NCERT Solutions for Class 10 Maths Chapter 1 Real Numbers Ex 1.2

NCERT Solutions for Class 10 Mathematics Chapter 1 Real Numbers Ex 1.2 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Mathematics Chapter 1 Real Numbers Ex 1.2. https://mcqquestions.guru/ncert-solutions-for-class-10-maths-chapter-1-ex-1-2/

Board CBSE
Textbook NCERT
Class Class 10
Subject Maths
Chapter Chapter 1
Chapter Name Real Numbers
Exercise Ex 1.2
Number of Questions Solved 7
Category NCERT Solutions

NCERT Solutions for Class 10 Maths Chapter 1 Real Numbers Ex 1.2

Ex 1.2 Class 10 Question 1.
Express each number as a product of its prime factors:
(i) 140
(ii) 156
(iii) 3825
(iv) 5005
(v) 7429.
Solutions:
(i) 140
Ex 1.2 Class 10

(ii) 156
Exercise 1.2 Class 10 Maths

(iii) 3825
1.2 Class 10 Maths Chapter 1

(iv) 5005
NCERT Solutions for Class 10 Maths Chapter 1 Real Numbers Ex 1.2 3a

Exercise 1.2 Class 10
(v) 7429.
So, 7429 = 17 x 19 x 23
Ex 1.2 Class 10

Exercise 1.2 Class 10 Maths Question 2.
Find the LCM and HCF of the following pairs of integers and verify that LCM x HCF = product of two numbers,
(i) 26 and 91
(ii) 510 and 92
(iii) 336 and 54
Solutions:
(i) 26 and 91
Class 10 Maths Chapter 1 Exercise 1.2

(ii) 510 and 92
Ex 1.2 Class 10 Maths

(iii) 336 and 54
Ex 1.2 Class 10 Maths Exercise 1.2 Class 10 Maths

1.2 Class 10 Maths Chapter 1 Question 3.
Find the LCM and HCF of the following integers by applying the prime factorisation method.
(i) 12,15 and 21
(ii) 17,23 and 29
(iii) 8, 9 and 25
Solutions:
(i) 12,15 and 21
Exercise 1.2 Class 10 Maths

(ii) 17,23 and 29
Class 10 Ex 1.2

(iii) 8, 9 and 25
Class 10 Maths Ex 1.2

Exercise 1.2 Class 10 Question 4.
Given that HCF (306,657) = 9, find LCM (306, 657).
Solutions:
Given that HCF (306, 657) = 9
We know that LCM x HCF = Product of two numbers
Class 10 Maths Chapter 1 Exercise 1.2 Solutions

Class 10 Maths Chapter 1 Exercise 1.2 Question 5.
Check whether 6n can end with the digit 0 for any natural number n.
Solutions:
Since prime factorisation of 6n is given by 6n = (2 x 3)n = 2n x 3n
Prime factorisation of 6n contains only prime numbers 2 and 3.
6n may end with the digit 0 for some ‘n’ if 5 must be in its prime factorisation which is not present.
So, there is no natural number VT for which 6n ends with the digit zero.

Ex 1.2 Class 10 Maths Question 6.
Explain why 7 x 11 x 13 + 13 and 7 x 6 x 5 x 4 x 3 x 2 x 1 + 5 are composite numbers.
Solutions:
Ex 1.2 Class 10 Maths
Both N1 and N2 are expressed as a product of primes. Therefore, both are composite numbers.

Exercise 1.2 Class 10 Maths Question 7.
There is a circular path around a sports field. Sonia takes 18 minutes to drive one round of the field, while Ravi takes 12 minutes for the same. Suppose they both start at the same point and at the same time, and go in the same direction. After how many minutes will they meet again at the starting point?
Solutions:
By taking LCM of time taken (in minutes) by Sonia and Ravi, we can get the actual number of minutes after which they meet again at the starting point after both start at same point and of the same time, and go in the same direction.
Class 10 Maths Chapter 1 Exercise 1.2 Solutions

Therefore, both Sonia and Ravi will meet again at the starting point after 36 minutes.

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