# RS Aggarwal Class 6 Solutions Chapter 7 Decimals Ex 7E

## RS Aggarwal Class 6 Solutions Chapter 7 Decimals Ex 7E

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 7 Decimals Ex 7E.

Other Exercises

Question 1.
Solution:
(c) $$\\ \frac { 7 }{ 10 }$$ = 0.7

Question 2.
Solution:
(d) $$\\ \frac { 5 }{ 100 }$$ = .05

Question 3.
Solution:
(b) $$\\ \frac { 9 }{ 1000 }$$ = 0.009

Question 4.
Solution:
(a) $$\\ \frac { 16 }{ 1000 }$$ = 0.016

Question 5.
Solution:
(c) $$\\ \frac { 134 }{ 1000 }$$ = 0.134

Question 6.
Solution:
(a) $$2 \frac { 17 }{ 100 }$$ = 2.17

Question 7.
Solution:
(b) $$4 \frac { 3 }{ 1000 }$$ = 4.03

Question 8.
Solution:
(b) 6.25 = $$6 \frac { 25 }{ 100 }$$ = $$6 \frac { 1 }{ 4 }$$

Question 9.
Solution:
(b) $$\\ \frac { 6 }{ 25 }$$
= $$\\ \frac { 6\times 4 }{ 25\times 4 }$$
= $$\\ \frac { 24 }{ 100 }$$
= 0.24

Question 10.
Solution:
(c) $$4 \frac { 7 }{ 8 }$$ = $$\\ \frac { 39 }{ 8 }$$ = 4.875

Question 11.
Solution:
(a) 24.8 = $$24 \frac { 8 }{ 10 }$$
= $$24 \frac { 4 }{ 5 }$$

Question 12.
Solution:
(b) $$2 \frac { 1 }{ 25 }$$
= 2 + $$\\ \frac { 1 }{ 25 }$$ x $$\\ \frac { 4 }{ 4 }$$
= 2 + $$\\ \frac { 4 }{ 100 }$$
= 2.04

Question 13.
Solution:
(c) 2 + $$\\ \frac { 3 }{ 10 }$$ + $$\\ \frac { 4 }{ 100 }$$
= 2 + $$\\ \frac { 30 }{ 100 }$$ + $$\\ \frac { 4 }{ 100 }$$
= 2.34

Question 14.
Solution:
(b) $$2 \frac { 6 }{ 100 }$$
= 2 + 0.06
= 2.06

Question 15.
Solution:
(c) $$\\ \frac { 4 }{ 100 }$$ + $$\\ \frac { 7 }{ 10000 }$$
= 0.04 + 0.0007
= 0.0407

Question 16.
Solution:
(c) 2.06
= $$\left( 2\times 1 \right) +\left( 6\times \frac { 1 }{ 100 } \right)$$
= $$2+\frac { 6 }{ 100 }$$

Question 17.
Solution:
(d) Among 2.600, 2.006, 2.660,2.080, 2.660 is the largest.

Question 18.
Solution:
(b) 2.002 < 2.020 < 2.200 < 2.222 is the correct.

Question 19.
Solution:
(a) 2.1 = 2.100 and 2.005
2.100 > 2.055
=> 2.1 > 2.055

Question 20.
Solution:
(b) 1cm = $$\\ \frac { 1 }{ 100 }$$ m
= 0.01

Question 21.
Solution:
(b) 2 m 5 cm = 2.05 m

Question 22.
Solution:
(c) 2 kg 8 g = 2 + 0.008 = 2.008

Question 23.
Solution:
(b) 2 kg 56 g = 2.056 kg
(∵ 1000 g = 1 kg)

Question 24.
Solution:
(c) 2 km 35 m = 2.035 km
(∵ 1000 m = 1 km)

Question 25.
Solution:
(c) ∵ 0.4 + 0.004 + 4.4
= 4.804

Question 26.
Solution:
(a) ∵ 3.5 + 4.05 – 6.005
= 3.500 + 4.050 – 6.005
= 7.550 – 6.005
= 1.545

Question 27.
Solution:
(b) ∵6.3 – 2.8 = 3.5

Question 28.
Solution:
(c) ∵ 5.01 – 3.6 = 5.01 – 3.60
= 1.41

Question 29.
Solution:
(a) ∵ 2 – 0.7 = 2.0 – 0.7 = 1.3

Question 30.
Solution:
(a) ∵ 1.1 – 0.3
= 0.8

Hope given RS Aggarwal Solutions Class 6 Chapter 7 Decimals Ex 7E are helpful to complete your math homework.

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