RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2B

RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2B

These Solutions are part of RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 2 Exponents Ex 2B.

Other Exercises

Question 1.
Solution:
(i) 57.36 = 5.736 x 101
(ii) 3500000 = 3.5 x 106
(iii) 273000 = 2.73 x 105
(iv) 168000000 = 1.68 x 108
(v) 4630000000000 = 4.63 x 1012
(vi) 345 x 105 = 3.45 x 102 x 105 = 3.45 x 107

Question 2.
Solution:
(i) 3.74 x 105
= \(\\ \frac { 374 }{ 100 } \) x 105
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2B Q2.1
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2B Q2.2

Question 3.
Solution:
(i) Height of Mount Everest = 8848 m
= 8.848 x 1000
= 8.848 x 103
(ii) Speed of light = 300000000 m/sec.
= 3.00000000 x 100000000
= (3 x 108) m/sec.
(iii) Distance between the earth and the sun = 149600000000 m
= (1.49600000000 x 100000000000)m = (1.496 x 1011) m

Question 4.
Solution:
Mass of earth = (15.97 x 1024) kg
and mass of moon = (7.35 x 1022) kg
= Total mass of earth and moon
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2B Q4.1

Question 5.
Solution:
(i) 0.0006
= \(\\ \frac { 6 }{ 10000 } \) = \(\frac { 6 }{ { 10 }^{ 4 } }\) = 6.10-4
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2B Q5.1
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2B Q5.2

Question 6.
Solution:
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2B Q6.1

Question 7.
Solution:
(i) 2.06 x 10-5
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2B Q7.1
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2B Q7.2

RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2B Q7.3

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RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A

RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A3

These Solutions are part of RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 2 Exponents Ex 2A.

Other Exercises

Question 1.
Solution:
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A 1
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q1.2

Question 2.
Solution:
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q2.1
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q2.2

Question 3.
Solution:
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q3.1
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q3.2

Question 4.
Solution:
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q4.1
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q4.2

Question 5.
Solution:
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q5.1

Question 6.
Solution:
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q6.1

Question 7.
Solution:
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q7.1

Question 8.
Solution:
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q8.1

Question 9.
Solution:
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q9.1

Question 10.
Solution:
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q10.1

Question 11.
Solution:
Let x be the required number which is multiplied
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q11.1

Question 12.
Solution:
Let x be the required number
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q12.1

Question 13.
Solution:
52x+1 ÷ 25 = 125
RS Aggarwal Class 8 Solutions Chapter 2 Exponents Ex 2A Q13.1

Hope given RS Aggarwal Solutions Class 8 Chapter 2 Exponents Ex 2A are helpful to complete your math homework.

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RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H

RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H

These Solutions are part of RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1H.

Other Exercises

Objective Questions :
Tick the correct answer in each of the following :

Question 1.
Solution:
Answer = (c)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q1.1

Question 2.
Solution:
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q2.1

Question 3.
Solution:
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q3.1

Question 4.
Solution:
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q4.1

Question 5.
Solution:
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q5.1

Question 6.
Solution:
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q6.1

Question 7.
Solution:
Answer = (b)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q7.1

Question 8.
Solution:
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q8.1

Question 9.
Solution:
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q9.1

Question 10.
Solution:
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q10.1

Question 11.
Solution:
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q11.1

Question 12.
Solution:
Product of two numbers = \(\\ \frac { -28 }{ 81 } \)
One number = \(\\ \frac { 14 }{ 27 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q12.1

Question 13.

Solution:
Answer = (c)
Let x be the required number, then
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q13.1

Question 14.
Solution:
Answer = (d)
Let x is to be subtracted then
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q14.1

Question 15.
Solution:
Answer = (c)
sum = -3,one number = \(\\ \frac { -10 }{ 3 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q15.1

Question 16.
Solution:
Answer = (c)
We know that a number is called in standard form if the numerator and denominator has no common divisor except 1.
\(\\ \frac { -9 }{ 6 } \) is in standard form.

Question 17.
Solution:
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q17.1

Question 18.
Solution:
Answer = (b)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q18.1

Question 19.
Solution:
Answer = (d)
Let x is required rational
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q19.1

Question 20.
Solution:
Additive inverse of \(\\ \frac { -5 }{ 9 } \) is = – \(\left( \frac { -5 }{ 9 } \right) \)

Question 21.
Solution:
Reciprocal of \(\\ \frac { -3 }{ 4 } \) is \(\\ \frac { -4 }{ 3 } \)

Question 22.
Solution:
A rational number between = \(\\ \frac { -2 }{ 3 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1H Q22.1

Question 23.

Solution:
Answer: (b)
The reciprocal of a negative rational
the number is also a negative rational number.

Hope given RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1H are helpful to complete your math homework.

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RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G

RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G

These Solutions are part of RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1G.

Other Exercises

Question 1.
Solution:
Total length of rope = 11 m.
Sum of lengths of two parts
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q1.1

Question 2.
Solution:
Total weight of rice and drum
= \(40\frac { 1 }{ 6 } \) kg
= \(13\frac { 3 }{ 4 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q2.1

Question 3.
Solution:
Total weight of three types of fruits
= \(19\frac { 1 }{ 3 } \) kg
= \(\\ \frac { 58 }{ 3 } \) kg
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q3.1

Question 4.
Solution:
Total earnings = Rs 160
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q4.1
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q4.2

Question 5.
Solution:
Cost of 1m cloth = Rs \(63\frac { 3 }{ 4 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q5.1

Question 6.
Solution:
Distance covered in 1 hour
= \(60\frac { 2 }{ 5 } \)
= \(\\ \frac { 302 }{ 5 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q6.1

Question 7.
Solution:
Length of rectangular park
= \(36\frac { 3 }{ 5 } \) m
= \(\\ \frac { 183 }{ 5 } \)
and breadth = \(16\frac { 2 }{ 3 } \) = \(\\ \frac { 50 }{ 3 } \) m
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q7.1

Question 8.
Solution:
Side of a square plot = \(8\frac { 1 }{ 2 } \) m
= \(\\ \frac { 17 }{ 2 } \) m
Area = (Side)² = Side x Side
= \(\\ \frac { 17 }{ 2 } \) x \(\\ \frac { 17 }{ 2 } \) m²
= \(\\ \frac { 289 }{ 4 } \) m²
= \(72\frac { 1 }{ 4 } \) m²

Question 9.
Solution:
Cost of 1 litre petrol = Rs \(63\frac { 3 }{ 4 } \)
= Rs \(\\ \frac { 255 }{ 4 } \)
Cost of 34 litres of petrol
= \(\\ \frac { 255 }{ 4 } \) x 34
= \(\\ \frac { 255X17 }{ 2 } \)
= \(\\ \frac { 4335 }{ 2 } \)
= Rs \(2167\frac { 1 }{ 2 } \)

Question 10.
Solution:
Distance covered in 1 hour = 1020 km.
Distance covered in \(4\frac { 1 }{ 6 } \) hours
= 1020 x \(4\frac { 1 }{ 6 } \)
= 1020 x \(\\ \frac { 25 }{ 6 } \) km
= \(\\ \frac { 25500 }{ 6 } \)
= 4250 km. Ans.

Question 11.
Solution:
Cost of \(3\frac { 1 }{ 2 }\) metres cloth
= Rs \(166\frac { 1 }{ 4 }\)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q11.1

Question 12.
Solution:
Total length of piece of chord
= \(71\frac { 1 }{ 2 }\)
No. of pieces = 26
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q12.1

Question 13.
Solution:
Area of a room = \(65\frac { 1 }{ 4 }\) m²
Breadth = \(5\frac { 7 }{ 16 }\) m
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q13.1

Question 14.
Solution:
Product of two fractions = \(9\frac { 3 }{ 5 }\)
= \(\\ \frac { 48 }{ 5 } \)
One fraction = \(9\frac { 3 }{ 7 }\) = \(\\ \frac { 66 }{ 7 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q14.1

Question 15.
Solution:
Let total number of students =1
and no.of boys = \(\\ \frac { 5 }{ 8 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q15.1

Question 16.
Solution:
Let no of pages = 1
Then no. of pages read = \(\\ \frac { 7 }{ 9 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q16.1

Question 17.
Solution:
Total amount, Rita has = Rs 300
Amount spent on notebooks = \(\\ \frac { 1 }{ 3 } \) of 300
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q17.1

Question 18.
Solution:
Total amount earned by Amit = Rs 32000
Amount spent on food = \(\\ \frac { 1 }{ 4 } \) of Rs 32000
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q18.1

Question 19.
Solution:
Let number = 1
Then difference between \(\\ \frac { 3 }{ 5 } \) and \(\\ \frac { 2 }{ 7 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q19.1

Question 20.
Solution:
Let total number of spectators = 1
No. of spectators in covered place = \(\\ \frac { 2 }{ 7 } \) of
1 = \(\\ \frac { 2 }{ 7 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1G Q20.1

Hope given RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1G are helpful to complete your math homework.

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RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1F

RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1F

These Solutions are part of RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1F.

Other Exercises

Question 1.
Solution:
Rational number between \(\\ \frac { 1 }{ 4 } \) and \(\\ \frac { 1 }{ 3 } \)
= \(\\ \frac { 1 }{ 2 } \) \(\left[ \frac { 1 }{ 4 } +\frac { 1 }{ 3 } \right] \)
= \(\\ \frac { 1 }{ 2 } \) \(\left[ \frac { 3+4 }{ 12 } \right] \)
= \(\\ \frac { 1 }{ 2 } \) x \(\\ \frac { 7 }{ 12 } \)
= \(\\ \frac { 7 }{ 24 } \)

Question 2.
Solution:
Solution. Rational number between 2 and 3
= \(\\ \frac { 1 }{ 2 } \)(2 + 3)
= \(\\ \frac { 1 }{ 2 } \) x 5
= \(\\ \frac { 5 }{ 2 } \)

Question 3.
Solution:
Rational number between \(\\ \frac { -1 }{ 3 } \) and \(\\ \frac { 1 }{ 2 } \)
= \(\\ \frac { 1 }{ 2 } \) \(\left[ \frac { -1 }{ 3 } +\frac { 1 }{ 2 } \right] \)
= \(\\ \frac { 1 }{ 2 } \) \(\left[ \frac { -2+3 }{ 6 } \right] \)
= \(\\ \frac { 1 }{ 2 } \) x \(\\ \frac { 1 }{ 6 } \)
= \(\\ \frac { 1 }{ 12 } \)

Question 4.
Solution:
First rational number between -3 and -2
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1F Q4.1

Question 5.
Solution:
First rational number between 4 and 5
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1F Q5.1

Question 6.
Solution:
First rational numbers between \(\\ \frac { 2 }{ 3 } \) and \(\\ \frac { 3 }{ 4 } \)
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1F Q6.1

Question 7.
Solution:
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1F Q7.1

Question 8.
Solution:
– 1 = \(\\ \frac { -5 }{ 5 } \) and 2 = \(\\ \frac { 10 }{ 5 } \)
12 rational number between – 1 and 2 can be
RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1F Q8.1

Hope given RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1F are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.