 18.
Solution:
Distance travelled by Rickshaw = \(4 \frac { 3 }{ 4 } \) km
Distance travelled on foot = \(1 \frac { 1 }{ 2 } \) km

Question 19.
Solution:
Weight of empty cylinder = \(16 \frac { 4 }{ 5 } \) kg
Weight of gas filled in it = \(14 \frac { 2 }{ 3 } \) kg
Total. weight of cylinder with gas

Hope given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5E are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5D

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5D.

Other Exercises

• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5A
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5B
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5C
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5D
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5E
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5F
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5G

Question 1.
Solution:
(i) Like fraction : Fractions having the same denominators are called like fractions. For examples:
\(\frac { 2 }{ 11 } ,\frac { 3 }{ 11 } ,\frac { 4 }{ 11 } ,\frac { 5 }{ 11 } ,\frac { 8 }{ 11 } \)
(ii) Unlike fraction : Fraction having the different denominators, are called unlike fractions. For examples:
\(\frac { 1 }{ 3 } ,\frac { 4 }{ 7 } ,\frac { 5 }{ 9 } ,\frac { 3 }{ 8 } ,\frac { 7 }{ 11 } \)

Question 2.
Solution:
We know that like fractions have same denominator
Now \(\frac { 3 }{ 5 } ,\frac { 7 }{ 10 } ,\frac { 8 }{ 15 } ,\frac { 11 }{ 30 } \)
LCM of 5, 10, 15 and 30 = 30

Question 3.
Solution:
We know that like fraction have same denominators
\(\frac { 1 }{ 4 } ,\frac { 5 }{ 8 } ,\frac { 7 }{ 12 } ,\frac { 13 }{ 24 } \)
LCM of 4, 8, 12, 24 = 24

Question 4.
Solution:

Question 5.
Solution:

Compare the fractions given below :

Question 6.
Solution:
\(\frac { 4 }{ 5 } and\frac { 5 }{ 7 } \)
LCM of 5 and 7 = 35

Question 7.
Solution:
\(\frac { 3 }{ 8 } and\frac { 5 }{ 6 } \)
LCM of 8 and 6 = 24

Question 8.
Solution:
\(\frac { 7 }{ 11 } and\frac { 6 }{ 7 } \)
LCM of 11 and 7 = 77

Question 9.
Solution:
\(\frac { 5 }{ 6 } and\frac { 9 }{ 11 } \)
LCM of 6 and 11 = 66

Question 10.
Solution:
\(\frac { 2 }{ 3 } and\frac { 4 }{ 9 } \)
LCM of 3 and 9 = 9

Question 11.
Solution:
\(\frac { 6 }{ 13 } and\frac { 3 }{ 4 } \)
LCM of 13 and 4 = 52

Question 12.
Solution:
\(\frac { 3 }{ 4 } and\frac { 5 }{ 6 } \)
LCM of 4 and 6 = 12

Question 13.
Solution:
\(\frac { 5 }{ 8 } and\frac { 7 }{ 12 } \)
LCM of 8 and 12 = 24

Question 14.
Solution:
\(\frac { 4 }{ 9 } and\frac { 5 }{ 6 } \)
LCM of 9 and 6 = 18

Question 15.
Solution:
\(\frac { 4 }{ 5 } and\frac { 7 }{ 10 } \)
LCM of 5 and 10 = 10

Question 16.
Solution:
\(\frac { 7 }{ 8 } and\frac { 9 }{ 10 } \)
LCM of 8 and 10 = 40

Question 17.
Solution:
\(\frac { 11 }{ 12 } and\frac { 13 }{ 15 } \)
LCM of 12 and 15 = 60

Question 18.
Solution:
\(\frac { 1 }{ 2 } ,\frac { 3 }{ 4 } ,\frac { 5 }{ 6 } and\frac { 7 }{ 8 } \)
LCM of 2, 4, 6 and 8 = 24

Question 19.
Solution:
\(\frac { 2 }{ 3 } ,\frac { 5 }{ 6 } ,\frac { 7 }{ 9 } and\frac { 11 }{ 18 } \)
LCM of 3, 6, 9 and 18 = 18

Question 20.
Solution:
\(\frac { 2 }{ 5 } ,\frac { 7 }{ 10 } ,\frac { 11 }{ 15 } and\frac { 17 }{ 30 } \)
LCM of 5, 10, 15 and 30 = 30

Question 21.
Solution:
\(\frac { 3 }{ 4 } ,\frac { 7 }{ 8 } ,\frac { 11 }{ 16 } and\frac { 23 }{ 32 } \)
LCM of 4, 8, 16 and 32 = 32

Arrange the following fractions in the descending order :

Question 22.
Solution:
\(\frac { 3 }{ 4 } ,\frac { 5 }{ 8 } ,\frac { 11 }{ 12 } and\frac { 17 }{ 24 } \)
LCM of 4, 8, 12 and 24 = 24

Question 23.
Solution:
\(\frac { 7 }{ 9 } ,\frac { 5 }{ 12 } ,\frac { 11 }{ 18 } and\frac { 17 }{ 36 } \)
LCM of 9, 12, 18 and 36 = 36

Question 24.
Solution:
\(\frac { 2 }{ 3 } ,\frac { 3 }{ 5 } ,\frac { 7 }{ 10 } and\frac { 8 }{ 15 } \)
LCM of 3, 5, 10 and 15 = 30

Question 25.
Solution:
\(\frac { 5 }{ 7 } ,\frac { 9 }{ 14 } ,\frac { 17 }{ 21 } and\frac { 31 }{ 42 } \)
LCM of 7, 14, 21 and 42 = 42

Question 26.
Solution:
∴ the numerators are equal
∴ The fraction having small denominator is greater than the fraction having large denominator
∴ In descending order, we can write
\(\frac { 1 }{ 12 } ,\frac { 1 }{ 23 } ,\frac { 1 }{ 7 } ,\frac { 1 }{ 9 } ,\frac { 1 }{ 17 } ,\frac { 1 }{ 50 } \)

Question 27.
Solution:
Here, the numerators of all fractions are equal
∴ The fraction having small denominator is greater than the fraction having large denominator
Now in descending order is
\(\frac { 3 }{ 4 } ,\frac { 3 }{ 5 } ,\frac { 3 }{ 7 } ,\frac { 3 }{ 11 } ,\frac { 3 }{ 13 } ,\frac { 3 }{ 17 } \)

Question 28.
Solution:
Lalita read 30 pages of a book containing 100 pages
She read \(\\ \frac { 30 }{ 100 } \) = \(\\ \frac { 3 }{ 10 } \) part of the book and Sarita read \(\\ \frac { 2 }{ 5 } \) of the book
Now in \(\\ \frac { 3 }{ 10 } \) and \(\\ \frac { 2 }{ 5 } \), LCM of 10, 5 = 10
\(\\ \frac { 3 }{ 10 } \) = \(\\ \frac { 3 }{ 10 } \)
\(\\ \frac { 2 }{ 5 } \) = \(\\ \frac { 2\times 2 }{ 5\times 2 } \) = \(\\ \frac { 4 }{ 10 } \)
From above, Sarita read more
as \(\\ \frac { 4 }{ 10 } \) or \(\frac { 2 }{ 5 } >\frac { 3 }{ 10 } \)

Question 29.
Solution:
Rafiq exercised for \(\\ \frac { 2 }{ 3 } \) hour and Rohit exercised for \(\\ \frac { 3 }{ 4 } \) hour
In \(\\ \frac { 2 }{ 3 } \) and \(\\ \frac { 3 }{ 4 } \), LCM of 3 and 4 = 12
\(\\ \frac { 2 }{ 3 } \) = \(\\ \frac { 2\times 4 }{ 3\times 4 } \) = \(\\ \frac { 8 }{ 12 } \)
\(\\ \frac { 3 }{ 4 } \) = \(\\ \frac { 3\times 3 }{ 4\times 3 } \) = \(\\ \frac { 9 }{ 12 } \)
\(\frac { 9 }{ 12 } >\frac { 8 }{ 12 } \)
=> \(\frac { 3 }{ 4 } >\frac { 2 }{ 3 } \)
∴ Rohit exercised more time

Question 30.
Solution:
In VI A, 20 student passed out of 25 or \(\\ \frac { 20 }{ 25 } \) or \(\\ \frac { 4 }{ 5 } \) students passed
But in VI B, 24 out of 30 passed 24 or \(\\ \frac { 24 }{ 30 } \) or \(\\ \frac { 4 }{ 5 } \) students passed
Now \(\\ \frac { 4 }{ 5 } \) = \(\\ \frac { 4 }{ 5 } \)
∴ Both sections gave same result

Hope given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5D are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5C

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5C.

Other Exercises

• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5A
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5B
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5C
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5D
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5E
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5F
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5G

Question 1.
Solution:
(i) \(\\ \frac { 2 }{ 3 } \)
= \(\\ \frac { 2X2 }{ 3X2 } \)
= \(\\ \frac { 4 }{ 6 } \)

Question 2.
Solution:
(i) In \(\\ \frac { 5 }{ 6 } \) and \(\\ \frac { 20 }{ 24 } \)
\(\\ \frac { 5 }{ 6 } \) = \(\\ \frac { 20 }{ 24 } \)

Question 3.
Solution:
Equivalent fraction of \(\\ \frac { 3 }{ 5 } \) having
(i) Denominator = 30 and 30 = 5 x 6

Question 4.
Solution:
(i) Denominator = 54, and 54 = 9 x 6

Question 5.
Solution:
Equivalent fraction of \(\\ \frac { 6 }{ 11 } \) having
(i) Denominator = 77 and 77 = 11 = 7
\(\\ \frac { 6 }{ 11 } \)
= \(\\ \frac { 6X7 }{ 11X7 } \)
= \(\\ \frac { 42 }{ 77 } \)
(ii) Numerator = 60 and 60 = 6 x 10
\(\\ \frac { 6 }{ 11 } \)
= \(\\ \frac { 6X10 }{ 11X10 } \)
= \(\\ \frac { 60 }{ 110 } \)

Question 6.
Solution:
Let \(\\ \frac { 24 }{ 30 } \) = \(\\ \frac { 4 }{ x } \)
In order to get 4, divide 24 by 6,

Question 7.
Solution:
Equivalent fraction of \(\\ \frac { 36 }{ 48 } \), with
(i) Numerator 9 and 9 = 36 + 4
\(\frac { 36 }{ 48 } =\frac { 36\div 4 }{ 48\div 4 } =\frac { 9 }{ 12 } \)
(ii) Denominator = 4 and 4 = 48 ÷ 12
\(\frac { 36 }{ 48 } =\frac { 36\div 12 }{ 48\div 12 } =\frac { 3 }{ 4 } \)

Question 8.
Solution:
Equivalent fraction of \(\\ \frac { 56 }{ 70 } \) with
(i) Numerator 4 and = 56 ÷ 14
\(\frac { 56 }{ 70 } =\frac { 56\div 14 }{ 70\div 14 } =\frac { 4 }{ 5 } \)
(ii) Denominator =10 and 10 = 70 ÷ 7
\(\frac { 56 }{ 70 } =\frac { 56\div 7 }{ 70\div 7 } =\frac { 8 }{ 10 } \)

Question 9.
Solution:
(i) In \(\\ \frac { 9 }{ 15 } \), HCF of 9 and 15 = 3
Now, dividing each term by 3, we get:
\(\frac { 9 }{ 15 } =\frac { 9\div 3 }{ 15\div 3 } =\frac { 3 }{ 5 } \)

Question 10.
Solution:
We know that a fraction is in its simplest form if its HCF of numerator and denominator is 1.

Question 11.
Solution:

Hope given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5C are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5B

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5B.

Other Exercises

• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5A
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5B
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5C
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5D
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5E
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5F
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5G

Question 1.
Solution:
We know that, a fraction is proper if its denominator is greater than its numerator. Therefore,
\(\\ \frac { 1 }{ 2 } \), \(\\ \frac { 3 }{ 5 } \) and \(\\ \frac { 10 }{ 11 } \) are proper fractions. Ans.

Question 2.
Solution:
We know that a fraction is improper if its denominator is less than its numerator
Therefore,

are improper fractions. Ans.

Question 3.
Solution:
Six improper fractions with denominator 5 can be

Question 4.
Solution:
Six improper fraction with denominator 13 can be

Question 5.
Solution:

Question 6.
Solution:

Question 7.
Solution:

Question 8.
Solution:

Hope given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5B are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 6 Solutions Chapter 5 Fractions Ex 5A

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5A.

Other Exercises

• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5A
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5B
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5C
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5D
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5E
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5F
• RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5G

Question 1.
Solution:
(i) \(\\ \frac { 3 }{ 4 } \)
(ii) \(\\ \frac { 1 }{ 4 } \)
(iii) \(\\ \frac { 2 }{ 3 } \)
(iv) \(\\ \frac { 3 }{ 10 } \)
(v) \(\\ \frac { 4 }{ 9 } \)
(vi) \(\\ \frac { 3 }{ 8 } \)

Question 2.
Solution:
In the figure, \(\\ \frac { 4 }{ 9 } \) is shaded

Question 3.
Solution:
In the figure, whole rectangle is not divided into four equal parts.

Question 4.
Solution:
(i) Three-fourths = \(\\ \frac { 3 }{ 4 } \)
(ii) Four-sevenths = \(\\ \frac { 4 }{ 7 } \)
(iii) Two-fifths = \(\\ \frac { 2 }{ 5 } \)
(iv) Three-tenths = \(\\ \frac { 3 }{ 10 } \)
(v) One-eighth = \(\\ \frac { 1 }{ 8 } \)
(vi) three-tenths = \(\\ \frac { 5 }{ 6 } \)
(vii) five-sixths = \(\\ \frac { 8 }{ 9 } \)
(vii) seven-twelfths = \(\\ \frac { 7 }{ 12 } \)

Question 5.
Solution:
(i) In \(\\ \frac { 4 }{ 9 } \), numerator is 4 and denominator is 9.
(ii) In \(\\ \frac { 6 }{ 11 } \), numerator is 6 and denominator is 11.
(iii) In \(\\ \frac { 8 }{ 15 } \), numerator is 8 and denominator is 15.
(iv) In \(\\ \frac { 12 }{ 17 } \), numerator is 12 and denominator is 17.
(v) \(\\ \frac { 5 }{ 1 } \) , numerator is 5 and denominator is 1.

Question 6.
Solution:
(z) Numerator = 3, Denominator = 8, then fraction = \(\\ \frac { 3 }{ 8 } \).
(ii) Numerator = 5, Denominator = 12, then fraction = \(\\ \frac { 5 }{ 12 } \)
(iii) Numerator = 7, Denominator = 16, then fraction = \(\\ \frac { 7 }{ 16 } \).
(iv) Numerator = 8, Denominator = 15, then fraction = \(\\ \frac { 8 }{ 15 } \)

Question 7.
Solution:
(i) \(\\ \frac { 2 }{ 3 } \) = two-thirds
(ii) \(\\ \frac { 4 }{ 9 } \) = four-ninths
(iii) \(\\ \frac { 2 }{ 5 } \) = two-fifths
(iv) \(\\ \frac { 7 }{ 10 } \) = seven-tenths
(v) \(\\ \frac { 1 }{ 3 } \) = one-thirds
(vi) \(\\ \frac { 3 }{ 4 } \) = three-fourth
(vii) \(\\ \frac { 3 }{ 8 } \) = three-eighths
(viii) \(\\ \frac { 9 }{ 14 } \) = nine-fourteenths
(ix) \(\\ \frac { 5 }{ 11 } \) = five-elevanths
(x) \(\\ \frac { 6 }{ 15 } \) = six-fifteenths

Question 8.
Solution:
24 minutes is the fraction of 1 hour i.e.,
60 minutes = \(\\ \frac { 24 }{ 60 } \)

Question 9.
Solution:
Natural number between 2 to 10 are 2, 3, 4, 5, 6, 7, 8, 9, 10 = 9
Out of these prime number are 2, 3, 5, 7 = 4
Fraction = \(\\ \frac { 4 }{ 9 } \)

Question 10.
Solution:
(i) \(\\ \frac { 2 }{ 3 } \) of 15 pens = \(\\ \frac { 2 }{ 3 } \) x 15 = 2 x 5 = 10 pens.
(ii) \(\\ \frac { 2 }{ 3 } \) of 27 balls = \(\\ \frac { 2 }{ 3 } \) x 27 = 2 x 9 = 18 balls.
(iii) \(\\ \frac { 2 }{ 3 } \) of 36 balloons = \(\\ \frac { 2 }{ 3 } \) x 36 = 2 x 12 = 24 balloons. Ans.

Question 11.
Solution:
(i) \(\\ \frac { 3 }{ 4 } \) of 16 cups = \(\\ \frac { 3 }{ 4 } \) x 16 = 3 x 4
= 12 cups.
(ii) \(\\ \frac { 3 }{ 4 } \) of 28 rackets = \(\\ \frac { 3 }{ 4 } \) x 28 = 3 x 7
= 21 rackets.
(iii) \(\\ \frac { 3 }{ 4 } \) of 32 books = \(\\ \frac { 3 }{ 4 } \) x 32 = 3 x 8
= 24 books. Ans.

Question 12.
Solution:
Total number of pencils Neelam has = 25
No. of pencils given to Meena
= \(\\ \frac { 4 }{ 5 } \) of 25
= \(\\ \frac { 4 }{ 5 } \) x 25 – 20
No. of pencils left with Neelam = 25 – 20 = 5

Question 13.
Solution:
(i) \(\\ \frac { 3 }{ 8 } \)
Take a line segment OA = one unit of length
Divide it into 8 equal parts and take 3 parts at P, then P represents \(\\ \frac { 3 }{ 8 } \).

(ii) \(\\ \frac { 5 }{ 9 } \)
(a) Take a line segment OA = one unit of length.
(b) Divide it into nine equal parts and take 5 parts at P, then P represents \(\\ \frac { 5 }{ 9 } \).

(iii) \(\\ \frac { 4 }{ 7 } \)
(a) Take a line segment OA = one unit of length.
(b) Divide it into 7 equal parts and take 4 parts at P then P represents \(\\ \frac { 4 }{ 7 } \).

(iv) \(\\ \frac { 2 }{ 5 } \)
(a) Take a line segment OA = 1 unit of length.
(b) Divide it with 5 equal parts and take 2 parts and P then P represents \(\\ \frac { 2 }{ 5 } \).

(v) \(\\ \frac { 1 }{ 4 } \)
(a) Take a line segment OA = 1 unit of length.
(b) Divide it with 4 equal parts and take 1 parts and P then P represents \(\\ \frac { 1 }{ 4 } \).

Hope given RS Aggarwal Solutions Class 6 Chapter 5 Fractions Ex 5A are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.