# RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1D

## RS Aggarwal Class 6 Solutions Chapter 1 Number System Ex 1D

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1D

Other Exercises

Question 1.
Solution:
(a) 40
(b) 170
(c) 3870
(d) 16380

Question 2.
Solution:
(a) 800
(b) 1300
(c) 43100
(d) 98200

Question 3.
Solution:
(a) 1000
(b) 5000
(c) 17000
(d) 28000

Question 4.
Solution:
(a) 20000
(b) 30000
(c) 30000
(d) 270000

Estimate each sum to the nearest ten :

Question 5.
Solution:
(57 + 34)
57 estimated to the nearest ten = 60
34 estimated to the nearest ten = 30
Required sum = 60 + 30
= 90 Ans.

Question 6.
Solution:
(43 + 78)
43 estimated to the nearest ten = 40
78 estimated to the nearest ten = 80
Required sum = 40 + 80
= 120 Ans.

Question 7.
Solution:
(14 + 69)
14 estimated to the nearest ten = 10
69 estimated to the nearest ten = 70
Required sum = 10 + 70
= 80 Ans.

Question 8.
Solution:
(86 +19)
86 estimated to the nearest ten = 90
19 estimated to the nearest ten = 20
Required sum = 90 + 20
= 110 Ans.

Question 9.
Solution:
(95 + 58)
95 estimated to the nearest ten =100
58 estimated to the nearest ten = 60
Required sum = 100 + 60
= 160 Ans

Question 10.
Solution:
77 estimated to the nearest ten = 80
63 estimated to the nearest ten = 60
Required sum = 80 + 60
= 140 Ans.

Question 11.
Solution:
(356 + 275)
356 estimated to the nearest ten = 360
275 estimated to the nearest ten = 280
Required sum = 360 + 280
= 640 Ans.

Question 12.
Solution:
463 + 182
463 estimated to the nearest ten = 460
182 estimated to the nearest ten = 180
Required sum = 460 + 180
= 640 Ans.

Question 13.
Solution:
(538 + 276)
538 estimated to the nearest ten = 540
276 estimated to the nearest ten = 280
Required sum = 540 + 280
= 820 Ans.

Estimate each sum to the nearest hundred:

Question 14.
Solution:
(236 + 689)
236 estimated to the nearest hundred = 200
689 estimated to the nearest hundred = 700
Required sum = 200 + 700
= 900 Ans.

Question 15.
Solution:
(458 + 324)
458 estimated.to the nearest hundred = 500
324 estimated to the nearest hundred = 300
Required sum = 500 + 300
= 800 Ans.

Question 16.
Solution:
(170 + 395)
170 estimated to the nearest hundred = 200
395 estimated to the nearest hundred = 400
Required sum = 200 + 400
= 600 Ans.

Question 17.
Solution:
(3280 + 4395)
3280 estimated to the nearest hundred = 3300
4395 estimated to the nearest hundred = 4400
Required sum = 3300 + 4400
= 7700 Ans.

Question 18.
Solution:
(5130 + 1410)
5130 estimated to the nearest hundred = 5100
1410 estimated to the nearest hundred = 1400
Required sum = 5100 + 1400
= 6500 Ans.

Question 19.
Solution:
(10083 + 29380)
10083 estimated to the nearest hundred =10100
29380 estimated to the nearest hundred = 29400
Required sum = 10100 + 29400
= 39500 Ans.

Estimate each sum to the nearest thousand :

Question 20.
Solution:
(32836 + 16466)
32836 estimated to the nearest thousand = 33000
16466 estimated to the nearest thousand = 16000
Required sum = 33000 + 16000
= 49000 Ans.

Question 21.
Solution:
(46703 + 11375)
46703 estimated to the nearest thousand = 47000
11375 estimated to the nearest thousand = 11000
Required sum = 47000 + 11000
= 58000 Ans.

Question 22.
Solution:
54 balls + 79 balls
54 balls estimated to the nearest 10 = 50
79 balls estimated to the nearest 10 = 80
Required total number of balls = 50 + 80 + 130 Ans.

Estimate each difference to the nearest ten :

Question 23.
Solution:
(53 – 18)
53 estimated to the nearest ten = 50
18 estimated to the nearest ten = 20
Difference of 50 and 20
= 50 – 20
= 30 Ans.

Question 24.
Solution:
(97 – 38)
97 estimated to the nearest ten =100
38 estimated to the nearest ten = 40
Difference of 100 and 40
= 100 – 40
= 60 Ans.

Question 25.
Solution:
(409 – 148)
409 estimated to the nearest ten = 410
148 estimated to the nearest ten = 150
Difference of 410 and 150
= 410 – 150
= 260 Ans.

Estimate each difference to the nearest hundred :

Question 26.
Solution:
(678 – 215)
678 estimated to the nearest hundred = 700
215 estimated to the nearest hundred = 200
Difference between 700 and 200
= 700 – 200
= 500 Ans.

Question 27.
Solution:
(957 – 578)
957 estimated to the nearest hundred = 1000
578 estimated to the nearest hundred = 600
Difference between 1000 and 600
= 1000 – 600
= 400 Ans.

Question 28.
Solution:
(7258 – 2429)
7258 estimated to the nearest hundred = 7300
2429 estimated to the nearest hundred = 2400
Difference between 7300 and 2400
= 7300 – 2400
= 4900 Ans.

Question 29.
Solution:
5612 estimated to the nearest hundred = 5600
3095 estimated to the nearest hundred = 3100
Difference between 5600 and 3100
= 5600 – 3100
= 2500 Ans.

Estimate each difference to the nearest thousand :

Question 30.
Solution:
35863 estimated to the nearest thousand = 36000
27677 estimated to the nearest thousand = 28000
Difference between 36000 and 28000
= 36000 – 28000
= 8000 Ans.

Question 31.
Solution:
(47005 – 39488)
47005 estimated to the nearest thousand = 47000
39488 estimated to the nearest thousand = 39000
Difference between 47000 and 39000
= 47000 – 39000
= 8000 Ans.

Hope given RS Aggarwal Solutions Class 6 Chapter 1 Number System Ex 1D are helpful to complete your math homework.

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