RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.2
These Solutions are part of RD Sharma Class 10 Solutions. Here we have given RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.2
Other Exercises
- RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.1
- RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.2
- RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.3
- RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.4
- RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.5
- RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions Ex 5.6
- RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions VSAQS
- RD Sharma Class 10 Solutions Chapter 5 Arithmetic Progressions MCQS
Question 1.
 Show that the sequence defined by an = 5n – 7 is an A.P., find its common difference.
 Solution:
 
Question 2.
 Show that the sequence defined by an = 3n² – 5 is not an A.P.
 Solution:
 
Question 3.
 The general term of a sequence is given by an = -4n + 15. Is the sequence an A.P.? If so, find its 15th term and the common difference.
 Solution:
 General term of a sequence
 an = -4n + 15
 
Question 4.
 Write the sequence with nth term :
 (i) an = 3 + 4n
 (ii) an = 5 + 2n
 (iii) an = 6 – n
 (iv) an = 9 – 5n
 Show that all of the above sequences form A.P.
 Solution:
 
 
Question 5.
 The nth term of an A.P. is 6n + 2. Find the common difference. [CBSE 2008]
 Solution:
 
Question 6.
 Justify whether it is true to say that the sequence, having following nth term is an A.P.
 (i) an = 2n – 1
 (ii) an = 3n² + 5
 (iii) an = 1 + n + n²
 Solution:
 
 
 
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