ML Aggarwal Class 7 Solutions Chapter 14 Symmetry Objective Type Questions for ICSE Understanding Mathematics acts as the best resource during your learning and helps you score well in your exams.
ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 14 Symmetry Objective Type Questions
Mental Maths
Question 1.
 Fill in the blanks:
 (i) The hands of a clock rotate only in ………. direction.
 (ii) While opening the cap of a bottle, the direction of rotation is ……….
 (iii) The number of lines of symmetry of an isosceles right-angled triangle is …………
 (iv) A figure has ……….. symmetry if it is its own image under a reflection.
 (v) The centre of rotation of an equilateral triangle is the point of intersection of its ………..
 (vi) The centre of rotation of a rhombus is the point ……….
 (vii) A regular polygon of n-sides has ……….. the number of lines of symmetry.
 (viii) The angle of rotational symmetry in an equilateral triangle is ……….
 (ix) The angle of rotational symmetry in a regular pentagon is ……..
 (x) If after a rotation of 45° about a fixed point the figure looks exactly the same, then the order of rotational symmetry is ……….
 Solution:
 
Question 2.
 State whether the following statements are true (T) or false (F):
 (i) The letter A has line symmetry but no rotational symmetry.
 (ii) A rhombus is also a parallelogram and hence it does not have line symmetry.
 (iii) A parallelogram has two lines of symmetry.
 (iv) The order of rotational symmetry of a rhombus is four.
 (v) A circle has exactly four lines of symmetry.
 (vi) In a regular pentagon, the perpendicular bisector of the sides are the only lines of symmetry.
 (vii) In a regular hexagon, the perpendicular bisector of the sides are the only lines of symmetry.
 (viii) In a rectangle, the angle of rotational symmetry is 90°.
 (ix) A semicircle has rotational symmetry of order 2.
 (x) An isosceles triangle has neither a line symmetry nor a rotational symmetry.
 (xi) If a figure possesses a rotational symmetry, then it must look exactly the same atleast once up to a rotation of 180°.
 (xii) The angle of rotation of a figure is obtained by dividing 360° by the order of rotational symmetry.
 (xiii) A regular triangle has 3 lines of symmetry and rotational symmetry of order 3.
 (xiv) A regular pentagon has 5 lines of symmetry and rotational symmetry of order 5.
 Solution:
 
 
Multiple Choice Questions
Choose the correct answer from the given four options (3 to 14):
 Question 3.
 A quadrilateral having four lines of symmetry is a
 (a) parallelogram
 (b) rectangle
 (c) rhombus
 (d) square
 Solution:
 
Question 4.
 The letter Z has
 (a) one horizontal line of symmetry
 (b) one vertical line of symmetry
 (c) two lines of symmetry
 (d) no line of symmetry
 Solution:
 
Question 5.
 A figure that does not have any rotational symmetry is
 (a) circle
 (b) parallelogram
 (c) kite
 (d) regular pentagon
 Solution:
 
Question 6.
 The number of lines of symmetry in the given figure is
 (a) 1
 (b) 3
 (c) 6
 (d) infinitely many
 
 Solution:
 
Question 7.
 Rotating a figure by 60° anticlockwise is equivalent to a clockwise rotation of
 (a) 60°
 (b) 120°
 (c) 240°
 (d) 300°
 Solution:
 
Question 8.
 A figure having 1 line of symmetry and whose order of rotational symmetry is also 1 is
 (a) rhombus
 (b) parallelogram
 (c) kite
 (d) scalene triangle
 Solution:
 
Question 9.
 The order of rotational symmetry of a line segment is
 (a) 1
 (b) 2
 (c) 3
 (d) 4
 Solution:
 
Question 10.
 The order of the rotational symmetry in the given figure is
 (a) 1
 (b) 2
 (c) 4
 (d) infinitely many
 
 Solution:
 
Question 11.
 A possible angle of rotation of a figure having rotational symmetry of order greater than 1 is
 (a) 36°
 (b) 144°
 (c) 150°
 (d) 360°
 Solution:
 
Question 12.
 The figure which does not have both reflection and rotational symmetry is
 
 Solution:
 
Question 13.
 In the word ’MATHS’ which of the following pairs of letters have rotational symmetry?
 (a) M and T
 (b) A and S
 (c) T and S
 (d) H and S
 Solution:
 
Question 14.
 The letter which has both reflection and rotational symmetry is
 (a) H
 (b) M
 (c) S
 (d) Y
 Solution:
 