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	<title>NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4 &#8211; MCQ Questions</title>
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		<title>NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4</title>
		<link>https://mcqquestions.guru/ncert-solutions-for-class-9-maths-chapter-5-ex-5-4/</link>
		
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				<category><![CDATA[CBSE Class 9]]></category>
		<category><![CDATA[NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4]]></category>
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					<description><![CDATA[NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4 are part of NCERT Solutions for Class 9 Maths. Here we have given NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4. Board CBSE Textbook NCERT Class Class 9 Subject Maths Chapter Chapter 5 Chapter Name Triangles Exercise Ex 5.4 Number of ... <a title="NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4" class="read-more" href="https://mcqquestions.guru/ncert-solutions-for-class-9-maths-chapter-5-ex-5-4/" aria-label="Read more about NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4">Read more</a>]]></description>
										<content:encoded><![CDATA[<p>NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4 are part of <a href="https://mcqquestions.guru/ncert-solutions-for-class-9-maths/">NCERT Solutions for Class 9 Maths</a>. Here we have given NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4.</p>
<table style="table-layout: fixed; width: 650px;">
<tbody>
<tr>
<td><strong>Board</strong></td>
<td>CBSE</td>
</tr>
<tr>
<td><strong>Textbook</strong></td>
<td>NCERT</td>
</tr>
<tr>
<td><strong>Class</strong></td>
<td>Class 9</td>
</tr>
<tr>
<td><strong>Subject</strong></td>
<td>Maths</td>
</tr>
<tr>
<td><strong>Chapter</strong></td>
<td>Chapter 5</td>
</tr>
<tr>
<td><strong>Chapter Name</strong></td>
<td>Triangles</td>
</tr>
<tr>
<td><strong>Exercise</strong></td>
<td>Ex 5.4</td>
</tr>
<tr>
<td><strong>Number of Questions Solved</strong></td>
<td>6</td>
</tr>
<tr>
<td><strong>Category</strong></td>
<td><a title="NCERT Solutions" href="https://mcqquestions.guru/ncert-solutions/">NCERT Solutions</a></td>
</tr>
</tbody>
</table>
<h2>NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4</h2>
<p><span style="color: #eb4924;"><strong>Question 1.</strong></span><br />
<strong>Show that in a right angled triangle, the hypotenuse is the longest side.</strong><br />
<span style="color: #008000;"><strong>Solution:</strong></span><br />
Let ABC be a right angled triangle, such that ∠ ABC = 90°<br />
<img decoding="async" class="alignnone size-full wp-image-88628" src="https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-1.png" alt="NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4 img 1" width="159" height="152" /><br />
We know that,<br />
∠ABC + ∠BCA + ∠CAB = 180° (By A property)<br />
⇒ 90° + ∠BCA + ∠CAB = 180°<br />
⇒ ∠BCA + ∠CAB = 90°<br />
From above, we have ∠ BCA and ∠ CAB are acute angles.<br />
⇒ ∠BCA &lt; 90°<br />
and ∠CAB &lt; 90°<br />
⇒ ∠BCA &lt; ∠ABC<br />
and ∠CAB &lt; ∠ABC<br />
⇒ AB &lt; AC and BC &lt; AC (∵ Side opposite to greater angle is longer)<br />
Hence, the hypotenuse (AC) is the longest side.</p>
<p><span style="color: #eb4924;"><strong>Question 2.</strong></span><br />
<strong>In figure, sides AB and AC of ∆ABC are extended to points P and Q respectively. Also, ∠PBC &lt; ∠QCB. Show that AC &gt; AB.</strong><br />
<span style="color: #008000;"><strong>Solution:</strong></span><br />
We know that,<br />
<img decoding="async" class="alignnone size-full wp-image-88629" src="https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-2.png" alt="NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4 img 2" width="146" height="163" /><br />
∠ACB + ∠QCB = 180° (Linear pair)&#8230;(i)<br />
and ∠ABC+ ∠PBC = 180° (Linear pair)&#8230;(ii)<br />
From Eqs. (i) and (ii), we have<br />
∠ABC + ∠PBC = ∠ACB + ∠QCB &#8230;.(iii)<br />
But ∠PBC &lt; ∠QCB (Given)&#8230;(iv) From Eqs. (iii) and (iv), we have ∠ ABC &gt; ∠ ACB<br />
⇒ AC &gt; AB<br />
(∵ Side opposite to greater angle is longer)</p>
<p><span style="color: #eb4924;"><strong>Question 3.</strong></span><br />
<strong>In figure, ∠B &lt;∠ A and ∠C &lt;∠ D. Show that AD &lt; BC.</strong><br />
<span style="color: #008000;"><strong>Solution:</strong></span><br />
<img fetchpriority="high" decoding="async" class="alignnone size-full wp-image-88630" src="https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-3.png" alt="NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4 img 3" width="524" height="289" srcset="https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-3.png 524w, https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-3-300x165.png 300w" sizes="(max-width: 524px) 100vw, 524px" /></p>
<p><span style="color: #eb4924;"><strong>Question 4.</strong></span><br />
<strong>AB and CD are respectively the smallest and longest sides of a quadrilateral ABCD (see figure). Show that ∠ A&gt; ∠C and ∠B &gt; ∠D.</strong><br />
<img loading="lazy" decoding="async" class="alignnone size-full wp-image-88631" src="https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-4.png" alt="NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4 img 4" width="134" height="109" /><br />
<span style="color: #008000;"><strong>Solution:</strong></span><br />
Given ABCD is a quadrilateral. AB is the smallest side and CD is the longest side.<br />
To prove ∠A &gt; ∠C and ∠B &gt; ∠D<br />
Construction Join A to C and B to D.<br />
Proof In ∆ABC, we have AB is the smallest side.<br />
∴ AB &lt; BC<br />
⇒ ∠5 &lt; ∠1<br />
<img loading="lazy" decoding="async" class="alignnone size-full wp-image-88632" src="https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-5.png" alt="NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4 img 5" width="154" height="146" /><br />
(∵ Angle opposite to longer side is greater) &#8230;(i)<br />
In ∆ADC, we have CD is the largest side.<br />
<img loading="lazy" decoding="async" class="alignnone size-full wp-image-88633" src="https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-6.png" alt="NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4 img 6" width="530" height="337" srcset="https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-6.png 530w, https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-6-300x191.png 300w" sizes="(max-width: 530px) 100vw, 530px" /></p>
<p><span style="color: #eb4924;"><strong>Question 5.</strong></span><br />
<strong>In figure, PR &gt; PQ and PS bisect ∠QPR. Prove that</strong><br />
<strong>∠PSR &gt;∠PSQ.</strong><br />
<img loading="lazy" decoding="async" class="alignnone size-full wp-image-88634" src="https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-7.png" alt="NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4 img 7" width="156" height="137" /><br />
<span style="color: #008000;"><strong>Solution:</strong></span><br />
In ∆ PQR, we have<br />
PR &gt; PQ (Given)<br />
⇒ ∠ PQR &gt; ∠ PRQ &#8230;(i)<br />
(∵ Angle opposite to longer side is greater)<br />
<img loading="lazy" decoding="async" class="alignnone size-full wp-image-88635" src="https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-8.png" alt="NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4 img 8" width="528" height="200" srcset="https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-8.png 528w, https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-8-300x114.png 300w" sizes="(max-width: 528px) 100vw, 528px" /><br />
<img loading="lazy" decoding="async" class="alignnone size-full wp-image-88636" src="https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-9.png" alt="NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4 img 9" width="536" height="233" srcset="https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-9.png 536w, https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-9-300x130.png 300w" sizes="(max-width: 536px) 100vw, 536px" /></p>
<p><span style="color: #eb4924;"><strong>Question 6.</strong></span><br />
<strong>Show that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.</strong><br />
<span style="color: #008000;"><strong>Solution:</strong></span><br />
Given x is a line and A is a point not lying on x. AB ⊥ x, Cis any point on x other than B.<br />
<img loading="lazy" decoding="async" class="alignnone size-full wp-image-88637" src="https://mcqquestions.guru/wp-content/uploads/2020/12/NCERT-Solutions-for-Class-9-Maths-Chapter-5-Triangles-Ex-5.4-img-10.png" alt="NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4 img 10" width="191" height="152" /><br />
To prove AB∠C<br />
⇒ AC&gt; AB<br />
(∵ the Side opposite to greater angle is longer)<br />
⇒ AB &lt; AC<br />
Hence, the perpendicular line segment is the shortest.<br />
We hope the NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4 help you. If you have any query regarding NCERT Solutions for Class 9 Maths Chapter 5 Triangles Ex 5.4, drop a comment below and we will get back to you at the earliest.</p>
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