NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.5

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.5 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.5.

BoardCBSE
TextbookNCERT
ClassClass 6
SubjectMaths
ChapterChapter 7
Chapter NameFractions
Exercise Ex 7.5
Number of Questions Solved5
CategoryNCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.5

Question 1.
Write these fractions appropriately as additions or subtractions:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 84
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 85
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 86
Question 2.
Solve
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 87
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 88
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 89

Question 3.
Shubham painted \(\frac { 2 }{ 3 }\) of the wall space in his room. Her sister Madhavi helped and painted \(\frac { 1 }{ 3 }\) of the wall space. How much did they paint together?
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 90
Hence, they painted together with the complete wall space. ,

Question 4.
Fill in the missing fractions :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 91
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 92
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 93
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 94
Question 5.
Javed was given \(\frac { 5 }{ 7 }\) of a basket of oranges. What fraction of oranges was left in the basket?
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 95
Hence, fraction \(\frac { 2 }{ 7 }\) of oranges was left in the basket.

 

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NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4.

BoardCBSE
TextbookNCERT
ClassClass 6
SubjectMaths
ChapterChapter 7
Chapter NameFractions
Exercise Ex 7.4
Number of Questions Solved10
CategoryNCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4

Question 1.
Write shaded portion as a fraction. Arrange them in ascending and descending order using correct sign ‘<‘, ‘=’, ‘>’ between the fraction:
(a)
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 53
(b)
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 54
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 55
appropriate signs between the fractions  given
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 56
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 57
(i) In ascending order, these are
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 58
(ii) In descending order, these are
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 59
(b)
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 60
(i) In ascending order, these are
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 61
(ii) In descending order, these are
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 62
(c)
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 63
Question 2.
Compare the fractions and put an appropriate sign.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 64
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 65

NCERT Solutions for Class 6 Maths Chapter 7 Fractions 66
Question 3.
Make five more such pairs and make appropriate signs.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 67

Question 4.
Look at the figures and write ‘<’ or ‘>’, ‘=’ between the pairs of fractions.
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 68
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 69
Make five more such problems and solve them with your friends.
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 70
For the remaining part, please try yourself.

Question 5.
How quickly can you do this? Fill appropriate sign (<, =,>)
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 71
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 72
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 73
Question 6.
The following fractions represent just three different numbers. Separate them into three groups of equivalent fractions, by changing each one to its simplest form.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 74
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 75
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 76
Question 7.
Find answers to the following. Write and indicate how you solved them.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 77
Solution :
(a) Equivalent fraction of \(\frac { 5 }{ 9 }\) are
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 78
Equivalent fraction of \(\frac { 4 }{ 5 }\) are
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 79
(b) Equivalent fraction of \(\frac { 9 }{ 16 }\) are
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 80
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 81

Question 8.
Ila reads 25 pages of a book containing 100 pages. Lalita reads \(\frac { 1 }{ 2 }\) of the same book. Who read less?
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 82
Question 9.
Rafiq exercised for \(\frac { 3 }{ 6 }\) of an hour, while 6 Rohit exercised for \(\frac { 3 }{ 4 }\) of an hour. Who exercised for a longer time?
Solution :
∴ \(\frac { 3 }{ 4 }\) > \(\frac { 3 }{ 6 }\)
∴ Rohit exercised for a longer time.

Question 10.
In class A of 25 students, 20 passed in first class; in another class B of 30 students, 24 passed in first class. In which class was a greater fraction of students getting first class?
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 83
Hence, in both the classes the same fraction \(\left( \frac { 4 }{ 5 } \right)\)of total students got first class.

 

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NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3.

BoardCBSE
TextbookNCERT
ClassClass 6
SubjectMaths
ChapterChapter 7
Chapter NameFractions
Exercise Ex 7.3
Number of Questions Solved9
CategoryNCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3

Question 1.
Write the fractions. Are all these fractions equivalent?
(a)
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 18
(b)
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 19
Solution :
(a)
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 20
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 21
(b)
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 22
No ! all these fractions ae not equivalent.

Question 2.
Write the fractions and pair up the equivalent fractions from each row.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 23
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 24
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 25
Equivalent fractions are
(a), (ii);
(b), (,iv);
(c), (i);
(d), (v);
(e), (iii).

Question 3.
Replace in each of the following by the correct number:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 26
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 27
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 28
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 29
Question 4.
Find the equivalent fraction of \(\frac { 3 }{ 5 }\) having
(a) denominator 20
(b) numerator 9
(d) numerator 27
(c) denominator 30
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 30
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 31
Question 5.
Find the equivalent fraction of \(\frac { 36 }{ 48 }\) with
(a) numerator 9
(b) denominator 4.
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 32
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 33
Question 6.
Check whether the given fractions are equivalent :
(a) \(\frac { 5 }{ 9 }\), \(\frac { 30 }{ 54 }\)
(b) \(\frac { 3 }{ 10 }\), \(\frac { 12 }{ 50 }\)
(c) \(\frac { 7 }{ 13 }\), \(\frac { 5 }{ 11 }\)
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 34
∴ The given fractions \(\frac { 5 }{ 9 }\) and \(\frac { 30 }{ 54 }\) are equivalent.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 35
∴ The given fractions \(\frac { 3 }{ 10 }\) and \(\frac { 12 }{ 50 }\) are not equivalent.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 36
∴ The given fractions \(\frac { 7 }{ 3 }\) and \(\frac { 5 }{ 11 }\) are not equivalent.

Question 7.
Reduce the following fractions to simplest form:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 37
Solution :
(a) \(\frac { 48 }{ 60 }\)
Factors of 48 are 1, 2, 3,4, 6, 8, 12, 16, 24 and 48.
Factors of 60 are 1, 2, 3,4, 5, 6, 10,12, 15, 20, 30 and 60.
∴ Common factors of 48 and 60 are 1, 2, 3, 4, 6 and 12. Highest of these common factors is 12.
∴ H.C.F. of 48 and 60 is 12.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 38
(b) \(\frac { 150 }{ 60 }\)
Factors of 150 are 1,2,3,5,6.10,15,25,30,50, 75 and 150.
Factors of 60 are 1, 2. 3, 4. 5, 6, 10, 12, 15, 20, 30 and 60.
∴ Common factors of 150 and 60 are 1, 2, 3, 5,6, 10, 15 and 30.
Highest of these common factors is 30.
∴ H.C.F. of 150 and 60 is 30.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 39
(c) \(\frac { 84 }{ 98 }\)
Factors of 84 are 1, 2, 3,4, 6, 7, 12, 14, 21, 28, 42 and 84.
Factors of 98 are 1, 2, 7, 14,49 and 98.
∴ Common factors of 84 and 98 are 1,7 and 14. Highest of these common factors is 14.
∴ H.C.F. of 84 and 98 is 14.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 40
(d) \(\frac { 12 }{ 52 }\)
Factors of 12 are 1, 2, 3,4, 6 and 12.
Factors of 52 are 1, 2, 4, 13, 26 and 52.
∴ Common factors of 12 and 52 are 1,2 and 4. Highest of these common factors is 4.
∴ H.C.F. of 12 and 52 is 4.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 41
(e) \(\frac { 7 }{ 28 }\)
Factors of 7 are 1 and 7.
Factors of 28 are 1, 2,4, 7, 14 and 28.
∴ Common factors of 7 and 28 are 1 and 7. Highest of these common factors is 7.
∴ H.C.F. of 7 and 28 is 7.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 42
Question 8.
Ramesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamaal used up 40 pencils. What fraction did each use up? Check if each has used up an equal fraction of his/her pencils?
Solution :
For Ramesh
Number of pencils he had = 20 Number of pencils used by him =10
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 43
For Sheelu
Number of pencils she had = 50 Number of pencils used by her = 25
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 44

For Jamaal
Number of pencils he had = 80 Number of pencils used by him = 40
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 45
Yes ! each has used up an equal fraction of his/her pencils.

Question 9.
Match the equivalent fractions and write another two more for each :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 46
Solution :
(i) \(\frac { 250 }{ 400 }\)
Factors of 250 are 1, 2, 5, 10, 25, 50, 125 and 250.
Factors of 400 are 1,2,4,5,8,10,16,20,25,40, 80, 100, 200 and 400.
∴ Common factors of 250 and 400 are 1,2,5, 10, 25 and 50.
Highest of these common factors is 50.
∴ H.C.F. of 250 and 400 is 50.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 47

(ii) \(\frac { 180 }{ 200 }\)
Factors of 180 are 1,2, 3,4, 5, 6,9,10,12,15, 18, 20, 30, 36, 45, 60, 90 and 180.
Factors of 200 are 1,2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 200.
∴ Common factors of 180 and 200 are 1,2, 4, 5, 10 and 20.
Highest of these common factors is 20.
∴ H.C.F. of 180 and 200 is 20.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 48

(iii) \(\frac { 600 }{ 990 }\)
Factors of 660 are 1,2,3,4,5,6,10,12,22,30, 66, 110, 132, 165, 220, 330 amd 660.
Factors of 990 are 1,2,3,5,6,9,10,11,30,33, 90, 99, 110, 165, 198, 330, 495 and 990.
∴ Common factors of 660 and 990 are 1,2,3, 5,6, 10, 30, 110 and 330.
Highest of these common factors is 330.
∴ H.C.F. of 660 and 990 is 330.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 49

(iv) \(\frac { 180 }{ 360 }\)
Factors of 180 are 1, 2, 3,4, 5, 6, 9, 10, 12,15, 18, 20, 30, 36,45, 60, 90 and 180.
Factors of 360 are 1, 2, 3,4, 5, 6,9,10, 12, 15, 18, 20, 24, 30, 36,40, 60, 72, 90, 120, 180 and 360.
∴ Common factors of 180 and 360 are 1,2, 3,4,5,6,9,10,12,15,18.20, 30, 36,60,90 and 180.
Highest of these common factors is 180.
∴ H.C.F. of 180 and 360 is 180.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 50

(v) \(\frac { 220 }{ 550 }\)
Factors of 220 are 1,2,4, 5,10,11, 20, 22,44, 55, 110 and 220.
Factors of 550 are 1, 2, 5, 10, 22, 25, 55, 110, 275 and 550.
∴ Common factors of 220 and 550 are 1,2,5, 10, 20 and 110.
Highest of these common factors is 110.
∴ H.C.F. of 220 and 550 is 110.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 51
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 52

 

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NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.2

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.2 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.2.

BoardCBSE
TextbookNCERT
ClassClass 6
SubjectMaths
ChapterChapter 7
Chapter NameFractions
Exercise Ex 7.2
Number of Questions Solved3
CategoryNCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.2

Question 1.
Draw number lines and locate the points on them:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 9
Solution :
(a)
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 10
(b)
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 11
(c)
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 12
Question 2.
Express the following as mixed fractions:
(a) \(\frac { 20 }{ 3 }\)
(b) \(\frac { 11 }{ 5 }\)
(c) \(\frac { 17 }{ 7 }\)
(d) \(\frac { 28 }{ 5 }\)
(e) \(\frac { 19 }{ 6 }\)
(f) \(\frac { 35 }{ 9 }\).
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 13
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 14
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 15

Question 3.
Express the following as improper fractions:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 16
Solution :
NCERT Solutions for Class 6 Maths Chapter 7 Fractions 17

 

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NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3

NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3.

BoardCBSE
TextbookNCERT
ClassClass 6
SubjectMaths
ChapterChapter 6
Chapter NameIntegers
Exercise Ex 6.3
Number of Questions Solved4
CategoryNCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3

Question 1.
Find:
(a)
35 – (20)
(b) 72 – (90)
(c) (-15) – (-18)
(d) (-20) – (13)
(e) 23 -(-12)
(f) (-32) -(- 40).
Solution.
(a) 35-(20)
35 – (20)
= 35 + (additive inverse of 20)
= 35 + (- 20)
= 15 + 20 + (- 20)
= 15 + 0= 15

(b) 72-90
72-90
= 12 + (additive inverse of 90)
= 72 + (- 90)
= 72 + (- 72) + (- 18)
= 0 + (- 18) = – 18

(c) (- 15) – (- 18)
(-15)-(-18)
= (- 15) + (additive inverse of -18)
= (- 15) + (18)
= (- 15) + (15) + (3)
= 0 + (3) = 3

(d) (- 20) – (13)
= (-20)-(13)
= (- 20) + (additive inverse of 13)
= (- 20) + (- 13) = – 33

(e) 23 – (- 12)
23 – (- 12)
= 23 + (additive inverse of – 12)
= 23+12 = 35

(f) (- 32) – (- 40)
(-32)-(-40)
= (- 32) + (additive inverse of – 40)
= (-32)+ (+40)
= (- 32) + (+ 32) + (+ 8)
= 0 + (+ 8) = 8.

Question 2.
Fill in the blanks with >, < or = sign :
(a)
(- 3) + (- 6)……… (-3)-(-6)
(b) (- 21) – (- 10)….. (-31)+ (-11)
(c) 45 -(- 11)……. 57 +(-4)
(d) (- 25) – (- 42)……. (-42)-(-25).
Solution.
(a) L.H.S. = (- 3) + (- 6) = – 9
R.H.S. = (- 3) – (- 6)
= (- 3) + (additive inverse of – 6)
= (- 3) + 6
= (- 3) + 3 + 3
=0+3=3
∴ (- 3) + (- 6) < (- 3) – (- 6)

(b) L.H.S. = (- 21) – (- 10)
= (- 21) + (additive inverse of -10)
= (- 21) + 10
= (- ll) + (- 10)+ 10
= (- 11) + 0 = – 11
R.H.S. = (-31)+ (-11)
= -42
∴ (-21)-(-10) >(-31)+ (-11)

(c) L.H.S. =45-(-11)
= 45 + (additive inverse of – 11)
= 45 + 11 = 56
R.H.S.;= 57 + (-4)
= 53 + 4 + (- 4)
= 53 + 0 = 53
∴ 45-(-11) >57 +(-4)

(d) L.H.S. = (-25) – (-42)
= (- 25) + (additive inverse of – 42)
= (-25)+ (+42)
= (- 25) + (+ 25) + (+ 17)
= 0 + (+ 17)= 17
R.H.S. = (- 42) – (- 25)
= (- 42) + (additive inverse of – 25)
= (- 42) + (+ 25)
= (- 17) + (- 25) + (+ 25)
= (- 17) + 0 = – 17
∴ (-25)-(-42) >(-42)-(-25).

Question 3.
Fill in the blanks: 

(a) (-8) + =0
(b) 13 + = 0
(c) 12 + (-12) –
(d) (-4) + =-72
(e) – 75 = -10.
Solution.
(a) (-8)+ 8 = 0
(b) 13 + (-13) = 0
(c) 12 + (- 12) = 0.
(d)(-4) + (-8) = -12
(e) (+5)-15 =-10.

Question 4.
Find:
(a) (-7) -8 -(-25)
(b) (-13)+ 32-8-1
(c) (-7) + (-8) + (-90)
(d) 50-(-40)-(-2)
Solution.
(a) (- 7) – 8 – (- 25)
(- 7) – 8 – (- 25)
= (- 7) + (additive inverse of 8) – (- 25)
= (- 7) + (- 8) – (- 25)
= – 15-(-25)
= – 15 + (additive inverse of – 25)
= -15+ (+25)
= – 15 + (+ 15) + (+ 10)
= 0 + (+ 10) = 10

(b) (- 13) + 32 – 8 – 1
(-13)+ 32-8-1
= (-13)+ 32-9
= (- 13) + 32 + (additive inverse of 9)
= (- 13) + 32 + (- 9)
= (- 13) + 23 + 9 + (- 9)
= (-13)+ 23 + 0
= (- 13)+ 23
= (-13)+13+10
= 0+ 10 = 10

(c) (- 7) + (- 8) + (- 90)
(-7) +(-8)+ (-90)
= (-15)+ (-90)
= -105

(d) 50-(-40)-(-2) 
= 50 – (- 40) – (- 2)
= 50 + (additive inverse of – 40) – (- 2)
= 50+ (40)-(-2)
= 90-(-2)
= 90 + (additive inverse of – 2)
= 90 + 2 = 92.

We hope the NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3 help you. If you have any query regarding NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3, drop a comment below and we will get back to you at the earliest.