NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.3

NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.3 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.3.

BoardCBSE
TextbookNCERT
ClassClass 6
SubjectMaths
ChapterChapter 5
Chapter NameUnderstanding Elementary Shapes
Exercise Ex 5.3
Number of Questions Solved2
CategoryNCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.3

Question 1.
Match the following :
(i) Straight angle (a) Less than one-fourth a revolution.
(ii) Right angle    (b) More than half a revolution
(iii) Acute angle   (c) Half of a revolution
(iv) Obtuse angle (d) One-fourth a revolution
(v) Reflex angle    (e) Between \(\frac { 1 }{ 4 }\) and \(\frac { 1 }{ 2 }\) of a revolution (f) One complete revolution.
Solution :
(i) Straight angle ↔ (c) Half of a revolution
(ii) Right angle ↔ (d) One-fourth a revolution
(iii) Acute angle ↔ (a) Less than one-fourth a revolution
(iv) Obtuse angle ↔ (e) Between 1/4 and 1/2 of a revolution
(v) Reflex angle ↔ (b) More than half a revolution.

Question 2.
Classify each one of the following angles as right, straight, acute, obtuse or reflex :
NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes 10
Solution :
(a) Acute
(b) Obtuse
(c) Right
(d) Reflex
(e) Straight
(f) Acute.

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NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.2

NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.2 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.2.

BoardCBSE
TextbookNCERT
ClassClass 6
SubjectMaths
ChapterChapter 5
Chapter NameUnderstanding Elementary Shapes
Exercise Ex 5.2
Number of Questions Solved7
CategoryNCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.2

Question 1.
What fraction of a clockwise revolution does the hour hand of a clock turn through, when it goes from
(a) 3 to 9
(b) 4 to 7
(c) 7 to 10
(d) 12 to 9
(e) 1 to 10
(f) 6 to 3?
Solution :
(a) \(\frac { 1 }{ 2 }\) of a revolution
(b) \(\frac { 1 }{ 4 }\) of a revolution
(c) \(\frac { 1 }{ 4 }\) of a revolution
(d) \(\frac { 3 }{ 4 }\) of a revolution
(e) \(\frac { 3 }{ 4 }\) of a revolution
(f) \(\frac { 3 }{ 4 }\) of a revolution.

Question 2.
Where will the hand of a clock stop, if it
(a) starts at 12 and makes 1/2 of a revolution, clockwise?
(b) starts at 2 and makes 1/2 of a revolution, clockwise?
(c) starts at 5 and makes 1/4 of a revolution, clockwise?
(d) starts at 5 and makes 3/4 of a revolution, clockwise?
Solution :
(a) at 6
(b) at 8
(c) at 8
(d) at 2.

Question 3.
Which direction will you face if you start facing
(a) east and make 1/2 of a revolution clockwise?
(b) east and make 1/2 of a revolution clockwise?
(c) west and make 3/4 of a. revolution anti-clockwise?
(d) south and make one full revolution? (Should we specify clockwise or anti-clockwise for this last question? Why not?)
Solution :
(a) West
(b) West
(c) North
(d) South.
To answer (d), it is immaterial whether we turn clockwise or anti-clockwise because one full revolution will bring us back to the original position.

Question 4.
What part of a revolution have you turned through if you stand to face
(a) east and turn clockwise to face north?
(b) south and turn clockwise to face east?
(c) west and turn clockwise to face east?
Solution :
(a) \(\frac { 3 }{ 4 }\) of a revolution.
(b) \(\frac { 3 }{ 4 }\) of a revolution.
(c) \(\frac { 1 }{ 2 }\) of a revolution.

Question 5.
Find the number of right angles turned through by the hour hand of a clock when it goes from
(a) 3 to 6
(b) 2 to 8
(c) 5 to 11
(d) 10 to 1
(e) 12 to 9
(f) 12 to 9
Solution :
(a) 1 right angle
(b) 2 right angles
(c) 2 right angles
(d) 1 right angle
(e) 3 right angles
(f) 2 right angle

Question 6.
Now many right angles do you make if you start facing
(a) south and turn clockwise to the west?
(b) north and turn anti-clockwise to the east?
(c) west and turn to west?
(d) south and turn to the north?
Solution :
(a) 1 right angle
(b) 3 right angles
(c) 4 right angles
(d) 2 right angles
(clockwise or anticlockwise).

Question 7.
Where will the hour’s hand of a clock stop if it starts
(a) from 6 and turns through 1 right angle?
(b) from 8 and turns through 2 right angles?
(c) from 10 and turns through 3 right angles?
(d) from 7and turns through 2 straight angles?
Solution :
(a) 9
(b) 2
(c) 7
(d) 7.
(We should consider only clockwise direction here).

 

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NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.2

NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.2 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.2.

BoardCBSE
TextbookNCERT
ClassClass 6
SubjectMaths
ChapterChapter 3
Chapter NamePlaying With Numbers
Exercise Ex 3.2
Number of Questions Solved12
CategoryNCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.2

Question 1.
What is the sum of any two :
(a) Odd numbers
(b) Even numbers.
Solution :
(a) The sum of any two odd numbers is an even number.
(b) The sum of any two even numbers is an even number.

Question 2.
State whether the following statements are True or False :

  1. The sum of three odd numbers is even.
  2. The sum of two odd numbers and one even number is even.
  3. The product of three odd numbers is odd.
  4. If an even number is divided by 2, the quotient is always odd.
  5. All prime numbers are odd.
  6. Prime numbers do not have any factors.
  7. Sum of two prime numbers is always even.
  8. 2 is the only even prime number.
  9. All even numbers are composite numbers.
  10. The product of two even numbers is always even.

Solution :

  1. This statement is false.
  2. This statement is true.
  3. This statement is true.
  4. This statement is false.
  5. This statement is false.
  6. This statement is false.
  7. This statement is false.
  8. This statement is true.
  9. This statement is false.
  10. This statement is true.

Question 3.
The numbers 13 and 31 are prime numbers. Both these numbers have the same digits 1 and 3. Find such pairs of prime numbers up to 100.
Solution :
All other such pairs of prime numbers up to 100 are as follows :
17 and 71; 37 and 73; 79 and 97.

Question 4.
Write down separately the prime and composite numbers less than 20.
Solution :
NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers 1
Question 5.
What is the greatest prime number between 1 and 10?
Solution :
The greatest prime number between 1 and 10 is 7.

Question 6.
Express the following as the sum of two odd primes :
(a) 44
(b) 36
(c) 24
(d) 18.
Solution :
(a) 44 = 3+41
(b) 36 = 5 + 31
(c) 24 = 5+19
(d) 18 = 5+13.

Question 7.
Give three pairs of prime numbers whose difference is 2.
[Remark: Two prime numbers whose difference is 2 are called twin primes],
Solution :
The three pairs of prime numbers, whose difference is 2, are as follows :
3, 5 ; 5, 7 ; 11, 13.

Question 8.
Which of the following numbers are prime?
(a) 23
(b) 51
(c) 37
(d) 26.
Solution :
(a) 23,
(c) 37 are prime numbers.

Question 9.
Write seven consecutive composite numbers less than 100 so that there is no prime number between them.
Solution :
90, 91, 92, 93, 94, 95, 96.

Question 10.
Express each of the following numbers as the sum of three odd primes :
(a) 21
(b) 31
(c) 53
(d) 61.
Solution :
(a) 21 = 3 + 5 + 13
(b) 31 = 3 + 5 + 23
(c) 53 = 13+ 17 + 23
(d) 61 =7;+ 13+41.

Question 11.
Write five pairs of prime numbers below 20 whose sum is divisible by 5. (Hint: 3 + 7 – 10).
Solution :
2, 3 ; 2, 13 ; 3, 17 ; 7, 13 ; 11, 19.

Question 12.
Fill in the blanks in the following :

  1. A number which has only two factors is called a
  2. A number which has more than two factors is called a
  3. 1 is neither nor
  4. The smallest prime number is
  5. The smallest composite number is
  6. The smallest even number is

Solution :

  1. A number which has only two factors is called a prime number.
  2. A number which has more than two factors is called a composite number.
  3. 1 is neither prime number nor composite number.
  4. The smallest prime number is 2.
  5. The smallest composite number is 4.
  6. The smallest even number is 2.

 

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NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1.

BoardCBSE
TextbookNCERT
ClassClass 6
SubjectMaths
ChapterChapter 14
Chapter NamePractical Geometry
Exercise Ex 14.1
Number of Questions Solved5
CategoryNCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1

Question 1.
Draw a circle of radius 3.2 cm.
Solution :
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 1
Steps of Construction

  • Open the compasses for the required radius 3.2 cm, by putting the pointer on 0 and opening the pencil upto 3.2 cm.
  • Draw a point with a sharp pencil and marks it as O in the centre.
  • Place the pointer of the compasses where the centre has been marked.
  • Turn the compasses slowly to draw the circle.

Question 2.
With the same centre O, draw two circles of radii 4 cm and 2.5 cm.
Solution :
Steps of Construction
1. For circle of radius 4 cm

  • Open the compasses for the required radius 4 cm, by putting the pointer on 0 and opening the pencil upto 4 cm.
  • Place the pointer of the compasses at O.
  • Turn the compasses slowly to draw the circle.

2. For circle of radius 2.5 cm

  • Open the compasses for the required radius 2.5 cm. by putting the pointer on 0 and opening the pencil upto 2.5 cm.
  • Place the pointer of the compasses at O.
  • Turn the compasses slowly to draw the circle.

Question 3.
Draw a circle and any two of its diameters. If you join the ends of these diameters, what is the figure obtained? What figure is obtained if the diameters are perpendicular to each other? How do you check your answer?
Solution :
(i) On joining the ends of any two diameters of the circle, the figure obtained is a rectangle.
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 2
(ii) On joining the ends of any two diameters of the circle, perpendicular to each other, the figure obtained is a square.
To check the answer, we measured the sides and angles of the figure obtained.
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 3
Question 4.
Draw any circle and mark points A, B and C such that:
(a) A is on the circle.
(b) B is in the interior of the circle.
(c) C is in the exterior of the circle.
Solution :
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 4
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 5

Question 5.
Let A, B be the centres of two circles of equal radii; draw them so that each one of them passes We need a ruler here. through the centre of the other. Let them intersect at C and D. Examine whether \(\overline { AB }\) and \(\overline { CD }\) are at right angles.
Solution :
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 6
Yes! \(\overline { AB }\) and \(\overline { CD }\) are at right angles.

 

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NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1

NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1.

BoardCBSE
TextbookNCERT
ClassClass 6
SubjectMaths
ChapterChapter 12
Chapter NameRatio and Proportion
Exercise Ex 12.1
Number of Questions Solved16
CategoryNCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1

Question 1.
There are 20 girls and 15 boys in a class.
(a) What is the ratio of a number of girls to the number of boys?
(b) What is the ratio of a number of girls to the total number of students in the class?
Solution :
(a) Ratio of number of girls to the number of boys
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 1
(b) Total number of students in the class = 20 + 15 = 35
∴ Ratio of number of girls to the total number of students in the class
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 2

Question 2.
Out of 30 students in a class, 6 like football, 12 like cricket and remaining like tennis. Find the ratio of:
(a) Number of students liking football to a number of students liking tennis.
(b) Number of students liking cricket to the total number of students.
Solution :
(a) Number of students liking tennis = 30-(6+ 12) = 30 – 18 = 12
∴ Ratio of number of students liking football to number of students liking tennis
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 3
(b) Number of students liking cricket to total number of students
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 4

Question 3.
See the figure and find the ratio of:
(a) Number of triangles to the number of circles inside the rectangle.
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 5
(b) Number of squares to all the figures inside the rectangle.
(c) Number of circles to all the figures inside the rectangle.
Solution :
(a) Number of triangle inside the rectangle = 3 . , Number of circles inside the rectangle = 2 Ratio of number of triangles to the number of circles inside the rectangle = \(\frac{ 3 }{ 2 }\) =3:2.
(b) Number of squares inside the rectangle = 2 Number of all the figures inside the rectangle = 7
∴ Ratio of number of squares to all the figures 2
inside the rectangle = \(\frac{ 2 }{ 7 }\) =2:7.
(c) Ratio of number of circles to all the figures inside the rectangle = \(\frac{ 2 }{ 7 }\) =2:1.

Question 4.
Distance travelled by Hamid and Akhtar in an hour are 9 km and 12 km. Find the ratio of speed of Hamid to the speed of Akhtar.
Solution :
Ratio of speed of Hamid to the speed of
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 31
Question 5.
Fill in the following blanks:
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 6
Solution :
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 7
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 8

Question 6.
Find the ratio of the following :
(a) 81 to 108
(b) 98 to 63
(c) 33 km to 121 km
(d) 30 minutes to 45 minutes.
Solution :
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 9
Question 7.
Find the ratio of the following :
(a) 30 minutes to 1.5 hours
(b) 40 cm to 1.5 m
(c) 55 paise to ₹ 1
(d) 500 ml to 2 litres.
Solution :
(a) 1.5 hours = 1.5 × 60 minutes = 90 minutes
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 10
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 11

Question 8.
In a year, Seema earns- ₹ 1,50.000 and saves ₹ 50,000. Find the ratio of:
(a) Money that Seema earns to the money she saves.
(b) Money that she saves to the money that she spends.
Solution :
(a) Ratio of money that Seema earns to the money she saves
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 12
(b) Money that she spends
= ₹ 1,50,000 – ₹ 50,000 = ₹ 1,00,000
∴ Ratio of money she saves to the money she spends
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 13
Question 9.
There are 102 teachers in a school of 3300 students. Find the ratio of the number of teachers to the number of students.
Solution :
Ratio of the number of teachers to the number of students
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 14
Question 10.
In a college, out of4320 students, 2300 are girls. Find the ratio of:
(a) Number of girls to the total number of students.
(b) Number of boys to the number of girls.
(c) Number of boys to the total number of students.
Solution :
(a) Ratio of number of girls to the total number of students
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 15
(b) Number of boys = 4320 – 2300 = 2020
∴ Ratio of number of boys to the number of girl
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 16
(c) Ratio of number of boys to the total number of students
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 17
Question 11.
Out of 1800 students in a school, 750 opted basketball, 800 opted cricket and remaining opted table tennis. If a student can opt only one game, find the ratio of:
(a) Number of students who opted basketball to the number of students who opted table tennis.
(b) Number of students who opted cricket to the number of students opting basketball.
(c) Number of students who opted basketball to the total number of students.
Solution :
(a) Number of students opting table tennis = 1800 – (750 + 800) = 1800 -1550 = 250
∴ Ratio of number of students opting basketball to number of students opting table tennis
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 18
(b) Ratio of number of students opting cricket to the number of students opting basketball
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 19
(c) Ratio of number of students opting basketball to the total number of students
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 20
Question 12.
Cost of a dozen pens is ₹ 180 and cost of 8 ball pens is ₹ 56. Find the ratio of cost of a pen to the cost of a ball pen.
Solution :
1 dozen =12 items
∴ Cost of 12 pens = ₹ 180
∴ Cost of 1 pen = ₹ \(\frac{ 180 }{ 12 }\) = ₹ 15
∴ Cost of 8 ball pens = ₹ 56
∴ Cost of 1 ball pen = ₹ \(\frac{ 56 }{ 8 }\) = ₹ 7
∴ Ratio of cost of a pen to the cost of a ball 15 pen = \(\frac{ 15 }{ 7 }\) =15:7.

Question 13.
Consider the statement: Ratio of breadth and length of a hall 2: 5. Complete the following table that shows some possible breadths and lengths of the hall.
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 21
Solution :
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 22
Hence, the completed table is as follows:
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 23
Question 14.
Divide 20 pens between Sheela and Sangeeta in the ratio 3: 2.
Solution :
Total number of pens = 20 Ratio = 3:2
Sum of the parts = 3 + 2 = 5
∴ Sheel’s shae = \(\frac{ 3 }{ 5 }\) × 20 = 12 and, Samgeeta’s share = \(\frac{ 2 }{ 5 }\) × 20 = 8

Question 15.
Mother wants to divide ₹ 36 between her daughters Shreya and Bhoomika in the ratio of their ages. If the age of Shreya is 15 years and age of Bhoomika is 12 years, find how much Shreya and Bhoomika will get?
Solution :
Total money = ₹ 36
The ratio of the ages of Shreya and Bhoomika
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 24
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 25
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 26
Hence, Shreya will get ₹ 20 and Bhoomika will get ₹ 16.

Question 16.
Present age of the father is 42 years and that of his son is 14 years. Find the ratio of :
(a) Present age of father to the present age of the son.
(b) Age of the father to the age of son, when the son was 12 years old.
(c) Age of father after 10 years to the age of son after 10 years.
(d) Age of father to the age of son when father was 30 years old.
Solution :
(a) Ratio of the present age of father to the present age of the son
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 27
(b) Son was 12 years old 14 – 12 = 2 years before
Age of the father 2 years before = 42 – 2 = 40 years
∴ Ratio of the age of the father to the age of the son. when son was 12 years old
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 28
(c) Age of father after 10 years = 42 + 10 = 52 years
Age of son after 10 years = 14 + 10 = 24 years
∴ Ratio of age of father after 10 years to the age of son after 10 years
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 29
(d) Father was 30 years old 42 – 30 = 12 years before
Age of son 12 years before = 14 – 12 = 2 years
∴ Ratio of the age of father to the age of son when father was 30 years old
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 30

 

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