NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3

NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3.

BoardCBSE
TextbookNCERT
ClassClass 7
SubjectMaths
ChapterChapter 4
Chapter NameSimple Equations
ExerciseEx 4.3
Number of Questions Solved4
CategoryNCERT Solutions

NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3

Question 1.
Solve the following equations:
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 1
Solution:
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 2
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 3
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NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 8
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 9
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 10

Question 2.
Solve the following equations:

(a) 2 (x + 4) = 12
(6) 3 (n – 5) = 21
(c) 3 (n – 5) = -21
(d) -4 (2 + x) = 8
(e) 4 (2 – x) = 8

Solution:
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 11
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 12
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 13
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 14

Question 3.
Solve the /bilowing equations:

(a) 4 = 5 (p – 2)
(b) -4 = 5 (p – 2)
(c) 16 = 4 + 3 (t + 2)
(d) 4 + 5 (p – 1) = 34
(e) 0 = 16 + 4 (m – 6)

Solution:
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 15
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 16
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 17
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Question 4.
(a) Construct 3 equations starting with x = 2
(b) Construct 3 equations starting with x = – 2.
Solution:
(a) 1. Start with x = 2
Multiply both sides by 3, 3x = 6
Subtract 2 from both sides, 3x – 2 = 4 …(1)

2. Start with x = 2
Multiply both sides by 4, 4x = 8
Add 5 to both sides, 4x + 5 = 13 …(2)

3. Start with x = 2 Multiply both sides by 5 5x = 10
Subtract 1 from both sides, 5x – 1 = 9 …(3)

(b) First equation:
Start with x = -2
Multiply both sides by 2, 2x = -4
Subtract 3 from both sides, 2x – 3 = -7

Second equation:
Start with x = – 2
Multiply both sides by – 5, – 5x = 10
Add 10 to both sides, 10 – 5x = 20

Third equation:
Start with x = -2
Divide both sides by 2, \(\frac { x }{ 2 } \) = -1
Add 3 to both sides, \(\frac { x }{ 2 } \) + 3 = 2

We hope the NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 help you. If you have any query regarding NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2

NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2.

BoardCBSE
TextbookNCERT
ClassClass 7
SubjectMaths
ChapterChapter 4
Chapter NameSimple Equations
ExerciseEx 4.2
Number of Questions Solved4
CategoryNCERT Solutions

NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2

Question 1.
Give first the step you will use to separate the variable and then solve the equation:
(a) x – 1 = 0
(b) x + 1 = 0
(c) x – 1 = 5
(e) y – 4 = – 7
(f) y – 4 = 4
(g) y + 4 = 4
(h) y + 4 = – 4
Solution:
(a) The given equation is x – 1 = 0
Add 1 to both sides,
x – 1 + 1 = 0 + 1 ⇒ x = 1
It is the required solution.
Check. Put the solution x = 1 back into the equation.
L.H.S. = x – 1 = 1 = 1 – 0 = R.H.S.
The solution is thus checked for its correctness.

(b) The given equation is x + 1 = 0
Subtract 1 from both sides, x + 1 – 1 = 0 – 1 ⇒ x = – 1
It is the required solution.
Check. Put the solution x = – 1 back into the equation.
L.H.S. = x + 1 = (-1)+1
= 0 = R.H.S.
The solution is thus checked for its correctness.

(c) The given equation is
x – 1 = 5
Add 1 to both sides,
x + 1 – 1 = 5 + 1 ⇒ x = 6
It is the required solution
Check. Put the solution x = 6 back into the equation.
L.H.S. = x – 1 = 6 – 1 = 5 = R.H.S.
The solution is thus checked for its correctness.

(d) The given equation is x + 6 = 2
Subtract 6 from both sides, x + 6 – 6 = 2 – 6 ⇒ x = – 4
It is the required solution.
Check. Put the solution x = – 4 back into the equation.
L.H.S. = x + 6 = – 4 + 6 = 2 = R.H.S.
The solution is thus checked for its correctness.

(e) The given equation is y – 4 = – 7
Add 4 to both sides, y – 4 + 4 = – 7 + 4 ⇒ y = – 3
It is the required solution.
Check. Put the solution
L.H.S. = y – 4 = – 3 – 4 = – 7 = R.H.S.
The solution is thus checked for its correctness.

(f) The given equation is y – 4 = 4
Add 4 to both sides,
y – 4 + 4 = 4 + 4 ⇒ y = 8
It is the required solution.
Check. Put the solution y = 8 back into the equation.
L.H.S. = y – 4 = 8 – 4 = 4 = R.H.S.
The solution is thus checked for its correctness.

(g) The given equation is y + 4 = 4
Subtract 4 from both sides, y + 4 – 4 = 4 – 4 ⇒ y = 0
It is the required solution.
Check. Put the solution y = 0 back into the equation.
L.H.S. =y + 4 = 0 + 4 = 4 = R.H.S.
The solution is thus checked for its correctness.

(h) The given equation is y + 4 = – 4
Subtract 4 from both sides, y + 4 – 4 = – 4 – 4 ⇒ y = -8
It is the required solution.
Check. Put the solution y = – 8 back into the equation.
L.H.S. = y + 4 = -8 + 4 = – 4 = R.H.S.
The solution is thus checked for its correctness.

Question 2.
Give first the step you will use to separate the variable and then solve the equation:
(a) 3l = 42
(b) \(\frac { b }{ 2 } \) = 6
(c) \(\frac { p }{ 7 } \) = 4
(d) 4x = 25
(e) 8y = 36
(f) \(\frac { z }{ 3 } \) = \(\frac { 5 }{ 4 } \)
(g) \(\frac { a }{ 5 } \) = \(\frac { 7 }{ 15 } \)
(h) 20t = – 10

Solution:
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 1
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Question 3.
Give the steps you will use to separate the variable and then solve the equation :
(a) 3n – 2 = 46
(b) 5m + 7 = 17
(c) \(\frac { 20p }{ 3 } \) = 40
(d) \(\frac { 3p }{ 10 } \) = 6
Solution:
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 7NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 7
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 8
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 9
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 10

Question 4.
Solve the following equations:
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 11
Solution:
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 12
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 13
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 14
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 15
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 16
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We hope the NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 help you. If you have any query regarding NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.2

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.2 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.2.

BoardCBSE
TextbookNCERT
ClassClass 7
SubjectMaths
ChapterChapter 3
Chapter NameData Handling
ExerciseEx 3.2
Number of Questions Solved5
CategoryNCERT Solutions

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.2

Question 1.
The scores in mathematics test (out of 25) of 15 students is as follows:
19, 25, 23, 20, 9, 20, 15, 10, 5, 16, 25, 20, 24, 12, 20
Find the mode and median of this data. Are they the same?
Solution:
For Median. We arrange the data in ascending order, we get
5, 9, 10, 12, 15, 16, 19, 20,
20, 20, 20, 23, 24, 25, 25
Median is the middle observation.
Therefore, 20 is the median.
For Mode.
Mode = Observation with highest frequency = 20
Yes, they are the same.

Question 2.
The runs scored in a cricket match by 11 players is as follows:
6, 15, 120, 50, 100, 80, 10, 15, 8, 10, 15.
Find the mean, mode, and median of this data. Are the three same?
Solution:
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.2 1
(ii) For Median. We arrange the data in ascending order, we get
6, 8, 10, 10, 15, 15, 15, 50, 80, 100, 120
Median is the middle observation. Therefore, 15 is the median.

(iii) For Mode. Mode = observation with highest frequency = 15
No! They are not the same.

Question 3.
The weights (in kg.) of 15 students of a class are:
38, 42, 35, 37, 45, 50, 32, 43,
43, 40, 36, 38, 43, 38, 47

  1. Find the mode and median of this data.
  2. Is there more than one mode?

Solution:
(i) For Median. We arrange the data in ascending order, we get
32, 35, 36, 37, 38, 38, 38, 40, 42, 43, 43,
43, 45, 47, 50
Median is the middle observation.
Therefore, 40 kg is the median.
For Mode. Mode = observation with highest frequency = 38 kg and 43 kg.
(ii) Yes! there are 2 (more than one) modes.

Question 4.
Find the mode and median of the data:
13, 16, 12, 14, 19, 12, 14, 13, 14.
Solution:
For Median. We arrange the data in ascending order, we get 12, 12, 13, 13, 14, 14, 14, 16, 19.
Median is the middle observation.
Therefore, 14 is the median.
For Mode. Mode = observation with highest frequency = 14.

Question 5.
Tell whether the statement is true or false:

  1. The mode is always one of the numbers in data.
  2. The mean is one of the numbers in a data.
  3. The median is always one of the numbers in a data.
  4. The data 6, 4, 3, 8, 9, 12, 13, 9 has a mean of 9.

Solution:

  1. True
  2. False
  3. True
  4. False.

 

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NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3.

BoardCBSE
TextbookNCERT
ClassClass 7
SubjectMaths
ChapterChapter 3
Chapter NameData Handling
ExerciseEx 3.3
Number of Questions Solved6
CategoryNCERT Solutions

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3

Question 1.
Use the bar graph to answer the following questions.
(a) Which is the most popular pet?
(b) How many children have dog as a pet?
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3 1
Solution:
(a) The most popular pet is ‘Cat’.
(b) 8 children have a dog as a pet.

Question 2.
Read the bar graph which shows the number of books sold by a bookstore during five consecutive years and answer the following questions:
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3 2

  1. About how many books were sold in 1989?1990?1992?
  2. ln which year were about 475 books sold? About 225 books sold?
  3. In which years were fewer than 250 books sold?
  4. Can you explain how you would estimate the number of books sold in 1989?

Solution:
Clearly, from the given graph, we have

  1. Number of books sold in the year
    1989: 170 (approx.)
    1990: 475 (approx.)
    1992: 225 (approx.)
  2. In the year 1990, about 475 books were sold. In the year 1992, about 225 books were sold.
  3. Fewer than 250 books were sold in the years 1989 and 1992.
  4. It can be estimated using the height of the bar such that the height of 1 cm = 100 books.

Question 3.
The number of children in six different classes is given below. Represent the data on a bar graph.
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3 3
(a) How would you choose a scale?
(b) Answer the following questions:
(i) Which class has the maximum number of children? And the minimum?
(ii) Find the ratio of students of class sixth to the students of the class eighth.
Solution:
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3 4
(a) Start the scale at 0. The greatest value in the data is 135, so end the scale at a value greater than 135, such as 140. Use equal divisions along the axes, such as increments of 10.
We know that all the bars would lie between 0 and 140.
We choose the scale such that the length between 0 and 140 is neither too long nor too small.
Here, we take 1 unit for 10 children.
(b) (i) Fifth class has the maximum number of children. Tenth class has the minimum number of children.
(ii) Ratio of students of class sixth to eighth = 120 : 100 = \(\frac { 12 }{ 100 } \) = \(\frac { 6 }{ 5 } \) = 6 : 5

Question 4.
The performance of a student in 1st Term and, 2nd Term is given. Draw a double bar graph choosing the appropriate scale and answer the following :
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3 5

  1. In which subject, has the child improved his performance the most?
  2. In which subject is the improvement the least?
  3. Has the performance gone down in any subject?

Solution:
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3 6

  1. The child improved his performance the most in the subject of Maths.
  2. The improvement is the least in the subject of S. Science.
  3. Yes! The performance has gone down in the subject of Hindi.

Question 5.
Consider this data collected from a survey of a colony.
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3 7

  1. Draw a double graph choosing an appropriate scale.
    What do you infer from the bar graph?
  2. Which sport is most popular?
  3. Which is more preferred, watching or participating in sports?

Solution:
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3 8

  1. It is inferred that more people prefer cricket and fewer athletics.
  2. The most popular sport is cricket.
  3. Watching is more preferred than participating.

Question 6.
Take the data giving the minimum and the maximum temperature of various cities given at the beginning of this chapter. Plot a double bar graph using the data and answer the following:

  1. Which city has the largest difference in the minimum and maximum temperature on the given date?
  2. Which is the hottest city and which is the coldest city?
  3. Name two cities where the maximum temperature of one was less than the minimum temperature of the other.
  4. Name the city which has the least difference between its minimum and the maximum temperature.

Solution:
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3 9
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3 10

  1. The city Jammu has the largest difference in the minimum and maximum temperature on the given date.
  2. Jammu is the hottest city and Bangalore is the coldest city.
  3. The name of the two cities where the maximum temperature of one was less than the minimum temperature of the other is Bangalore and Jaipur or Bangalore and Ahmedabad.
  4. Mumbai has the least difference between its minimum and maximum temperature.

We hope the NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3 help you. If you have any query regarding NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3, drop a comment below and we will get back to you at the earliest.

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.4

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.4 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.4.

BoardCBSE
TextbookNCERT
ClassClass 7
SubjectMaths
ChapterChapter 3
Chapter NameData Handling
ExerciseEx 3.4
Number of Questions Solved3
CategoryNCERT Solutions

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.4

Question 1.
Tell whether the following is certain to happen, impossible, can happen but not certain.

  1. You are older today than yesterday.
  2. A tossed coin will land heads up.
  3. A die when tossed shall land up with 8 on top.
  4. The next traffic light seen will be green.
  5. Tomorrow will be a cloudy day.

Solution:

  1. Certain to happen
  2. Can happen but not certain
  3. Impossible
  4. Can happen but not certain
  5. Can happen but not certain

Question 2.
There are 6 marbles in a box with numbers from 1 to 6 marked on each of them.

  1. What is the probability of drawing a marble with the number 2?
  2. What is the probability of drawing a marble with the number 5?

Solution:
Out of 6 marbles, one can be drawn in 6 ways. So, the total number of events = 6

1. The marble with the number 2 can be obtained only in one way.
∴ Required probability = \(\frac { 1 }{ 6 } \)

2. The marble with the number 5 can be obtained only in one way.
∴ Required probability = \(\frac { 1 }{ 6 } \)

Question 3.
A coin is flipped to decide which team starts the game. What is the probability that your team will start?
Solution:
On tossing a coin, the possible outcomes are head (H) or tail (T).
Required probability = \(\frac { 1 }{ 2 } \)

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