CBSE Class 7

RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2C

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2C.

Other Exercises

• RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2A
• RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2B
• RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2C
• RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2D
• RS Aggarwal Solutions Class 7 Chapter 2 Fractions CCE Test Paper

Question 1.
Solution:

Question 2.
Solution:

Question 3.
Solution:

Question 4.
Solution:

Question 5.
Solution:
Total weight of 18 boxes

Question 6.
Solution:
Total amount of oranges=Rs 378

Question 7.
Solution:

Question 8.
Solution:

Question 9.
Solution:

Question 10.
Solution:

Question 11.
Solution:

Question 12.
Solution:

Question 13.
Solution:
Total quantity of milk = 24 litres
and quantity of milk got by one student = \(\frac { 2 }{ 5 }\) litres

Question 14.
Solution:
Quantity of water in a bucket

Question 15.
Solution:

Question 16.
Solution:
Product of two numbers = 42

Question 17.
Solution:

Hope given RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2C are helpful to complete your math homework.

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RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2B

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2B.

Other Exercises

• RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2A
• RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2B
• RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2C
• RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2D
• RS Aggarwal Solutions Class 7 Chapter 2 Fractions CCE Test Paper

Question 1.
Solution:

Question 2.
Solution:

Question 3.
Solution:

Question 4.
Solution:

Question 5.
Solution:
Cost of 1 metre pf cloth

Question 6.
Solution:
Distance covered in 1 hour

Question 7.
Solution:

Question 8.
Solution:

Question 9.
Solution:

Question 10.
Solution:

Question 11.
Solution:
Weight of Amit = 35 kg.

Question 12.
Solution:
Total number of students in a class = 42
Number of boys = \(\frac { 5 }{ 7 }\) of 42 = 5 x 6 = 30
Number of girls = 42 – 30 = 12

Question 13.
Solution:
Sapna total income for one month = Rs 24000
Amount spent = \(\frac { 7 }{ 8 }\) of her income
= \(\frac { 7 }{ 8 }\) x 24000
= Rs (7 x 3000) = Rs 21000
Amount deposited in the bank per month = Rs 24000 – 21000 = Rs 3000

Question 14.
Solution:
Length of each side of a square

Question 15.
Solution:
Length of rectangular field (l)

Hope given RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2B are helpful to complete your math homework.

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RS Aggarwal Class 7 Solutions Chapter 2 Fractions Ex 2A

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2A.

Other Exercises

• RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2A
• RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2B
• RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2C
• RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2D
• RS Aggarwal Solutions Class 7 Chapter 2 Fractions CCE Test Paper

Question 1.
Solution:

Question 2.
Solution:

Question 3.
Solution:

Question 4.
Solution:
Reenu get \(\frac { 2 }{ 7 }\) of an apple while Sonal gets \(\frac { 4 }{ 5 }\) part of it

Question 5.
Solution:

Question 6.
Solution:

Question 7.
Solution:

Question 8.
Solution:

Question 9.
Solution:

Question 10.
Solution:

Question 11.
Solution:
For finding the required fraction, we have to subtract 7\(\frac { 3 }{ 5 }\) from 18

Question 12.
Solution:
For finding the required fraction we should subtract 7\(\frac { 4 }{ 15 }\) from 8\(\frac { 2 }{ 5 }\)

Question 13.
Solution:

Question 14.
Solution:

Question 15.
Solution:

Question 16.
Solution:

Hope given RS Aggarwal Solutions Class 7 Chapter 2 Fractions Ex 2A are helpful to complete your math homework.

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RS Aggarwal Class 7 Solutions Chapter 1 Integers CCE Test Paper

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 1 Integers CCE Test Paper.

Other Exercises

• RS Aggarwal Solutions Class 7 Chapter 1 Integers Ex 1A
• RS Aggarwal Solutions Class 7 Chapter 1 Integers Ex 1B
• RS Aggarwal Solutions Class 7 Chapter 1 Integers Ex 1C
• RS Aggarwal Solutions Class 7 Chapter 1 Integers Ex 1D
• RS Aggarwal Solutions Class 7 Chapter 1 Integers CCE Test Paper

Question 1.
Solution:
Let the other integer be a. Then, we have;
a + (-12) = 43
⇒ a = 43 – (-12) = 55
Hence, the other integer is 55.

Question 2.
Solution:
p – (-8) = 3
⇒ p = 3 + (-8)
⇒ p = -5
Hence, the value of p is -5.

Question 3.
Solution:
Product of (-16) and (-9) = (-16) x (-9) = 144
Now, (-132) ÷ 6 gives the quotient -22.
144 + (-22) = 122

Question 4.
Solution:
Suppose that a divides -240 to obtain 16. Then, we have:
(-240) ÷ a =16
⇒ a = (-240) ÷ 16 = -15
Hence, -15 should divide -240 to obtain 16.

Question 5.
Solution:
Let a be divided by (-7) to obtain 12. Then, we have:
a ÷ (-7) = 12
a = \(\frac { -7 }{ 12 }\)
Hence, \(\frac { -7 }{ 12 }\) should be divided by -7 to obtain 12.

Question 6.
Solution:
(i) -450
(ii) 360
(iii) -1080
(iv) -600
(v) (-5)5 = -3125
(vi) (-1)25 = -1

Question 7.
Solution:
(i) (-16) x 12 + (-16) x 8 = (-16) x (12 + 8) [Associative property]
= (-16) x 20
= -320
(ii) 25 x (-33) + 25 x (-17)
= 25 x [(-33) + (-17)] [Associative property]
= 25 x (-50)
= -1250
(iii) (-19) x (-25) + (-19) x (-15)
= (-19) x [(-25) + (-15)] [Associative property]
= (-19) x (-40)
= 760
(iv) (-47) x 68 – (-47) x 38
= (-47) x (68 – 38) [Asssociative property]
= (-47) x 30
= -1410
(v) (-105) ÷ 21
(-105) ÷ 21 = -5
(vi) (-168) ÷ (-14) = 12
(vii) 0 ÷ (-34)
= 0 (zero).
Dividing 0 by any integer gives 0.
(viii) 37 ÷ 0
Not defined.
Dividing any integer by zero is not defined.

Mark (√) against the correct answer in each of the following:
Question 8.
Solution:
(d) -8
Let the other integer be a. Then, we have:
2 + a = -6
⇒ a = -6 – 2 = -8
⇒ The other integer is -8.

Question 9.
Solution:
(b) 8
Suppose that a is subtracted from (-7). Then, we have
-7 – a = -15
a = -7 + 15 = 8
8 must be subtracted from -7 to obtain-15.

Question 10.
Solution:
(b) 108
(108) + (-18) = -6

Question 11.
Solution:
(a) 370
= (-37) x (-7) + (-37) x (-3)
= (-37) x [(-7) + (-3)] [Associative property]
= (-37) x (-10)
= 370

Question 12.
Solution:
(c) -250
=(-25) x 8 + (-25) x 2
= (-25) x (8 + 2) [Associative property]
= (-25) x 10 = -250

Question 13.
Solution:
(b) -3
(-9) – (-6)
= (-9) + 6
= -3

Question 14.
Solution:
(b) -6
-8 – (-6) = 2
Hence, -8 is -6 less than -2.

Question 15.
Solution:
(i) (-35) x -1 = 35
(ii) (-53) x (1) = -53
(iii) (-14) x (-1) = (-16) x (-14) [Commutative property]
(iv) (-21) x (0) = 0 [Property of zero]
(v) (-119) ÷ 17 = (-7)
(vi) (-247) ÷ (-19) = 13
(vii) (0) ÷ 31 = 0
(viii) (152) ÷ (-19) = -8

Question 16.
Solution:
(i) True (T)
(ii) (-8) ÷ 0 = 0
False (F). Dividing any integer by zero is not defined.
(iii) False (F).
(-1) ÷ (-1) = 1
(iv) True (T)
(v) True(T)
(vi) False (T).
68 ÷ (-17) = -4

Hope given RS Aggarwal Solutions Class 7 Chapter 1 Integers CCE Test Paper are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

RS Aggarwal Class 7 Solutions Chapter 1 Integers Ex 1D

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 1 Integers Ex 1D.

Other Exercises

• RS Aggarwal Solutions Class 7 Chapter 1 Integers Ex 1A
• RS Aggarwal Solutions Class 7 Chapter 1 Integers Ex 1B
• RS Aggarwal Solutions Class 7 Chapter 1 Integers Ex 1C
• RS Aggarwal Solutions Class 7 Chapter 1 Integers Ex 1D
• RS Aggarwal Solutions Class 7 Chapter 1 Integers CCE Test Paper

OBJECTIVE QUESTIONS
Mark (√) against the correct answer in each of the following.
Question 1.
Solution:
(c)
6 – (-8) = 6 + 8 = 14

Question 2.
Solution:
(b)
-9 – (-6) = -9 + 6 = -3

Question 3.
Solution:
(d)
-3 + 5 = 2

Question 4.
Solution:
(a)
-1 – (+5) = -1 – 5 = -6

Question 5.
Solution:
(a)
-2 – (4) = -2 – 4 = -6

Question 6.
Solution:
(b)
-4 – (+4) = -4 – 4 = -8

Question 7.
Solution:
(b)
-3 – (-5) = -3 + 5 = 2

Question 8.
Solution:
(c)
-3 – (-9) = -3 + 9 = 6

Question 9.
Solution:
(c)
-5 – (6) = -5 – 6 = -11

Question 10.
Solution:
(c)
-8 – (-13) = -8 + 13 = 5

Question 11.
Solution:
(a)
(-36) ÷ (-9) = 4

Question 12.
Solution:
(b)
0 ÷ (-5) = 0
(Zero divided by any integer other than zero, is zero)

Question 13.
Solution:
(c)
Division by zero is not defined

Question 14.
Solution:
(b)

Question 15.
Solution:
(b)
-3 + 9 = 6

Question 16.
Solution:
(a)
-4 – (-10) = -4 + 10 = 6

Question 17.
Solution:
(a)
Sum = 14
One integer = -8
Second = 14 – (-8) = 14 + 8 = 22

Question 18.
Solution:
(c)

Question 19.
Solution:
(b)
(-15) x 8 + (-15) x 2
= (-15) {8 + 2}
= -15 x 10 = -150

Question 20.
Solution:
(b)
(-12) x 6 – (-12) x 4 = (-12) (6 – 4) = -12 x 2 = -24

Question 21.
Solution:
(b)
(-27) x (-16)+ (-27) x (-14)
= (-27) {-16 – 14}
= (-27) x (-30)
= 810

Question 22.
Solution:
(a)
30 x (-23) + 30 x 14
= 30 x (-23 + 14)
= 30 x (-9)
= -270

Question 23.
Solution:
(c)
Sum of two integers = 93
One integer = -59
Second = 93 – (-59) = 93 + 59 = 152

Question 24.
Solution:
(b)
(?) ÷ (-18) = -5
Let x ÷ (-18) = -5
⇒ \(\frac { x }{ -18 }\) = -5
⇒ x = (-5) x (-18) = 90

Hope given RS Aggarwal Solutions Class 7 Chapter 1 Integers Ex 1D are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.