CBSE Class 6 – Page 58 – MCQ Questions

Who Did Patrick’s Homework? Extra Questions and Answers Class 6 English Honeysuckle

January 5, 2022July 28, 2020 by Prasanna

Here we are providing Who Did Patrick’s Homework Extra Questions and Answers Class 6 English Honeysuckle, Extra Questions for Class 6 English was designed by subject expert teachers.

Who Did Patrick’s Homework Extra Questions and Answers Class 6 English Honeysuckle

Who Did Patrick’s Homework Extra Questions and Answers Short Answer Type

Question 1.
Did Patrick like doing homework?
Answer:
No, Patrick didn’t like it. According to Patrick, homework was too boring.

Question 2.
What were the indoor and outdoor games Patrick liked to play?
Answer:
He liked to play two outdoor games, hockey and basketball and one indoor game, Nintendo.

Question 3.
Did the elf-like to do what Patrick had asked?
Answer:
No, but he had to do it because he had granted a wish to Patrick.

Question 4.
What was the tiny man wearing?
Answer:
The tiny man wore a woollen shirt with old fashioned britches and tall hat.

Question 5.
Why did Patrick hate to do a home work? Give your views in details.
Answer:
Patrick never liked to do his homework. He hated to do his homework because for him it was too boring. Instead of doing his homework, he used to play hockey basketball and Nintendo.

Question 6.
How did Patrick get the elf to do his homework?
Answer:
One day Patrick saw his cat playing with a doll when Patrick grabbed it he found out that it was not a doll but a man of tinniest size. The elf yelled at Patrick to save from the cat and he will grant him a wish. Patrick saved him from the cat and, wished that elf should do his homework for one semester that is for 35 days.

Question 7.
What did Patrick think his cat was playing with? What was it really?
Answer:
Patrick thought that his cat was playing with a doll, but in reality it was an elf (man of tinniest size).

Question 8.
Why did the little man grant Patrick a wish?
Answer:
The little man granted a wish to Patrick because Patrick saved him from cat.

Question 9.
What was Patrick’s wish?
Answer:
Patrick wished that the elf will do all his homework till the end of semester, which was of 35 days.

Question 10.
In what subjects did the little man need help, to do Patrick’s homework?
Answer:
To do Patrick’s homework the little man needed help in English, Mathematics and Human history.

Question 11.
How did Patrick help him?
Answer:
Patrick helped him by bringing books from library, consulting a dictionary, guiding the little man in doing sums of arithmetic and read out portions from history book.

Question 12.
Who do you think did Patrick’s homework- the little man, or Patrick himself? Give reasons for your answers.
Answer:
Patrick himself did his homework as little man did not know anything, in English, math’s and human history. Patrick had to consult dictionary, guide him with math’s rules and helped him to read too. He stayed up at nights and worked hard. Therefore, it was Patrick who did the homework.

Who Did Patrick’s Homework Extra Questions and Answers Long Answer Type

Question 1.
While helping the elf in doing the homework, Patrick did his own homework. Do you think self- help is the best help?
Answer:
Patrick was a lazy boy who love to play hockey, basketball and Nintendo, but when the elf gave him the wish that he would do all his homework for a semester. Patrick became very happy. To his surprise the elf did not know anything about his homework. The elf asked Patrick to help him in English, Mathematics and Human history. To help them Patrick has started going to library, tried to solve the sums, read human history to explain everything to elf.

So that elf do his homework. But Patrick not even once realized that he was studying everything and helping the elf in doing his homework. At the end of the semester Patrick got A grade and had developed a changed attitude and behaviour. All this . was the result of Patrick’s sheer hard work that he did while helping the elf. Now he was a completely changed boy, developed a whole new positive attitude. His teachers and parents were now proud of him. We can say that self-help is best help because if elf would have done Patrick’s homework than Patrick would not be a changed boy. He might have been same as earlier but now he has developed a liking towards study and his home work.

Question 2.
Children don’t like doing homeworks, Explain by giving examples from the chapter about the importance of doing homework.
Answer:
Homework is a really important task of learning days. It is a kind of revision for the work done in the class; It helps in preparing and understanding the chapter. Patrick did all his homework while he was helping the elf. He studied human history, practiced math and English too.

During this entire period he had developed a liking towards study. Now he was not feeling that homework is too boring. All the concepts and topics were now clear to him, had developed a whole new attitude. He got A grades. All this happened because of homework he did. So it is very important for all the students to do their homework.

Who Did Patrick’s Homework Extra Questions and Answers Reference to Context

Question 1.
Then one day he found his cat playing with a little doll and he grabbed it away. To his surprise it wasn’t a doll at all, but a man of the tiniest size. He had a little wool shirt with old fashioned britches and a high tall hat much like a witch’s. He yelled, “Save me! Don’t give me back to that cat. I’ll grant you a wish, I promise you that.”

(i) The elf was grabbed by a
(ii) Elf promised Patrick to if he saves his life.
(iii) Who yelled ‘Save me’?
(iv) The hat worn by elf was
(v) Synonym of short trouser is
Answer:
(i) Cat
(ii) Grant a wish
(iii) Elf
(iv) High
(v) Britches

Question 2.
“I don’t know this word,” the elf squeaked while reading Patrick’s homework. “Get me a dictionary. No, what’s even better, look up the word and sound it out by each letter.” When it came to maths, Patrick was out of luck. “What are times tables?” the elf shrieked. “We elves never need that. And addition and subtraction and division and fractions? Here, sit down beside me, you simply must guide me.” Elves know nothing of human history, to them it’s a mystery. So the little elf, already a shouter, just got louder. “Go to the library, I need books. More and more books. And you can help me read them too.”

(i) The elf took help of Patrick in reading
(ii) Elves never Practise
(iii) Patrick guided him ….. Mathematics
(iv) History was ……… for elves.
Answer:
(i) to look up for meaning
(ii) Maths
(iii) in
(iv) Mystery

Question 3.
Finally, the last day of school arrived and the elf was free to go. As for homework, there was no more, so he quietly and slyly slipped out the back door. Patrick got his A’s; his classmates were amazed; his teachers smiled and were full of praise. And his parents? They wondered what had happened to Patrick. He was now the model kid. Cleaned his room, did his chores, was cheerful, never rude, like he had developed a whole new attitude.

(i) The elf was free to go because
(ii) The word similar to the meaning ‘sly’ is
(iii) Patrick was the model kid as
(iv) Antonym of cheerful is
(v) The best achievement of Patrick was that he scored A grade.
Answer:
(i) It was the last day of the school
(ii) Secretively or cunningly
(iii) he had developed a new attitude
(iv) Sad
(v) Had

Extra Questions for Class 6 English Honeysuckle, A Pact with the Sun

January 5, 2022July 24, 2020 by Veer

CBSE Extra Questions for Class 6 English: Here we are providing NCERT Extra Questions for Class 6 English Honeysuckle, A Pact with the Sun. Students can get Class 6 English NCERT Solutions, Chapter Wise CBSE Class 6 English Extra Important Questions and Answers were designed by subject expert teachers.

Want to explore more about the English language in class 6 to score more marks in the final exam? Then, this article is the best choice for you. Here we have compiled a list of extra questions for class 6 English which are created by subject experts based on NCERT Syllabus prescribed by CBSE. View the list & access the links to download important English questions with answers free pdf and prepare well for the annual examination.

Extra Questions for Class 6 English Honeysuckle, A Pact with the Sun Important Questions

For more practice on the English language, checkout the below-given pdf links & prepare well with Extra Questions for Class 6 English with Answers.

Extra Questions for Class 6 English Honeysuckle Prose

Extra Questions for Class 6 English Honeysuckle Poem

Extra Questions for Class 6 English A Pact with the Sun

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RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A

January 5, 2022April 29, 2019 by Prasanna

RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A.

Other Exercises

Question 1.
Solution:
Steps of construction :
(i) Draw a line segment PQ = 6.2 cm
RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A Q1.1
(ii) With centre P and Q and radius more than half of PQ, draw arcs on each side intersecting each other at L and M.
(iii) Join LM intersecting PQ at N.
Then, LM is the perpendicular bisector of PQ.

Question 2.
Solution:
Steps of Construction :
1. Draw a line segment AB = 5.6 cm.
2. With A as centre and radius more than half AB, draw arcs, one one each side of AB.
RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A Q2.1
3. With B as centre and same radius as before, draw arcs, cutting the previous arcs at P and Q respectively.
4. Join P and Q, meeting AB at M. Then PQ is the required perpendicular bisector of AB.
Verification : Measure ∠AMP. We see that ∠AMP = 90°. So, PQ is the perpendicular bisector of AB.

Question 3.
Solution:
Steps of Contruction :
1. Draw a ray RX.
2. With O as centre and any radius draw an arc cutting OA and OB at P and Q respectively.
RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A Q3.1
3. With R as centre and same radius draw an arc cutting RX at S.
4. With S as centre and radius PQ cut the arc through S at T.
5. Join RT and produce it to Y. Then ∠XRY is the required angle equal to ∠AOB.
Verification: Measuring angle AOB and ∠XRY, we observe that ∠XRY = ∠AOB.

Question 4.
Solution:
Steps of constructions :
(i) Draw an angle ABC = 50° with the help of a protractor.
RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A Q4.1
(ii) With centre B and C and a suitable radius, draw an arc meeting AB at Q and BC at P.
(iii) With centres P and Q and with a suitable radius draw two arcs intersecting each other at R inside the angle ABC.
(iv) JoinRB.
Then ray BR is the bisector of ∠ABC.

Question 5.
Solution:
Steps of construction :
(i) Draw an angle AOB = 85° with the help of the protractor.
RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A Q5.1
(ii) With centre O, draw an arc with a suitable radius meeting OB at E and OA at F.
(iii) With centre E and F and with a suitable radius draw arcs intersecting each other at X inside the angle AOB.
Then ray OX is the bisector of ∠AOB.

Question 6.
Solution:
Steps of Construction :
(1) Draw the given line AB and take a point P on it.
RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A Q6.1
(2) With P as centre and any suitable radius draw a semi-circle to cut the line AB at X and Y.
(3) With centre X and radius more than XP draw an arc.
(4) With centre Y and same radius draw another arc to cut the previous arc at
(5) Join PQ. Then, PQ is the required line passing through P and perpendicular to AB.
Verification : Measure ∠APQ, we see that ∠APQ = 90°

Question 7.
Solution:
Steps of Construction :
(1) Draw the given line AB and take a point P outside it.
RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A Q7.1
(2) With P as centre and suitable radius, draw an arc intersecting AB at C and D.
(3) With C as centre and radius more than half CD, draw an arc.
(4) With D as centre and same radius, draw another arc to cut the previous arc at Q.
(5) Join PQ, meeting AB at L. Then PL is the required line passing through P and perpendicular to AB.
Verification : Measure ∠PLB. We see that ∠PLB = 90°.

Question 8.
Solution:
Steps of Construction :
1. Draw a given line AB and take a point P outside it.
RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A Q8.1
2. Take a point R on AB
3. Join PR.
4. Draw ∠RPQ such that ∠RPQ = ∠PRB as shown in the figure.
5. Produce PQ on both sides to form a line. Then, PQ is the required line passing through P and parallel to AB.
Verification: Since ∠RPQ = ∠PRB and these are alternate interior angles, it follows that PQ || AB.

Question 9.
Solution:
Steps of Construction :
1. Draw a ray BX and cut of BC = 5 cm.
2. With B as centre and suitable radius draw an arc above BX and cutting it at P.
RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A Q9.1
3. With P as centre and the same radius as before draw another arc to cut the previous arc at Q.
4. Join PQ and produce it to the point A such that. AB = 4.5 cm. Then ∠ABC = 60° is the required angle.
5. Draw ∆RAB such that ∆RAB = ∆ABC.
6. Produce RA on both sides to form a line. Then, RY is the line parallel to BC and passing through A.
7. Now, draw ∆SCX = ∆ABC at the point C.
8. Produce CS to intersect the line RY at D.Then CD is the required line through C and parallel to AB.
9. Measure AB and CD. We see that AD = 5 cm. and CD = 4.5 cm.
Verification. Since ∠RAB = ∠ABC and these are alternate angles, it follows that RY || BC.
Also ∠SCX = ∠ABC and these are corresponding angles, it follows that CD || AB.

Question 10.
Solution:
Steps of Construction :
1. With the help of a rular, draw a line segment AB = 6 cm. and off AC = 2.5 cm such that the point C is on AB.
RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A Q10.1
2. With C as centre and any suitable radius draw a semi-circle to cut AB at P and
3. With P as centre and any radius more than PC draw an arc.
4. With Q as centre and same radius draw another arc to cut the previous arc at D.
5. Join CD. Then CD is the required line perpendicular to AB.
Verification : Measure ∠ACD. We see that ∠ACD = 90°.

Question 11.
Solution:
Steps of Construction :
1. With the help of rular, draw a line segment AB = 5.6 cm.
RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A Q11.1
2. With A as centre and radius more than half AB, draw arcs, one on each side of AB.
3. With B as centre and the same radius as before draw arcs, cutting the previous arcs at P and Q respectively.
4. Join PQ, meeting AB at M. Then, PQ is the required right bisector of AB.
Verification : On measuring AM and BM and ∠AMP, we see that AM = BM and ∠AMP = 90°.
So, PQ is the right bisector of AB.

Question 12.
Solution:
Steps of Construction :
1. With the help of a rular, draw a ray OA.
2. With O as centre and suitable radius draw an arc to cut OA at P.
RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A Q12.1
3. With P as centre and the same radius, draw another are to cut the previous arc at Q.
4. Join OQ and produce it to any point B, then ∠AOB = 60° is the required angle.
5. With P as centre and radius more than half PQ, draw an arc.
6. With Q as centre and the same radius, draw another arc to cut the previous arc at R.
7. Join OR and produce it to the point C. Then OC is the required bisector of ∠AOB.
Verification : Measure ∠AOC and ∠BOC. We see that ∠AOC = ∠BOC. So, OC is the bisector of ∠AOB.

Question 13.
Solution:
Steps of construction :
1. Draw a ray OA with the help of a rular.
2. With O as centre and suitable radius draw an arc above OA to cut it at P.
RS Aggarwal Class 6 Solutions Chapter 14 Constructions (Using Ruler and a Pairs of Compasses) Ex 14A Q13.1
3. With P as centre and same radius, cut the arc at Q and again with Q as centre and same radius cut the arc at R. With R as centre and same radius, again cut the arc at S.
4. Join OR and produce it to B and join OS and produce it to C.
5. Draw the bisector OD of ∠BOC.
6. Draw the bisector OE of ∠BOD. Then, ∠AOE = 135° is the required angle.

Hope given RS Aggarwal Solutions Class 6 Chapter 14 Constructions Ex 14A are helpful to complete your math homework.

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RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13D

January 5, 2022April 29, 2019 by Prasanna

RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13D

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 13 Angles and Their Measurement Ex 13D.

Other Exercises

Objective questions
Mark against the correct answer in each of following.

Question 1.
Solution:
(c) vertex of an angle lie on it.

Question 2.
Solution:
(c) an angle.

Question 3.
Solution:
(c) A straight angle has 180°

Question 4.
Solution:
An angle measuring 90° is called a right angle. (b)

Question 5.
Solution:
An angle measuring 91° is an obtuse angle as it is more than 90° and less than 180°.(b)

Question 6.
Solution:
An angle measuring 270° is a reflex angles as it is greater than 180° and less than 360°. (d)

Question 7.
Solution:
(c) A straight angle is equal to 180°

Question 8.
Solution:
(c) A reflex angles is greater than 180° but less than 360°

Question 9.
Solution:
(d) A complete angle is equal to 360°.

Question 10.
Solution:
(b) A reflex angle is greater than 180° but less than 360°.

Question 11.
Solution:
Two right angles = (2 x 90)°
= 180° (b)

Question 12.
Solution:
\(\frac { 3 }{ 2 } \) of a right angle = \(\frac { 3 }{ 2 } \) x 90° = 135° as 1 right angle = 90° (b)

Question 13.
Solution:
36 spokes has 360°
Angle between two adjacent spokes
= \(\frac { { 360 }^{ O } }{ { 36 }^{ O } } \) = 10° (c)

Hope given RS Aggarwal Solutions Class 6 Chapter 13 Angles and Their Measurement Ex 13D are helpful to complete your math homework.

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RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C

January 5, 2022April 29, 2019 by Prasanna

RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 13 Angles and Their Measurement Ex 13C.

Other Exercises

Question 1.
Solution:
(i) Place the protractor in such a way that its centre is exactly at the vertex O of the given angle AOB and the base line lies along the arm OA. Read off the mark through which the arm OB passes, starting from 0° on the side A.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q1.1
We find that ∠AOB = 45°.
(ii) The given angle is ∠PQR. Place the protractor in such a way that its centre is exactly on the vertex Q of the given angle and the base line lies along the arm QR.Read off the mark through which the arm QP passes, starting from 0° on the side of R.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q1.2
We find that ∠PQR = 67°
(in) The given angle is ∠DEF. Place the protractor in such a way that its centre is exactly on the vertex E of the given angle and the base line lies along the arm ED. Read off the mark through which the arm EF passes, starting from 0° on the side of D.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q1.3
We find that ∠DEF = 130°
(iv) The given angle is ∠LMN. Place the protractor in such a way that its centre is exactly on the vertex M of the given angle and the base line lies along the arm ML. Read off the mark through which the arm MN passes, starting from 0° on the side of L.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q1.4
We find that ∠LMN = 50°
(v) The given angle is ∠RST. Place the protractor in such a way that its centre is exactly on the vertex S of the given angle and the base line lies along the arm SR. Read off the mark through which the arm ST passes, starting from 0° on the side of R.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q1.5
We find that the ∠RST = 130°.
(vi) The given angle is ∠GHI. Place the protractor in such a way that its centre is exactly on the vertex H of the given angle and the base line lies along the arm HI. Read off the mark through which the arm HG passes, starting from 0° on the side of I.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q1.6
We find that ∠GHI = 70°

Question 2.
Solution:
(i) Draw a ray OA. Place the protractor in such a way that its centre lies exactly at O and the base line lies along OA. Starting from 0° on the side of A, look for the 25° mark on the protractor. Mark a point B at this 25° mark. Remove the protractor and draw the ray OB. Then ∠AOB is the required angle.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q2.1
(ii) Draw a ray OA. Place the protractor in such a way that its centre lies exactly at O and the base line lies along OA. Starting from 0° on the side of A, look for the 72° mark on the protractor. Mark a point B at this 72° mark. Remove the protractor and draw the ray OB. Then,
∠AOB is the required angle of measure 72°.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q2.2
(iii) Draw a ray OA. Place the protractor in such a way that its centre lies exactly at O and the base line lies along OA. Starting from 0° on the side of A, look for the 90° mark on the protractor. Mark a point B at this 90° mark. Remove the protractor and draw the ray OB. Then ∠AOB is the required angle whose measure is 90°.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q2.3
(iv) Draw a ray OA. Place the protractor in such a way that its centre exactly lies at O and the base line lies along OA. Starting from 0° on the side of A, look for the 117° mark on the protractor. Mark a point B at this 117° mark. Remove the protractor and draw the ray OB. Then ∠AOB is the required angle whose measure is 117°.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q2.4
(v) Draw a ray OP. Place the protractor in such a way that its centre lies exactly at O and the base line lies along OP. Starting from 0° on the side of P, look for the 165° mark on the protractor. Mark a point Q at this 165° mark. Remove the protractor and draw the ray OQ. Then, ∠POQ is the required angle whose measure is 165°.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q2.5
(vi) Draw a ray OP. Place the protractor in such a way that its centre lies exactly at O and the base line lies along OP. Starting from 0° on the side of P, look for the 23° mark on the protractor. Mark a point Q at this 23° mark. Remove the protractor and draw the ray OQ. Then ∠POQ is the required angle whose measure is 23°.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q2.6
(vii) Draw a ray OA. Place the protractor in such a way that its centre lies exactly at O and the base line lies along OA. Starting from 0° on the side of A,Took for the 180° mark on the protractor. Mark a point B on this 180° mark. Remove the protractor and draw the ray OB. Then ∠AOB is the required angle whose measure is 180°.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q2.7
(viii) Draw a ray Rs. Place the protractor in such away that its centre lies exactly at R and the base line lies along RS. Starting from 0° on the side of S, look for the 48° mark on the protractor. Mark a point T at this 48° mark. Remove the protractor and draw the ray RT. Then, ∠SRT is the required angle whose measure is 48°.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q2.8

Question 3.
Solution:
On measuring the given angle ABC with the help of a protractor, it is 50°
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q3.1
Now, place the protractor on EF in such a way that its centre lies on E exactly and base with the line EF.
Now read off the mark through with the arm ED passes at 50°.
Join DE,
Then ∠DEF is equal to 50° i.e. equal to ∠ABC.

Question 4.
Solution:
Steps of construction :
(i) Draw a line segment AB = 6 cm.
(ii) Take a point C on AB such that AC = 4 cm.
RS Aggarwal Class 6 Solutions Chapter 13 Angles and Their Measurement Ex 13C Q4.1
(iii) Place protractor with its centre at C and base along CB.
(iv) Mark a point D against 90°.
(v) Remove the protractor and join DC. Then DC ⊥ AB. Ans.

Hope given RS Aggarwal Solutions Class 6 Chapter 13 Angles and Their Measurement Ex 13C are helpful to complete your math homework.

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